Vector Mathematics.

Slides:



Advertisements
Similar presentations
Into to A.C. CKT Right Triangles and Phasor. Information n Mechanical Degree u Unit of measurement of rotational movement 360 degree n Angle u Whenever.
Advertisements

Trigonometry Ratios.
Special Triangles: 45 o -45 o -90 o ° x x Example: 45° 7 7 x x.
Trigonometry (RIGHT TRIANGLES).
Jeopardy Trig fractions Solving For Angles Solving for Sides Other Trig Stuff $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 Final Jeopardy.
Method #2: Resolution into Components. Solving Vector Problems using the Component Method  Each vector is replaced by two perpendicular vectors called.
Vector Mathematics Physics 1.
Right Triangle Trigonometry
1 Mathematical Fundamentals Need working knowledge of algebra and basic trigonometry if you don’t have this then you must see me immediately!
Vector components and motion. There are many different variables that are important in physics. These variables are either vectors or scalars. What makes.
The process of vector addition is like following a treasure map. ARRRR, Ye best learn your vectors!
Angles and the Unit Circle. An angle is in standard position when: 1) The vertex is at the origin. 2) One leg is on the positive x – axis. (This is the.
The Six Trig Functions Objective: To define and use the six trig functions.
Section 2 – WARM UP Use your graphing calculator to find the answers to the following trig. values or angle measurements. 1. sin θ = sec θ =
CP Vector Components Scalars and Vectors A quantity is something that you measure. Scalar quantities have only size, or amounts. Ex: mass, temperature,
Mathematical Vector Addition. Mathematical Addition of Vectors The process of adding vectors can be accurately done using basic trigonometry. If you.
Basics of Trigonometry Click triangle to continue.
Resolution and Composition of Vectors. Working with Vectors Mathematically Given a single vector, you may need to break it down into its x and y components.
Do Now: A golf ball is launched at 20 m/s at an angle of 38˚ to the horizontal. 1.What is the vertical component of the velocity? 2.What is the horizontal.
Right Angle Trigonometry Pythagorean Theorem & Basic Trig Functions Reciprocal Identities & Special Values Practice Problems.
Chapter 13 Right Angle Trigonometry
Component Vectors Vectors have two parts (components) –X component – along the x axis –Y component – along the y axis.
Vector Basics Characteristics, Properties & Mathematical Functions.
Convert Angles in Degrees to Degree and Minutes and vice versa.
VECTORS Wallin.
Vectors and Scalars Physics 1 - L.
Characteristics, Properties & Mathematical Functions
Right Triangle Trigonometry
The Inverse Trigonometric Functions
Basic Trigonometry We will be covering Trigonometry only as it pertains to the right triangle: Basic Trig functions:  Hypotenuse (H) Opposite (O) Adjacent.
Bearings and Navigation
Trigonometry Computer Integrated Manufacturing
Vector Resolution Level 1 Physics.
Pythagoras’ theorem Take a right-angled triangle with sides of 5cm, 4cm and 3cm. Draw squares off each side of the triangle.
Magnitude The magnitude of a vector is represented by its length.
8-4 Trigonometry Ms. Andrejko.
Vectors Vector: a quantity that has both magnitude (size) and direction Examples: displacement, velocity, acceleration Scalar: a quantity that has no.
Force Vectors Principles of Engineering
7.7– Solve Right Triangles
Periods 2 and 3 Take notes on the following in your Physics Journals
10 m 16 m Resultant vector 26 m 10 m 16 m Resultant vector 6 m 30 N
A Mathematical Approach
Right Triangle Trigonometry
7.4 - The Primary Trigonometric Ratios
7.7 Solve Right Triangles Obj: Students will be able to use trig ratios and their inverses to solve right triangles.
A 5 4 C 3 B 3 5 Sin A =.
Warm Up #8.
Force Vectors Principles of Engineering
10 m 16 m Resultant vector 26 m 10 m 16 m Resultant vector 6 m 30 N
ADDING VECTORS.
Vector Resolution.
Unit 3: Right Triangle Trigonometry
Find The Net Force on These
4.4 Trig Functions of any Angle
Warm-up.
SIX TRIGNOMETRIC RATIOS
Finding the Magnitude and Direction of the Resultant for two vectors that form right angles to each other.
Math Review.
Force Vectors Principles of Engineering
Vectors A vector is a quantity which has a value (magnitude) and a direction. Examples of vectors include: Displacement Velocity Acceleration Force Weight.
Vectors.
By Nishant Kumar and Dilan Patel
x x HW 13: Inverse Trig Functions HW 13: Inverse Trig Functions
All about right triangles
Vectors A vector is a quantity which has a value (magnitude) and a direction. Examples of vectors include: Displacement Velocity Acceleration Force Weight.
An Introduction to Vector Addition
Trigonometry – Angles & Lengths – Demonstration
10-6 Trigonometric Ratios
Trigonometry – Lengths – Demonstration
5.2 Apply the Tangent Ratio
Presentation transcript:

