Statically Determine of Beams and Frames

Slides:



Advertisements
Similar presentations
BENDING MOMENTS AND SHEARING FORCES IN BEAMS
Advertisements

Consider a section x-x at a distance 6m from left hand support A
Analysis of Beams in Bending ( )
Shear Force and Bending Moment
Beams WORKSHEET 8 to answer just click on the button or image related to the answer.
Analysis and Design of Beams for Bending
CHAPTER 6 BENDING.
CTC / MTC 222 Strength of Materials
ENGR 220 Section 6.1~6.2 BENDING.
Structure Analysis I. Lecture 8 Internal Loading Developed in Structural Members Shear & Moment diagram Ch.4 in text book.
Professor Joe Greene CSU, CHICO
ENGR 225 Section
ECIV 320 Structural Analysis I Internal Loadings in Structural Members Sections 4.1 – 4.5 Study all examples.
BFC (Mechanics of Materials) Chapter 2: Shear Force and Bending Moment
CHAPTER #3 SHEAR FORCE & BENDING MOMENT
Beams Shear & Moment Diagrams E. Evans 2/9/06. Beams Members that are slender and support loads applied perpendicular to their longitudinal axis. Span,
Analysis and Design of Beams for Bending
8. SHEAR FORCE AND BENDING MOMENT
Engineering Mechanics: Statics
NAZARIN B. NORDIN What you will learn:
BENDING MOMENTS AND SHEARING FORCES IN BEAMS
Bending Shear and Moment Diagram, Graphical method to construct shear
Shear Forces and Bending Moments in Beams
Eng Ship Structures 1 Hull Girder Response Analysis
Moment Area Theorems: Theorem 1:
7.2 Shear and Moment Equations and Diagrams
Beams, Shear Force & Bending Moment Diagrams
Copyright © 2010 Pearson Education South Asia Pte Ltd
Eng. Tamer Eshtawi First Semester
Engineering Mechanics: Statics
UNIT - II Shear Force Diagrams and Bending Moment Diagrams Lecture Number -1 Prof. M. J. Naidu Mechanical Engineering Department Smt. Kashibai Navale College.
NOR AZAH BINTI AZIZ KOLEJ MATRIKULASI TEKNIKAL KEDAH
MECHANICS OF MATERIALS Third Edition CHAPTER © 2002 The McGraw-Hill Companies, Inc. All rights reserved. Analysis and Design of Beams for Bending.
Structure Analysis I. Lecture 7 Internal Loading Developed in Structural Members Ch.4 in text book.
Beams - structural members supporting loads at various points along the member. Transverse loadings of beams are classified as concentrated loads or distributed.
Shear Force Diagram (SFD): The diagram which shows the variation of shear force along the length of the beam is called Shear Force Diagram (SFD). The diagram.
Axial Force Definition: Force which is parallel to the longitudinal axis of the member.
MECHANICS OF MATERIALS Fourth Edition Ferdinand P. Beer E. Russell Johnston, Jr. John T. DeWolf Lecture Notes: J. Walt Oler Texas Tech University CHAPTER.
Analysis and Design of Beams for Bending
Shear force and bending moments in Beams
Eng Ship Structures 1 Hull Girder Response Analysis
Structure Analysis I Eng. Tamer Eshtawi.
Analysis and Design of Beams for Bending
SFD &BMD (POINT LOAD & UDL) By: Mechanical Mania.
Analysis and Design of Beams for Bending
Shear Force and Bending Moment Diagrams
Shear Force and Bending Moment
INTERNAL FORCES AND FORCES IN BEAMS
Shear Force and Bending Moment Diagrams [SFD & BMD]
Shear Force and Bending Moment
STATICS (ENGINEERING MECHANICS-I)
Structure I Course Code: ARCH 208 Dr. Aeid A. Abdulrazeg
Chapter 7 FORCES IN BEAMS AND CABLES
Structure Analysis I Eng. Tamer Eshtawi.
STATICS (ENGINEERING MECHANICS-I)
Analysis and Design of Beams for Bending
Chapter 5 Torsion.
Analysis and Design of Beams for Bending
CHAPTER 8 SHEAR FORCE & BENDING MOMENT
Internal Forces.
Examples.
Shear Force and Bending Moment
Structure I Course Code: ARCH 208 Dr. Aeid A. Abdulrazeg
Structure I Course Code: ARCH 208
Statics Course Code: CIVL211 Dr. Aeid A. Abdulrazeg
Structure I Course Code: ARCH 208 Dr. Aeid A. Abdulrazeg
Engineering Mechanics: Statics
CE Statics Chapter 7 – Lecture 3.
Various Types of Beam Loading and Support
Presentation transcript:

