Theoretical Yield & Percent Yield

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Presentation transcript:

Theoretical Yield & Percent Yield

Theoretical Yield & Percent Yield Amount predicted by stoichiometry (maximum possible amt of product) Percent Yield Actual Yield X 100 = % Yield

EXAMPLE- Ethanol reacts with Acetic acid to produce Ethyl Acetate EXAMPLE- Ethanol reacts with Acetic acid to produce Ethyl Acetate. Stoichiometry predicts that 0.458 mol of the acetic acid reacting with excess ethanol will produce 0.458 mol of ethyl acetate. It is found, however, that only 0.399 mol of the acetate is obtained. What is the % yield? Rxn: E + A  EA Ans: 87.1 % Yield

Practice When 12.15 g of Mg ribbon is burned a white ash, solid magnesium oxide is formed. What is the theoretical yield for this reaction? 2 Mg + O2  2 MgO 12.15 g ? 12.15 g MgX (1 mol Mg/24.30 g Mg) X (2 mol MgO/2 mol Mg) X (40.30 g MgO/1 mol MgO) = 20.15 g MgO Theoretical Yield is 20.15 g MgO

Percent Yield When 12.15 g of Mg ribbon is burned a white ash, solid magnesium oxide is formed. Theoretical Yield is 20.15 g MgO What is the % Yield if 16.12 g of ash is produced? Ans: (16.12 g/20.15 g) x 100 = 80.00 % Meaning: you actually obtained 80.00% of what was theoretically expected.

Theoretical Yield When KI is added to a solution containing 0.500 g of lead II nitrate, solid lead II iodide (a yellow precipitate) is formed, PbI2. If 0.478 g of the precipitate is produced calculate the % yield.

% Yield When KI is added to a solution containing 0.500 g of lead II nitrate, solid lead II iodide (a yellow precipitate) is formed, PbI2. If 0.478 g of the precipitate is produced calculate the % yield. Ans: 98.7% yield