Exponential and Logarithms

Slides:



Advertisements
Similar presentations
The equation of a line - Equation of a line - Slope - Y intercept
Advertisements

EXPONENTIAL GROWTH Exponential functions can be applied to real – world problems. One instance where they are used is population growth. The function for.
4.7 Write and Apply Exponential & Power Functions
Warm-Up. One way to solve exponential equations is to use the property that if 2 powers w/ the same base are equal, then their exponents are equal. For.
Exponentials & Logarithms A2 REVIEW QUESTIONS. Question 1.
EXAMPLE 1 Solve quadratic equations Solve the equation. a. 2x 2 = 8 SOLUTION a. 2x 2 = 8 Write original equation. x 2 = 4 Divide each side by 2. x = ±
Evaluating logarithms
4.3 Logarithm Functions Recall: a ≠ 1 for the exponential function f(x) = a x, it is one-to-one with domain (-∞, ∞) and range (0, ∞). when a > 1, it is.
Exponential and Logarithmic Equations
7-5 Logarithmic & Exponential Equations
Take a logarithm of each side
Table of Contents Solving Exponential Equations An exponential equation is an equation with a variable as part of an exponent. The following examples will.
Introduction This chapter gives you several methods which can be used to solve complicated equations to given levels of accuracy These are similar to.
EQ: How do you use the properties of exponents and logarithms to solve equations?
11.3 – Exponential and Logarithmic Equations. CHANGE OF BASE FORMULA Ex: Rewrite log 5 15 using the change of base formula.
8.5 – Exponential and Logarithmic Equations. CHANGE OF BASE FORMULA where M, b, and c are positive numbers and b, c do not equal one. Ex: Rewrite log.
 If m & n are positive AND m = n, then  Can solve exponential equation by taking logarithm of each side of equation  Only works with base 10.
Laws of Logarithms 5.6. Laws of Logarithms O If M and N are positive real numbers and b is a positive number such that b  1, then O 1. log b MN = log.
Adding & Subtracting Whole Number and Fractions
Solve a logarithmic equation
EXAMPLE 4 Solve a logarithmic equation Solve log (4x – 7) = log (x + 5). 5 5 log (4x – 7) = log (x + 5) x – 7 = x x – 7 = 5 3x = 12 x = 4 Write.
Copyright © 2009 Pearson Education, Inc. CHAPTER 5: Exponential and Logarithmic Functions 5.1 Inverse Functions 5.2 Exponential Functions and Graphs 5.3.
Calculus 3.4 Manipulate real and complex numbers and solve equations AS
Introduction We are going to look at exponential functions We will learn about a new ‘special’ number in Mathematics We will see how this number can be.
To add fractions, you need a common denominator. Remember!
Applications of Common Logarithms Objective: Define and use common logs to solve exponential and logarithmic equations; use the change of base formula.
Common Logarithms - Definition Example – Solve Exponential Equations using Logs.
MAT 150 Module 9 – Exponential and Logarithmic Functions
GRAPHING EXPONENTIAL FUNCTIONS f(x) = 2 x 2 > 1 exponential growth 2 24–2 4 6 –4 y x Notice the asymptote: y = 0 Domain: All real, Range: y > 0.
EXAMPLE 2 Take a logarithm of each side Solve 4 = 11. x 4 = 11 x log 4 = log 11 x 4 4 log 4 x = 11 x = log 11 log 4 x 1.73 SOLUTION Write original equation.
Property of Logarithms If x > 0, y > 0, a > 0, and a ≠ 1, then x = y if and only if log a x = log a y.
CHAPTER 5 REVIEW Exponential and Logarithmic Functions.
Topic 10 : Exponential and Logarithmic Functions Solving Exponential and Logarithmic Equations.
LOGARITHMIC AND EXPONENTIAL EQUATIONS LOGARITHMIC AND EXPONENTIAL EQUATIONS SECTION 4.6.
3.4 Solving Exponential and Logarithmic Equations.
6.5 Applications of Common Logarithms Objectives: Define and use the common logarithmic function to solve exponential and logarithmic equations. Evaluate.
For b > 0 and b  1, if b x = b y, then x = y.
8.5 – Exponential and Logarithmic Equations
Splash Screen.
Ch. 8.5 Exponential and Logarithmic Equations
8-5 Exponential and Logarithmic Equations
8.5 – Exponential and Logarithmic Equations
3.4 Quick Review Express In 56 in terms of ln 2 and ln 7.
C3 Chapter 3: Exponential and Log Functions
Examples Solving Exponential Equations
Change of Base.
The Exponential and Log Functions
EXPONENTIAL GROWTH Exponential functions can be applied to real – world problems. One instance where they are used is population growth. The function for.
Integration By parts.
Geometric Series.
Trig addition formulae
Quadratics Completed square.
Logarithmic Functions and Their Graphs
Domain and range.
Domain and range.
Second Derivative 6A.
Natural Logarithm function
Challenging problems Area between curves.
Integration 2a.
Simultaneous Equations substitution.
Quadratics graphs.
Objective Solve quadratic equations by using square roots.
Challenging problems Area between curves.
Trig Equations.
Exponential and Logarithmic Functions
Trig Equations.
Functions Inverses.
Functions Inverses.
For b > 0 and b ≠ 1, if b x = b y, then x = y.
Compound Interest If a principal P is invested at an interest rate r for a period of t years, then the amount A of the investment is given by A = P(1 +
Presentation transcript:

