Molar Conversions Atoms to Moles, moles to atoms, mass to atoms, atoms to mass, mass to mass

How to Convert Anything! Identify the information given Given: Start point End point Connect information Conversion factor, mole ration, etc Setup conversion plan Start point and end point Fill in units New unit on the top old unit on the bottom Do the math! Fill in numbers

Atoms to mole, moles to atoms A few things to remember 6.022 x 10 23 particles = 1 mole of ANY compound Particles can be: ions, atoms, formula units, or molecules Conversion factors must link the two units New unit Old Unit

Lets convert ! End point: Moles Mg 2. Moles Mg atoms Mg Atoms to moles How many moles of magnesium are in 3.01 x 1022 atoms of magnesium? 1. Given: 3.01 x 1022 atoms Mg End point: Moles Mg 2. Moles Mg atoms Mg 3. 3.01 x 1022 atoms Mg x moles Mg atoms Mg = ____Moles Mg 4. 3.01 x 1022 atoms Mg x 1 mole Mg 6.022 x 10 23atoms Mg = .05 Moles Mg

Keep converting! Moles to molecules How many molecules are there in 4.00 moles of glucose, C6H12O6? 1.Given: 4.00 moles C6H12O6 End point: Molecules of C6H12O6 2. Molecules of C6H12O6 moles C6H12O6 3. 4.00 moles C6H12O6 x Molecules of C6H12O6 moles C6H12O6 = ____Molecules of C6H12O6 4. 4.00 moles C6H12O6 x 6.022 x 1023Molecules of C6H12O6 1 moles C6H12O6 = 2.4 x 1024 Molecules of C6H12O6

Moles to mass/ Mass to moles SAME PROCESS AS PARTICLES TO MOLES/MOLE TO PARTICLES Just different units! A few things to remember 1 moles = molar mass Elements: average atomic mass (periodic table) Compounds: Must calculate

Lets Convert! 1. What is the mass of 5 moles of Fe2O3 grams Fe2O3 moles of Fe2O3 5 moles of Fe2O3x grams Fe2O3 moles of Fe2O3 = ____ grams Fe2O3 5 moles of Fe2O3x 159.705 grams Fe2O3 1 moles of Fe2O3 = 798.525 grams Fe2O3 2. Find the number of moles of argon in 452 g of argon. Moles Ar grams of Ar 452 grams x Moles Ar grams of Ar = ____ Moles Ar 452 grams x 1 Moles Ar 39.948 grams of Ar = 11.318 Moles Ar Side Calculation Fe2O3 Fe: (2)55.854 = 111.69 O: (3) 15.999 = 47.997 159.705 g/mol

Moles to volume/Volume to moles SAME PROCESS AS PARTICLES TO MOLES/MOLE TO PARTICLES Just different units! A few things to remember 1 moles = 22.4 L @STP S: standard T: temperature ( 0 oC) P: Pressure (1 atm = 101.325 kPa = 760 mm Hg)

Conversion time What is the volume of 0.05 mol of neon gas at STP? How many moles of argon atoms are present in 11.2 L of argon gas at STP?   Moles of Ar Liters of Ar 11.2 L of Ar x Moles of Ar Liters of Ar = ____ Moles of Ar 11.2 L of Ar x 1 Moles of Ar 22.4 Liters of Ar = 0.5 Moles of Ar What is the volume of 0.05 mol of neon gas at STP?   Liters of Ne Moles of Ne 0.05 moles Ne x Liters of Ne Moles of Ne = ____ Liters Ne 0.05 moles Ne x 22.4 Liters of Ne 1 Moles of Ne = 1.12 Liters Ne

Mass to Particles : of the same Compound A few things to remember 6.022 x 10 23 particles = 1 mole of ANY compound Particles can be: ions, atoms, formula unit, or molecules 1 moles = molar mass Elements: average atomic mass (periodic table) Compounds: Must calculate Cannot complete in one step! Grams and particles cannot connect in one step. Must go to Moles 1st

Time to Convert Side Calculation N: (2) 14.007= 28.014 g/mol Find the mass, in grams, of 1.00 x 1023 molecules of N2 1.Start point: 1.00 x 10 23 molecules N2 End point: Grams of N2 Moles of N2 molecules N2 and Grams of N2 molecules N2 3. 1.00 x 10 23 molecules N2 x Moles of N2 molecules N2 = ____ Moles of N2 1.00 x 10 23 molecules N2 x 1 Moles of N2 6.022x 1023molecules N2 = .166 Moles of N2 _____Moles of N2 x Grams of N2 Moles of N2 = ____ Grams of N2 Side Calculation N: (2) 14.007= 28.014 g/mol 4. 0.166 Moles of N2 x 28.014 Grams of N2 1 Moles of N2 = 4.652 Grams of N2

Mass of one compound to mass of another Five Steps Label what is given Start point/ endpoint Connect the information Mole ratio (from balanced equation) Setup first conversion Setup second conversion Setup third conversion and solve

Steps 1 and 2 How many grams of potassium chloride, KCl, are produced if 25.0g of potassium chlorate, KClO3, decompose? 2KClO3 → 2KCl + 3O2 25.0 g ? g 2 moles KClO3 : 2 mole KCl

Step 3 and 4 Moles of KClO3 Grams of KClO3 25.0 g of KClO3 x Moles of KClO3 Grams of KClO3 = ____Moles of KClO3 25.0 g of KClO3 x 1 Moles of KClO3 122.549 g of KClO3 = .204 Moles of KClO3 Moles of KCl Moles of KClO3 _____Moles of KClO3x Moles of KCl Moles of KClO3 = ____ Moles of KCl .204 Moles of KClO3x 2 Moles of KCl 2 Moles of KClO3 = .204 Moles of KCl Side Calculation K: 39.089 g/mol Cl: 35.454 g/mol O: (3) 15.999 = 47.997 g/mol 122.549 g/mol

Step 5 Side Calculation K: 39.089 g/mol Cl: 35.454 g/mol 74.543 g/mol grams of KCl Moles of KCl _____Moles of KCl x grams of KCl Moles of KCl = ____grams of KCl .204 Moles of KCl x 74.543 grams of KCl 1 Moles of KCl = 15.207 grams of KCl