Speed of light The speed of light is 3.0 x 108 m/s in a vacuum

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Presentation transcript:

Speed of light The speed of light is 3.0 x 108 m/s in a vacuum 3.0 x 108 m/s = 300 000 000 m/s But what does that even mean?

Speed of Light A passenger jet travels at about 900 km/h (250 m/s) It would take a jet 45 hours to fly around the world at the equator (and that’s not including time to refuel)

Speed of Light If we could move at the speed of light, we could circle the earth 7.5 times in one second

Speed of light Okay, but I say the speed of light is 3.0 x 108 m/s in a vacuum Why did I say “in a vacuum”? ?

Imagine This... Think, Pair, Share

Refraction The bending or change in direction of light when it travels from one medium to another.

angle of incidence incident ray medium A medium B refracted angle of refraction

The Speed of Light It’s 3.0 x 108 m/s ... isn’t it?

Less friction (less dense) More friction (more dense)

Less friction (less dense) This wheel slows down, but the others continue to move at the same speed More friction (more dense)

More friction (more dense) Less friction (less dense)

More friction (more dense) This wheel speeds up, but the others continue to move at the same speed Less friction (less dense)

Both front wheels slows down. Less friction (less dense) More friction (more dense) Both front wheels slows down.

Rules of Refraction The incident ray, refracted ray, and the normal are all on the same plane. The incident ray and the refracted ray are on opposite sides of the line that separates the media. The light bends towards the normal when the speed of the light in the second medium is less than the speed of light in the first medium.

Medium A Medium B Which medium: Is less dense? Has a higher index of refraction? Is the light traveling slower?

1 2 More Dense Larger Index

3 More Dense Larger Index 4

3 Same Density Same Index 1

The Index of Refraction (n) The ratio of the speed of light in a vacuum (c) to the speed of light in a medium (v)

Example #1 How fast does light travel through water? (The index of refraction of water is 1.33) c = 3.00 x 108 m/s

Example #2 If the speed of light in a medium is 2.05 x 108 m/s, which solid medium is light traveling through?

Lateral Displacement Air Air Water Lateral Displacement

Think about it If you place two pieces of glass beside each other and shone a light through them, which way would the light bend? Towards the normal Away from the normal It would not bend It depends on the index of refraction

Think about it If you place two pieces of glass (with the same index of refraction) beside each other and shone a light through them, which way would the light bend? Towards the normal Away from the normal It would not bend

Partial Reflection and Refraction Refraction is often accompanied by reflection. Some light is reflected off of the surface and the rest is refracted. We often observe this in water, windows, and sunglasses.

Total Internal Reflection Critical Angle Air Water Total internal reflection

Total Internal Reflection Critical angle: The angle of incidence that results in an angle of refraction of 90º. Total Internal Reflection: occurs when the angle of incidence is equal or greater than the critical angle.

Total Internal Reflection Total internal reflections occurs when two conditions are met: Light is travelling more slowly in the first medium than in the second The angle of incidence is large enough that no refraction occurs

Critical Angle 48.8º 70º 25º

Fibre Optics

Converging Lens

Diverging Lens

Converging Lens O F Focus F’ Optical Centre focal length

Converging Lens incident ray emergent ray O F’ F focal length Focus

Simplifying the Path

Diverging Lens Optical Centre O F F’ Focus Focus

Converging Lens emergent ray incident ray O F F' focal length Focus

Aberration A distortion of the image

Spherical Aberration Irregularities in an image in a curved mirror or lens that result when rays to not go through the focus This is more noticeable as the lens gets thicker

Chromatic Aberration The dispersion of light through a lens Dispersion is the process of separating colours by refraction

Overcoming Aberration

Converging Lens O 2F F F 2F 1. A ray parallel to the principle axis will be refracted through the (right) focus (F). 2. A ray through the (left) focus (F) is refracted parallel to the principle axis. 3. A ray through the optical centre (O) continues straight through without being refracted

Simplifying the Path

O 2F F F 2F 1. A ray parallel to the principle axis refracts as if it had come from the (left) focus (F). 2. A ray aimed at the (right) focus (F) is refracted parallel to the principle axis. 3. A ray through the optical centre (O) continues straight through without being refracted

Converging Lens Diverging Lens 1. A ray parallel to the principle axis will be refracted through the (right) focus (F). 2. A ray through the (left) focus (F) is refracted parallel to the principle axis. 3. A ray through the optical centre (O) continues straight through without being refracted Diverging Lens 1. A ray parallel to the principle axis refracts as if it had come from the (left) focus (F). 2. A ray aimed at the (right) focus (F) is refracted parallel to the principle axis. 3. A ray through the optical centre (O) continues straight through without being refracted

Thin Lens Equation f: Focal length. Positive for converging lenses.   f: Focal length. Positive for converging lenses. di: Image distance. Positive for real images, negative for virtual images do: Object distance. Always positive.

Magnification Equation   m: Magnification. hi: Image height. Positive for upright images, negative for inverted images ho: Object height. Always positive. di: Image distance. Positive for real images, negative for virtual images do: Object distance. Always positive.

Practice Problem 1 A converging lens has a focal length of 12 cm. An object with a height of 4.0 cm is placed 18 cm in front of the lens. Calculate the image distance Calculate the image height State the 4 image characteristics

Practice Problem 2 A converging lens has a focal length of 16 cm. A person who is 2.0 cm tall is standing 8 cm in front of the mirror. Calculate the image distance Calculate the image height State the 4 image characteristics

Mirror Equation Practice pg 500 #1 - 4

Characteristics of Images formed in a Converging Lens Location of Object Size Attitude Location Type Beyond 2F' At 2F' Between 2F' and F' At F' Inside F' Between 2F and F Smaller Inverted Real Same size Inverted At 2F Real Larger Inverted Beyond 2F Real No clear image Same side as the object Larger Upright Virtual

Characteristics of Images formed in a Converging Lens Location of Object Size Attitude Location Type Beyond 2F' At 2F' Between 2F' and F' At F' Inside F' Between 2F and F Smaller Inverted Real Same size Inverted At 2F Real Larger Inverted Beyond 2F Real No clear image Same side as the object Larger Upright Virtual