The Energies of Stationary States ( Z2 n2 ) The energy of a stationary state is given by: En = -2.18  10-18 (Joules) “Z” is charge on nucleus. “n” is stationary state number. For Hydrogen, n = 4 and Z = 1 ( 12 42 ) E4 = -2.18  10-18 = -1.36 10-19 J For Hydrogen, n = 2 and Z = 1 ( 12 22 ) E2 = -2.18  10-18 = -5.45  10-19 J

The Energies of Stationary States E = -1.36  10-19 J Greater P.E. n=3 E = -5.45  10-19 J Lesser P.E. n=2 Energy Changes n=1 Ee- = Efinal - Einitial Ee- = (-5.45  10-19) - (-1.36  10-19) Ee- = - 4.08  10-19 J Energy change is negative since the atom LOST energy as light!

The Energies of Stationary States Energy Changes Ee- = Efinal - Einitial Ee- = (-5.45  10-19) - (-1.36  10-19) Ee- = - 4.08  10-19 J Energy change is negative since the atom LOST energy as light! Ee- = - 4.08  10-19 J = - Elight = h  = Elight/h = 4.08  10-19 / 6.626  10-34 = 6.16891014 Hz  = c /  = 3.00  108 / 6.16891014 = 486.3 nm (green line)