Vector Mathematics

Basic Addition and Subtraction This is far from rocket science, but without it we could never launch rockets! + = 5 m 3 m 8 m - = 5 m 3 m 2 m * a negative sign means to flip the vector! + = 5 m 3 m 2 m

?????????? What if the vectors look like this? 5 m 7 m + = ANYTIME the vectors are placed on an angle, you must find the components!!!!!!!!

Components 5 m + 7 m = We need an angle!! 5 m 7 m y component 23° 76° x component x component Angles are not to scale 

Angle must come from the horizontal for these to work A quick Trig Review Angle must come from the horizontal for these to work R = Resultant X = x component Y = y component 𝜃=𝐴𝑛𝑔𝑙𝑒 Do not be Afraid!!! These are just buttons on the calculator R Y 𝜃 X SOH CAH TOA Pythagorean Theorem 𝑠𝑖𝑛𝜃= 𝑌 𝑅 cos𝜃= 𝑋 𝑅 tan𝜃= 𝑌 𝑋 Y=𝑅∗𝑠𝑖𝑛𝜃 𝑋=𝑅∗𝑐𝑜𝑠𝜃 𝜃= tan −1 𝑌 𝑋 𝑅 2 = 𝑋 2 + 𝑌 2 Lets make one change 𝑅= 𝑋 2 + 𝑌 2

Components Angles are not to scale  5 m 7 m + We need an angle!! 5 m 23° 76° Find the components Y = 5*sin(23) = 1.953m X = 5*cos(23) = 4.602m Y = 7*sin(76) = 6.792m X = 7*cos(76) = 1.693m

𝜃=54.25° = 10.775 m 5 m 7 m + 76° 23° Y = 5*sin(23) = 1.953m X = 5*cos(23) = 4.602m Y = 7*sin(76) = 6.792m X = 7*cos(76) = 1.693m Y 1.953 + 6.792 = 8.745 m 𝑅= 6.295 2 + 8.745 2 = 10.775 m 𝜃= tan −1 ( 8.745 6.295 ) 𝜃=54.25° X 4.602 + 1.693 = 6.295 m

Practice 10 m 3 m 12 m + + 45° 15° y = 0 m 𝑦=3∗ sin 45 =2.121 𝑚 𝑦=12∗ sin 15 =3.105 𝑚 x = 10 m 𝑥=3∗ cos 45=2.121 𝑚 𝑥=12∗ cos 15=−11.59 𝑚 5.226 Y = 0 + 2.121 + 3.105 = 5.226 m 𝑅= 0.531 2 + 5.226 2 =5.252 𝑚 X = 10 + 2.121 – 11.59 = 0.531 m 𝜃= tan −1 ( 5.226 0.531 ) =84.19° 0.531

Find the Components of the Vector X 𝟑𝟗° Now you can use your short cuts Is the X component X=15cos(51) ??????????? 51° 𝑋=15 cos 39 15 m NO!!!!!!!!!!! You must first change the angle so that is comes from the horizontal axis! 𝑌=15 sin 39 90−51=39 Y