Exponential and Logarithms Real world models

Exponential and Logarithm functions KUS objectives BAT Solve real life problems involving growth functions of the form y = Aebx+c

Real life problems: growth functions Think Pair Share WB15 The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 Calculate the value of the car when it is new Calculate the value after 5 years c) What is the implied value of the car in the long run (ie – what value does it tend towards?) d) Sketch the Graph of P against t P = 16000e - t 10 a) Calculate the value of the car when it is new  The new price implies t, the time, is 0…  Substitute t = 0 into the formula… P = 16000e - 0 10 P = 16000e P = £16000

The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 WB15 solution The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 b) Calculate the value after 5 years…  5 years implies t = 5  Substitute t = 5 into the formula… P = 16000e - t 10 P = 16000e - 5 10 -0.5 P = 16000e P = £9704.49 3A

WB15 solution The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 c) What is the implied value of the car in the long run (ie – what value does it tend towards?)  Imagine t tends towards infinity (gets really big) P = 16000e - t 10 P = 16000 x 0 P = £0 1 (10√e)t e - t 10 Bigger t = Bigger denominator = Smaller Fraction value… 3A

The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 WB15 solution P The Price of a used car is given by the formula: 𝑃=16000 𝑒 − 𝑡 10 d) Sketch the Graph of P against t  Value starts at £16000  Tends towards 0, but doesn’t get there… £16000 P = 16000e - t 10 t  t is independent so goes on the x axis  P is dependant on t so goes on the y axis 3A

Calculate the number of elephants in the herd in 2003 Think Pair Share WB16 The number of elephants in a herd can be represented by the equation: Where n is the number of elephants and t is the time in years after 2003. Calculate the number of elephants in the herd in 2003 Calculate the number of elephants in the herd in 2007 Calculate the year when the population will first exceed 100 elephants What is the implied maximum number in the herd? Calculate the number of elephants in the herd in 2003  Implies t = 0 t = 0 e0 = 1

WB16 solution b) Calculate the number of elephants in the herd in 2007  Implies t = 4 t = 4 Round to the nearest whole number c) Calculate the year when the population will first exceed 100 elephants  Implies N = 100 Subtract 150 Divide by -80 Take natural logs 2003 + 19 = 2022 Multiply by 40

WB16 solution d) What is the implied maximum number in the herd?  Implies t  ∞ Rearrange As t increases Denomintor becomes bigger Fraction becomes smaller, towards 0

WB17 In 1847, a group of pioneering UK Farmers headed off to a beautiful Caribbean island to make a new life. After t years, the population P of the farmers was given by 𝑃=236 𝑒 0.01𝑡   a) State the initial population of the farmers. b) Sketch the graph of P against t. c) State the population of farmers after 25 years. d) Find out after how many years it takes for the population to exceed 5000. a) When 𝑡=0, 𝑃=236 𝑒 0 =236 c) When 𝑡=25, 𝑃=236 𝑒 0.25 =… d) When 𝑃=5000, 236 𝑒 0.01𝑡 =5000 ln 236 𝑒 0.01𝑡 = ln 5000 ln 236 + ln 𝑒 0.01𝑡 = ln 5000 0.01𝑡= ln 5000 − ln 236 𝑡=100 ln 5000 − ln 236 = …

One thing to improve is – KUS objectives BAT Solve real life problems involving growth functions of the form y = Aebx+c self-assess One thing learned is – One thing to improve is –

END