Quadratic Equations.

Slides:



Advertisements
Similar presentations
Solving Quadratic Equations Lesson 9-3
Advertisements

solution If a quadratic equation is in the form ax 2 + c = 0, no bx term, then it is easier to solve the equation by finding the square roots. Solve.
Solving Quadratic Equations Algebraically Lesson 2.2.
Chapter 16 Quadratic Equations. Martin-Gay, Developmental Mathematics – Solving Quadratic Equations by the Square Root Property 16.2 – Solving.
If b2 = a, then b is a square root of a.
Lesson 1-6 Solving Quadratic Equations. Objective:
Many quadratic equations can not be solved by factoring. Other techniques are required to solve them. 7.1 – Completing the Square x 2 = 20 5x =
7.1 – Completing the Square
4.8 Quadratic Formula and Discriminant
Essential Question: What are some things the discriminate is used for?
Chapter 16 Quadratic Equations.
Chapter 8 Review Quadratic Functions.
Using the factoring method, what are the solutions of y = x 2 + 5x + 6.
Martin-Gay, Developmental Mathematics 1 Warm Up Factor the following.
5.6 Quadratic Equations and Complex Numbers
Solving Quadratic Equations Using Completing the Square and the Quadratic Formula.
Module :MA0001NP Foundation Mathematics Lecture Week 9.
1 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 8-1 Quadratic Functions Chapter 8.
Essential Question: How do you use the quadratic formula and the discriminant? Students will write a summary including the steps for using the quadratic.
Pre-Calculus Section 1.5 Equations Objectives: To solve quadratics by factoring, completing the square, and using the quadratic formula. To use the discriminant.
Introduction Completing the square can be a long process, and not all quadratic expressions can be factored. Rather than completing the square or factoring,
Derivation of the Quadratic Formula The following shows how the method of Completing the Square can be used to derive the Quadratic Formula. Start with.
The Quadratic Formula Students will be able to solve quadratic equations by using the quadratic formula.
CPM Section 9.4A Quadratic Formula. Thus far we have considered two methods for solving quadratic function- factoring and using the square root property.
Solving Quadratic Equations Unit Review. Solving Quadratics By Graphing.
Getting Started The objective is to be able to solve any quadratic equation by using the quadratic formula. Quadratic Equation - An equation in x that.
Solving Quadratic Equations by Completing the Square.
Deriving the Quadratic Formula. The Quadratic Formula The solutions of a quadratic equation written in Standard Form, ax 2 + bx + c = 0, can be found.
Warm-Up Use the quadratic formula to solve each equation. 6 minutes 1) x x + 35 = 02) x = 18x 3) x 2 + 4x – 9 = 04) 2x 2 = 5x + 9.
Martin-Gay, Developmental Mathematics 1 Warm-Up #28 (Thursday, 11/12)
Warm-Up Solve each equation by factoring. 1) x x + 36 = 02) 2x 2 + 5x = 12.
Warm Up  1.) Write 15x 2 + 6x = 14x in standard form. (ax 2 + bx + c = 0)  2.) Evaluate b 2 – 4ac when a = 3, b = -6, and c = 5.
Copyright © Cengage Learning. All rights reserved. Fundamentals.
3.4 Chapter 3 Quadratic Equations. x 2 = 49 Solve the following Quadratic equations: 2x 2 – 8 = 40.
Lesson 6.5: The Quadratic Formula and the Discriminant, pg. 313 Goals: To solve quadratic equations by using the Quadratic Formula. To use the discriminant.
Chapter 4 Quadratic Equations
2.2 Solving Quadratic Equations Algebraically Quadratic Equation: Equation written in the form ax 2 + bx + c = 0 ( where a ≠ 0). Zero Product Property:
Solving Quadratic Equations by the Quadratic Formula.
Section 2.5 – Quadratic Equations
Chapter 11 Quadratic Equations.
5.6 Quadratic Formula & Discriminant
4.6 Quadratic formula.
The Quadratic Formula & Discriminant
Using the Quadratic Formula to Find Solutions
Chapter 4 Quadratic Equations
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Solving quadratics methods
Derivation of the Quadratic Formula
NAME:-RAVIKANT KUMAR CLASS:-10 ROLL:-20.
4.6 Quadratic formula.
Solving Quadratic Equations by the Quadratic Formula
Worksheet Key 9 11/14/2018 8:58 PM Quadratic Formula.
The Quadratic Formula..
Warm up – Solve by Completing the Square
The Quadratic Formula.
9-6 The Quadratic Formula and Discriminant
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Quadratic Formula & the Discriminant
Quadratic Equations and Functions
Review: Simplify.
Chapter 8 Quadratic Functions.
Quadratic Equations.
Chapter 9 Section 3.
Chapter 3 Quadratic Equations
Solve quadratic equations using the: QUADRATIC FORMULA
Warm-up  .
Quadratic Formula & Discriminant
Applying the Quadratic Formula
Copyright 2013, 2009, 2005, 2002 Pearson, Education, Inc.
Presentation transcript:

