MOTION & ITS APPLICATIONS  Newton’s Second Law of Motion (P )

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MOTION & ITS APPLICATIONS  Newton’s Second Law of Motion (P .40-41) SPH4C COLLEGE PHYSICS MOTION & ITS APPLICATIONS  Newton’s Second Law of Motion (P .40-41)

Newton’s Second Law of Motion When a constant unbalanced force acts on an object, it seems reasonable that the object will not have a constant velocity but will accelerate. But this raises a couple of questions. How does the acceleration of the object depend on the resultant force acting? Can this relationship be expressed in a single equation?

The Variables Involved in Newton’s Second Law Imagine pushing a large sled with a few small boxes on top across a nearly frictionless icy surface. In scenario (a) you push as hard as you can and the sled starts from rest and attains a high velocity in very little time. In scenario (b) you push with less force on the sled and the velocity increases more gradually. These two scenario imply that the acceleration increases as the net force increases. In other words, 𝒂 ∝ 𝑭 .

The Variables Involved in Newton’s Second Law In scenario (c) you remove some of the boxes, push with a force and the lighter sled easily speeds up from rest. In scenario (d) you put more boxes on the sled and push with the same force. The heavier sled does not speed up at the same rate. These two scenario imply that the acceleration decreases as the mass increases. In other words, 𝒂 ∝ 𝟏 𝒎 .

Newton’s Second Law Newton’s second law of motion is summarized as follows:

Newton’s Second Law

Newton’s Second Law

Newton’s Second Law PRACTICE For each of the following, determine the net force and then state whether the object is experiencing uniform or non-uniform motion. (a) 5.0 N[N], 3.0 N[S] (a) Fnet = 2.0 N[N]  non-uniform motion

Newton’s Second Law PRACTICE For each of the following, determine the net force and then state whether the object is experiencing uniform or non-uniform motion. (b) 4.0 N[N], 2.0 N[E], 1.0 N[E], 1.0 N[S], 3.0 N[S], 3.0 N[W] (b) Fnet = 0.0 N  uniform motion

Newton’s Second Law NOTE! When analyzing motion, the solution will typically require more than one step. For example, you might have information about the forces acting on an object which you would use to draw a FBD. You would then use the FBD to find the net force and subsequently the acceleration of the object. In the final step, you would use the acceleration FBD to calculate other properties of the object’s motion, such as velocity or displacement. Still, in other cases, you might need to analyze the motion of an object in order to find the acceleration which would then be used to calculate a force acting on the object.

Newton’s Second Law PRACTICE 2. A worker applies a force of 360 N[E] on a trunk of mass 50 kg. A friction force of 340 N acts in the opposite direction. (a) Draw a FBD of the situation. (b) What is the acceleration of the trunk? (b) 𝑎 = 0.40 m/s2[E]

Newton’s Second Law PRACTICE 3. A boy pushes horizontally on a 10 kg wagon and the wagon accelerates along at 2.5 m/s2. If frictional forces total 50 N, what force must he be exerting on it? 𝐹 = 75 N[fwd]

Newton’s Second Law PRACTICE 4. In an extreme test of its braking system under ideal road conditions, a sports car, initially travelling at 28 m/s [S], applies it brakes and comes toastopin3.5s. Themassofthecarwiththedriveris1.2x103 kg. Calculate (i) the car’s acceleration and (ii) the net force needed to cause that acceleration. 𝑎 = 8.0 m/s2[N] 𝐹 net = 9600 N[N]

Newton’s Second Law PRACTICE 5. Assume that for each pulse, a human heart accelerates 21 g of blood from 18 cm/s to 28 cm/s during a time interval of 0.10 s. Calculate the magnitude of (i) the acceleration of the blood and (ii) the force needed to cause that acceleration. 𝑎 = 1.0 m/s2 𝐹 net = 0.021 N

Check your Understanding TEXTBOOK P .42 Q.1-5 WEEBLY (FORCES) WS5 (2nd Law - Horizontal)