Example 30k We want to calculate the voltage Vac. To solve this problem the circuit can be redrawn as.

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Presentation transcript:

Example 30k We want to calculate the voltage Vac. To solve this problem the circuit can be redrawn as

I1 30k Let the current I1 is flowing through the circuit. The KVL equation will be 10kI1 + 20kI1 + 30KI1 = 6 60kI1= 6

I1 30k I1 Vo I1 = 6/60k =0.1mA

Now Vac will be equal to Vac = (10k + 20k)I1 = 30k(0.1mA) =3 Volts. I1

Example We want to calculate the voltage Vbd. First we will have to calculate the voltage across 40k resistor. Let the current I1 be flowing through the loop.

Applying KVL 10kI1 + 9 + 40kI1+ 10kI1 – 6=0 60kI1 = -3

I1 = - 3/60k = - 0.05 mA

So, voltage across 40k resistor V40k = (-0.05m)(40k) = - 2 volts

Now to calculate Vbd we take the path bdcb Applying KVL Vbd + 2 -9 =0

d I1 e 40k Vbd 2V + - Vbd = 7 Volts.

Example We want to calculate the current I0. The circuit can be redrawn as

Here I1 = 120 mA

Applying KVL to mesh 2 8kI2 + 4kI2 + 4k(I2 – I1 ) = 0 I2 = 480/16k =30 mA

I1 I2 4k So I0 will be I0 = I1 – I2 I0 = 120 – 30 = 90 mA

Example We want to calculate the current I0 and the voltage V0. The circuit can be redrawn as

V0 Applying KVL to mesh 1 2kI1 +6k(I1 – I2 )= 12 8kI1 – 6kI2 = 12

Applying KVL at mesh 2 8kI2 + 4kI2 + 6k (I2 – I1) = 0 18kI2 - 6kI1 =0

Solving equations of mesh 1 and 2 24kI1 - 18kI2 = 36

V0 I1 I2 I2 = 36/54k =0.67mA

V0 I1 I2 Now V0 will be equal to V0 = 4k I2 = 2.66 Volts

Example We want to calculate the current I0. To apply KVL the circuit can be redrawn as

Here I1 = - 2mA I3 = 4mA

KVL for mesh 2 4kI2 + 6k (I2 – I3) + 2k(I2 – I1) = 12 4mA KVL for mesh 2 4kI2 + 6k (I2 – I3) + 2k(I2 – I1) = 12 12kI2 – 24 + 4 =12

I0 I1 I2 I3 4mA I2 = 32/12k =8/3 mA =2.66 mA I0 = I2 = 2.66mA

Example We want to calculate the current I0.The circuit can be redrawn as

Here I1 = - 2mA I3 = 4mA

Apply KVL on the mesh 2 2kI2 + 1k(I2 – I1) = 12 3KI2 + 2 =12 I2 = 10/3 mA = 3.33mA

I0 I1 I3 I2 2k Now I0 = I1 – I2 = - 2 – 3.33 = - 5.33 mA