Unit 7 Day 4 the Quadratic Formula.

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Presentation transcript:

Unit 7 Day 4 the Quadratic Formula

We can use the quadratic formula to solve quadratic equations in the form: x =

Example 1: 2x2 + 6x + 1 = 0

Examples 2. x2 – 4x + 3 = 0 3. 3x2 + 2x – 1 = 0 4. x2 = 3x – 1 5. 8x2 – 2x = 3

The discriminant determines the type and number of solutions.

If the discriminant is POSITIVE, there are 2 REAL solutions. If the discriminant is ZERO, there is 1 REAL solution If the discriminant is NEGATIVE, there are 2 IMAGINARY solutions.

Determine the type of solutions by using the discriminant: x2 – 22x = - 121 x2 – x – 1 = 1 x2 = - 4 7x2 – 4x = 0 9x2 + 12x = -4