Grouped data Objective Task Identify the modal class. [Grade C]

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Presentation transcript:

Grouped data Objective Task Identify the modal class. [Grade C] Sunday, 18 November 2018 Grouped data Objective Identify the modal class. [Grade C] Calculate an estimate of the mean from a grouped table. [Grade C] Task Key Words WS 1 Exam Qu1 By Cang Tu Exam Qu2

Key words Grouped data Estimated mean Modal class When data is grouped into classes. Click here If raw data is not given, the mean of that data is an estimated mean. Click here The class that has the highest frequency. Click here WS 1 Sunday, 18 November 2018 By Cang Tu 1st Slide

Worksheet 1 Find the modal class and the estimated mean for each table Grade C Qu1-2 Ans 1 Ans 2 Find the modal class and the estimated mean for each table 1) 2) Weight, 𝒘 (kg) Frequency, 𝒇 40<𝑤≤50 6 50<𝑤≤60 10 60<𝑤≤70 7 70<𝑤≤80 3 Mid-point, 𝒙 𝒇×𝒙 45 6 x 45 = 270 55 10 x 55 = 550 65 7 x 65 = 455 75 3 x 75 = 225 Modal class = 50<𝑤≤60 Estimated mean = 1500 26 = 57.7kg Total frequency = 26 Total 𝑓×𝑥 = 1500 Modal class = 20<𝑙≤25 Length, 𝒍 (cm) Frequency, 𝒇 20<𝑙≤25 14 25<𝑙≤30 5 30<𝑙≤35 3 Mid-point, 𝒙 𝒇×𝒙 22.5 14 x 22.5 = 315 27.5 5 x 27.5 = 137.5 32.5 3 x 32.5 = 97.5 Estimated mean = 550 22 = 25cm Exam Qu1 Total frequency = 22 Total 𝑓×𝑥 = 550 Sunday, 18 November 2018 By Cang Tu 1st Slide

Exam Qu 1 Caleb measures the heights of 30 plants Ans 1 Caleb measures the heights of 30 plants The table gives some information about the heights, h cm, of the plants. Work out an estimate for the mean height of a plant ………………..cm (4 marks, C) Height , h (cm) Frequency, f 0<ℎ≤10 2 10<ℎ≤20 8 20<ℎ≤30 9 30<ℎ≤40 7 40 < ℎ ≤ 50 4 Mid-point, 𝒙 𝒇×𝒙 5 2 x 5 = 10 15 8 x 15 = 120 25 9 x 25 = 225 35 7 x 35 = 245 45 4 x 45 = 180 Total frequency = 30 Total 𝑓×𝑥 = 780 = 780 30 = 26cm Estimated mean 26 Exam Qu2 Sunday, 18 November 2018 By Cang Tu 1st Slide

Exam Qu 2 Ans 2a Ans 2b 2) The table shows some information about the heights (h cm) of 100 students Find the class interval in which the median lies (1 mark, C) Work out an estimate for the mean height of the students (4 marks, C) Height , h (cm) Frequency 120<ℎ≤130 8 130<ℎ≤140 16 140<ℎ≤150 25 150<ℎ≤160 30 160 < ℎ ≤ 170 21 Mid-point, 𝒙 𝒇×𝒙 125 8 x 125 = 1000 135 16 x 135 = 2160 145 25 x 145 = 3625 155 30 x 155 = 4650 165 21 x 165 = 3465 Total frequency = 100 Total 𝑓×𝑥 = 14900 150 <ℎ ≤160 = 14900 100 = 149cm Estimated mean Sunday, 18 November 2018 By Cang Tu 1st Slide