Projectile Motion.

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Presentation transcript:

Projectile Motion

PROJECTILE MOTION An object launched into space without motive power of its own is called a projectile. If we neglect air resistance, the only force acting on a projectile is its weight, which causes its path to deviate from a straight line. The projectile has a constant horizontal velocity and a vertical velocity that changes uniformly under the influence of the acceleration due to gravity.

HORIZONTAL PROJECTION If an object is projected horizontally, its motion can best be described by considering its horizontal and vertical motion separately. In the figure we can see that the vertical velocity and position increase with time as those of a free-falling body. Note that the horizontal distance increases linearly with time, indicating a constant horizontal velocity.

Motion is dictated by gravity Vertical motion

Horizontal Motion

What if it moves in 2 directions at once??? Motion becomes a combination of two different motions. The two different motions must be treated differently. Horizontal motion is affected by………….nothing Vertical motion is affected by…………Gravity What if it moves in 2 directions at once???

Problem solving Process Step Action Formula 1 List given information 2 Use height to find time xy = 5t2 3 Use time to find horizontal distance xx = vxt Problem solving Process

A pool ball leaves a 0.60-meter high table with an initial horizontal velocity of 2.4 m/s. Predict (a)the time required for the pool ball to fall to the ground and (b)the horizontal distance between the table's edge and the ball's landing location. xx = vx= ay = Xy = t = Example 1

Determine the time xy = 5t2 becomes Determine the distance xx = vxt Solve the problem

A soccer ball is kicked horizontally off a 22 A soccer ball is kicked horizontally off a 22.0- meter high hill and lands a distance of 35.0 meters from the edge of the hill. Determine (a)the time it takes for the soccer ball to reach the ground, and (b)the initial horizontal velocity of the soccer ball. xx = vx= ay = xy = t = Example 2

Determine the time xy = 5t2 becomes Determine the distance xx = vxt Solve the problem