CIRCLE.

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Presentation transcript:

CIRCLE

RELATION BETWEEN THE CENTRAL ANGLE, SECTOR AREA, AND THE LENGHT OF ARCS BETWEEN TWO SECTORS Look at the picture

RELATION BETWEEN THE CENTRAL ANGLE, THE LENGHT OF ARCS, and SECTOR AREA   Look at the picture central  AOB = The lenght of arc AB The area of sector OAB central  COD arc CD The area of sector OCD

Circumference of circle If central angle is compared to a full angle of circle that is ( 3600), then : O B A  central  AOB = The lenght of arc AB The area of sector OAB 3600 Circumference of circle Area of circle

If the central angle that be compared to the full angle of circle ( 3600), then :  central  AOB = The lenght of arc AB the area of sector OAB 3600 2r r2

Example 1 : O D C A B 500 800 Look at the picture beside, the lenght of arc AB = 40 cm, AOB = 500, and AOB = 800. Find the lenght of arc CD.

Solution : Given : AB = 40 cm, AOB = 500, AOB = 800 D C A B 500 800 Asking : Find the lenght of arc CD Answer: central  AOB = The lenght of arc AB central  COD The lenght of arc CD 500 = 40 cm 800 X cm X = ( 40 x 80 ) : 50 = 64. So, we get the lenght of arc CD = 64 cm

Example 2 : Look at the picture! The lenght of radii = 20 cm, AOB = 540. Determine the area of sector OAB O A B 540

Solution : Given : AOB = 540, and radii = 20 cm 540 = x 3600 r2 3 = central  AOB = The area of sector OAB 3600 The area of circle 540 = x 3600 r2 3 = x 20 3,14 x 202 X = ( 3 x 1256 ) : 20 = 188,4 cm2. So, we get the area of sector OAB = 188,4 cm2.

EXERCISE

Question - 1 Look at the picture, the lenght of arc PQ = 50 cm, the lenght of arc QR = 75 cm and POQ = 450. Determine QOR. O P R 450 Q

Solution : 45 = 50 x 75 45 = 2 x 3 X = ( 3 x 45) : 2 = 135 : 2 = 67,50 Given : The lenght of arc PQ = 50 cm The lenght of arc QR = 75 cm POQ = 450 central  POQ = The lenght of arc PQ central  QOR The lenght of arc QR 45 = 50 x 75 45 = 2 x 3 X = ( 3 x 45) : 2 = 135 : 2 = 67,50 So, we get  QOR = 67,50.

Question - 2 Look at the picture, COD = 600, the lenght of OA = 12 cm and AC = 12 cm. Calculate the area of the shaded region. O C D B A 600 12 cm

Area of sector OAB = 60/360 x area of circle = 1/6 x 3,14 x 12 x 12 Solution : Given : Radii (1) = 12 cm Radii (2) = 24 cm. AOB = 600 Asking : the area of the shaded region. Answer: Area of sector OAB = 60/360 x area of circle = 1/6 x 3,14 x 12 x 12 = 3,14 x 24 = 75,36 cm2

Area of sector OCD = 60/360 x area of circle = 1/6 x 3,14 x 24 x 24 = 3,14 x 96 = 301,44 cm2 The area of the shaded region: = area of sector OCD - area of sector OAB = 301,44 cm2 - 75,36 cm2 = 226,08 cm2.

Question - 3 42 cm Calculate the area of the shaded region as shown in the figure above !

Solution : The area of circle that is shaded : L = ½  r2 42 cm The area of circle that is shaded : L = ½  r2 = ½ x 22/7 x 21 x 21 = ½ x 22 x 63 = 11 x 63 = 693 cm2 The area of small circle that is shaded = The area of small circle that isn’t shaded.

QUIZ

Quiz - 1 Look at the picture, the area of sector OAB =60 cm2, 1200 400 B Look at the picture, the area of sector OAB =60 cm2, AOB = 400 and BOC = 120o Find the area of sector OBC.

Calculate the area of the shaded region as shown in the figure above ! Quiz - 2 14 cm Calculate the area of the shaded region as shown in the figure above !

Solution Quiz 1 : 400 = 60 1200 x 1 = 60 3 x X = 3 x 60 = 180 cm2. Given : AOB = 400 and BOC = 1200 The area of sector OAB = 60 cm2 Asking: The area of sector OBC. Answer: central  AOB = The area of sector OAB central  BOC The area of sector OBC 400 = 60 1200 x 1 = 60 3 x X = 3 x 60 = 180 cm2. So we get the area of sector OBC = 180 cm2.

Solution Quiz 2 : The area of circle that is shaded : Lb =  r2 = 22/7 x 7 x 7 = 154 cm2 Lk =  r2 = 22/7 x 3,5 x 3,5 = 38,5 cm2 14 cm The area of the shaded region = 154 - 38,5 = 115,5 cm2

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