Vectors List 5-8 situations that would involve 1 or 2 different forces acting on an object that cause it to move in a certain direction.

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Presentation transcript:

Vectors List 5-8 situations that would involve 1 or 2 different forces acting on an object that cause it to move in a certain direction

Objectives Distinguish between basic trigonometric functions (SOH CAH TOA) Add vectors using graphical and analytical methods

SCALAR A SCALAR quantity is any quantity in physics that has MAGNITUDE ONLY Scalar Example Magnitude Speed 35 m/s Distance 25 meters Age 16 years Number value with units

VECTOR A VECTOR quantity is any quantity in physics that has BOTH MAGNITUDE and DIRECTION Vector Example Magnitude and Direction Velocity 35 m/s, North Acceleration 10 m/s2, South Force 20 N, East An arrow above the symbol illustrates a vector quantity. It indicates MAGNITUDE and DIRECTION

VECTOR APPLICATION ADDITION: When two (2) vectors point in the SAME direction, simply add them together. EXAMPLE: A man walks 46.5 m east, then another 20 m east. Calculate his displacement relative to where he started. + 46.5 m, E 20 m, E MAGNITUDE relates to the size of the arrow and DIRECTION relates to the way the arrow is drawn 66.5 m, E

VECTOR APPLICATION SUBTRACTION: When two (2) vectors point in the OPPOSITE direction, simply subtract them. EXAMPLE: A man walks 46.5 m east, then another 20 m west. Calculate his displacement relative to where he started. 46.5 m, E - 20 m, W 26.5 m, E

The resultant, or sum, of a number of vectors is that single vector that would have the same effect as all the original vectors taken together.

Vectors at right angles When two (2) vectors are PERPENDICULAR to each other, you must use the PYTHAGOREAN THEOREM FINISH Example: A man travels 120 km east then 160 km north. Calculate his resultant displacement. the hypotenuse is called the RESULTANT 160 km, N VERTICAL COMPONENT START 120 km, E HORIZONTAL COMPONENT

WHAT ABOUT DIRECTION? In the example, DISPLACEMENT asked for and since it is a VECTOR quantity, we need to report its direction. N W of N E of N N of E N of W N of E W E S of W S of E NOTE: When drawing a right triangle that conveys some type of motion, you MUST draw your components HEAD TO TOE. W of S E of S S

20 degrees "North of east" means "20 degrees north of the east axis 20 degrees "North of east" means "20 degrees north of the east axis. Specifically: you start with the east axis and rotate counter-clockwise for 20 degrees. 20 degrees "east of north" means you start with the north axis (or Y axis) and rotate clockwise 20 degrees.

NEED A VALUE – ANGLE! Just putting N of E is not good enough (how far north of east ?). We need to find a numeric value for the direction. To find the value of the angle we use a Trig function called TANGENT. 200 km 160 km, N θ N of E 120 km, E So the COMPLETE final answer is : 200 km, 53.1 degrees North of East

What are your missing components? Suppose a person walked 65 m, 25 degrees East of North. What were his horizontal and vertical components? The goal: ALWAYS MAKE A RIGHT TRIANGLE! To solve for components, we often use the trig functions since and cosine. H.C. = ? V.C = ? 25 65 m

Example 23 m, E - = 12 m, W - = 14 m, N 6 m, S 20 m, N 35 m, E R A bear, searching for food wanders 35 meters east then 20 meters north. Frustrated, he wanders another 12 meters west then 6 meters south. Calculate the bear's displacement. 23 m, E - = 12 m, W - = 14 m, N 6 m, S 20 m, N 35 m, E R 14 m, N θ 23 m, E The Final Answer: 26.93 m, 31.3 degrees NORTH of EAST

Example A boat moves with a velocity of 15 m/s, N in a river which flows with a velocity of 8.0 m/s, west. Calculate the boat's resultant velocity with respect to due north. 8.0 m/s, W 15 m/s, N Rv θ The Final Answer : 17 m/s, @ 28.1 degrees West of North

Example A plane moves with a velocity of 63.5 m/s at 32 degrees South of East. Calculate the plane's horizontal and vertical velocity components. H.C. =? 32 V.C. = ? 63.5 m/s

Example A storm system moves 5000 km due east, then shifts course at 40 degrees North of East for 1500 km. Calculate the storm's resultant displacement. 1500 km V.C. 40 5000 km, E H.C. 5000 km + 1149.1 km = 6149.1 km R 964.2 km θ The Final Answer: 6224.2 km @ 8.92 degrees, North of East 6149.1 km