Statically Determine of Beams and Frames

Axial Force The axial force at any transverse cross section of a straight beam is the algebraic sum of the component acting parallel to the axis of the member of all the loads and reactions applied to the portion of the member on either side of that cross section. For curved members the summation is done of the of the force components parallel to the tangent to the curve at the selected cross section.

Shearing Force: The shearing force at any transverse cross section of a straight member is the algebraic sum of the components acting transverse to the axis of the member of all the loads and reactions applied to the portion of the member on either side of that cross section. For curved members the summation is done of the of the force components transverse to the tangent to the curve at the selected cross section.

Bending Moment: The bending moment at any transverse cross section is the algabric sum of the moment taken about on axis normal to the plane of loading and passing through the cross section of all the loads and reactions applied to the portion of member on either side of the cross section.

Sign Conventions

Internal Forces in a System: General Procedure The general method of obtaining internal forces at certain cross-section of a system under a given loading (and support) condition is by applying the concepts of equilibrium. To illustrate, let us consider the beam-column AB in figure below.

Solution: Consider F. B. D. of whole structure as shown below

If a system is in static equilibrium condition, then every segment of it is also in equilibrium. Let us consider the equilibrium of part AC , and draw its free body diagram.

Figure below shows the free body diagram of CB .

Example:- Find the axial force, shearing force and bending moment at the section (1-1) located at 3 m from the left side of simply supported beam shown below.

Solution:- Draw F. B. D. of the beam

Axial force = - 30 kN (compression) Shear force = 40 – 20 = 20 kN Bending moment= 40*3 – 20*1 =100 kN.m

Relationships Between Loads, Shearing Force, and Bending Moment

Figure (b) 𝑭𝒚 =𝟎 →𝑽− 𝑽+𝒅𝑽 −𝒘.𝒅𝒙=𝟎 𝒅𝑽=−𝒘.𝒅𝒙 (𝟏) 𝒐𝒓 𝒅𝑽 𝒅𝒙 =−𝒘 (𝟐) Eq. (1): - States that the change in the value of shearing force between two points along the member is equal to the area of the load between these points. 𝑴 =𝟎 (𝒂𝒃𝒐𝒖𝒕 𝒕𝒉𝒆 𝒍𝒆𝒇𝒕 𝒇𝒂𝒄𝒆)

  𝑽+𝒅𝑽 𝒅𝒙+𝒘.𝒅𝒙. 𝒅𝒘 𝟐 − 𝑴+𝒅𝑴 +𝑴=𝟎 Neglecting higher order terms 𝒅𝑴=𝑽.𝒅𝒙 (𝟑) 𝒐𝒓 𝒅𝑴 𝒅𝒙 =𝑽 (𝟒) Eq.(3) :- The change in bending moment between two points along a member is equal to the area of the shearing force between these points. Eq.(4):- States that the slope of the bending moment diagram at any point is equal to the shearing at that point.

For the case of a concentrated load Fig.(c): - Vertical equilibrium 𝒅𝑽=−𝑷𝒐   For the case of a concentrated moment Fig.(d): - 𝒅𝑴=𝑴𝒐

Example: Draw S.F.D , and B.M.D for the beam shown in figure below.

Example: Draw A.F.D , S.F.D , and B.M.D for the frame shown in Fig.

Example: Draw A.F.D , S.F.D , and B.M.D for the frame shown in Fig.