Quadratic Equations

Solving Quadratic Equations by the Square Root Property

Martin-Gay, Developmental Mathematics Square Root Property We previously have used factoring to solve quadratic equations. This chapter will introduce additional methods for solving quadratic equations. Square Root Property If b is a real number and a2 = b, then Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Square Root Property Example Solve x2 = 49 Solve 2x2 = 4 x2 = 2 Solve (y – 3)2 = 4 y = 3 ± 2 y = 1 or 5 Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Square Root Property Example Solve x2 + 4 = 0 x2 = −4 There is no real solution because the square root of −4 is not a real number. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Square Root Property Example Solve (x + 2)2 = 25 x = −2 ± 5 x = −2 + 5 or x = −2 – 5 x = 3 or x = −7 Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Square Root Property Example Solve (3x – 17)2 = 28 3x – 17 = Martin-Gay, Developmental Mathematics

Solving Quadratic Equations by the Quadratic Formula

Martin-Gay, Developmental Mathematics The Quadratic Formula Another technique for solving quadratic equations is to use the quadratic formula. The formula is derived from completing the square of a general quadratic equation. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Quadratic Formula A quadratic equation written in standard form, ax2 + bx + c = 0, has the solutions. Martin-Gay, Developmental Mathematics

Solving Quadratic Equations Steps in Solving Quadratic Equations If the equation is in the form (ax+b)2 = c, use the square root property to solve. If not solved in step 1, write the equation in standard form. Try to solve by factoring. If you haven’t solved it yet, use the quadratic formula. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Quadratic Formula Example Solve 11n2 – 9n = 1 by the quadratic formula. 11n2 – 9n – 1 = 0, so a = 11, b = -9, c = -1 Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Quadratic Formula Example Solve x2 + x – = 0 by the quadratic formula. x2 + 8x – 20 = 0 (multiply both sides by 8) a = 1, b = 8, c = -20 Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Solving Equations Example Solve the following quadratic equation. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Quadratic Formula Example Solve x(x + 6) = -30 by the quadratic formula. x2 + 6x + 30 = 0 a = 1, b = 6, c = 30 So there is no real solution. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Discriminant The expression under the radical sign in the formula (b2 – 4ac) is called the discriminant. The discriminant will take on a value that is positive, 0, or negative. The value of the discriminant indicates two distinct real solutions, one real solution, or no real solutions, respectively. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics The Discriminant Example Use the discriminant to determine the number and type of solutions for the following equation. 5 – 4x + 12x2 = 0 a = 12, b = –4, and c = 5 b2 – 4ac = (–4)2 – 4(12)(5) = 16 – 240 = –224 There are no real solutions. Martin-Gay, Developmental Mathematics

Martin-Gay, Developmental Mathematics Solving Equations Example Solve 3x = x2 + 1. 0 = x2 – 3x + 1 Let a = 1, b = -3, c = 1 Martin-Gay, Developmental Mathematics