Module 7.15 Quanyka’s Quilts

Slides:



Advertisements
Similar presentations
Graphing Quadratic Functions Converting General Form To Standard Form The standard form and general form of quadratic functions are given below. General.
Advertisements

Example 1 Identifying Slopes and y-intercepts Find the slope and y -intercept of the graph of the equation. ANSWER The line has a slope of 1 and a y -intercept.
Solve an equation with variables on both sides
Intro To Algebra By: Carolyn Barone.
Vertical, Adjacent, Complementary, and Supplementary Angles Identify angles as vertical, adjacent, complementary, or supplementary. Start.
Can You Figure the Amount of Yardage to Buy?. What size is your bed?
How to solve using cross multiplication Created by: Brittany and Andrea.
5.8 Complete the Square This is the second to last lesson for MT5. Our last lesson will be on solving word problems. This lesson is on “Completing the.
EXAMPLE 4 Find the length of a hypotenuse using two methods SOLUTION Find the length of the hypotenuse of the right triangle. Method 1: Use a Pythagorean.
Decide if an equation has no solutions EXAMPLE 4 3x = –2 Write original equation. 3x + 5 = –8 Subtract 6 from each side. ANSWER The absolute value.
Solving Linear Equations
Solve Equations with Variables on Both Sides
Addition / Subtraction of Decimal Fractions When adding / subtracting decimal fractions. Be sure to “ line up “ your decimals to keep the place values.
$100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300.
Example #1 Add the whole numbers, then add the fractions. Rewrite with a common denominator.
What is Divisibility? Divisibility means that after dividing, there will be No remainder.
Ways to Check for Divisibility Dividing By 1 All numbers are divisible by 1.
Table of Contents Graphing Quadratic Functions Converting General Form To Standard Form The standard form and general form of quadratic functions are given.
G Stevenson What Are Tessellations? Basically, a tessellation is a way to tile a floor (that goes on forever) with shapes so that there is no overlapping.
Linear Equations in Two Variables A Linear Equation in Two Variables is any equation that can be written in the form where A and B are not both zero.
EXAMPLE 1 Identifying Slopes and y -intercepts Find the slope and y -intercept of the graph of the equation. a. y = x – 3 b. – 4x + 2y = 16 SOLUTION a.
Ways to Check for Divisibility Dividing By 1 All numbers are divisible by 1.
Polygons – Angles In Regular Polygons Regular Polygons have equal sides and equal angles, So if we can find one side, we would know the measure of all.
How can you draw shapes when only given lengths of sides?
Step One Draw a square on your paper. Step Two Beginning in the top left corner of the square, measure to the right about a half inch and place a dot.
Use the substitution method
Break into Simpler Parts
Addition / Subtraction of Decimal Fractions When adding / subtracting decimal fractions. Be sure to “ line up “ your decimals to keep the place values.
Section 9-2 Graphing Circles 1 General form for a circle Represents the center of the circle Represents a point on the circle Represents the radius of.
EXAMPLE 1 Find an inverse relation Find an equation for the inverse of the relation y = 3x – 5. Write original relation. y = 3x – 5 Switch x and y. x =
EXAMPLE 2 Solving an Equation Involving Decimals 1.4x – x = 0.21 Original equation. (1.4x – x)100 = (0.21)100 Multiply each side by 100.
EXAMPLE 1 Find an inverse relation Find an equation for the inverse of the relation y = 3x – 5. Write original relation. y = 3x – 5 Switch x and y. x =
x + 5 = 105x = 10  x = (  x ) 2 = ( 5 ) 2 x = 5 x = 2 x = 25 (5) + 5 = 105(2) = 10  25 = 5 10 = = 10 5 = 5.
Finding the Area of Polygons Rectangles Parallelograms Triangles Trapezoids.
{ 3.2: Solving Addition and Subtraction Equation.
Bell Work: Simplify -(-4) + (-2) + (-(-6)) -(+4) – (-5) + 5 – (-3) + (-6)
Comparative Relational Thinking
{ Module 4 Lesson 3 Model tiling with centimeter and inch unit squares as a strategy to measure area.
5x(x 2 – 4) (y 2 + 4)(y 2 – 4) (9 + d 2 )(9 – d 2 )
System of Equations Adapted by Mrs. Garay. Warm Up Solve for the indicated variable. 1. P = R – C for R 2. V = Ah for A 3. R = for C R = P + C Rt + S.
Then/Now You solved quadratic equations by using the square root property. Complete the square to write perfect square trinomials. Solve quadratic equations.
Factoring Trinomials.
Completing the Square 8
Perimeter.
Tessellation and prints
Germination Experiment
Solve a quadratic equation
قانون المنافسة ومنع الاحتكار
Polygons – Angles In Regular Polygons
Special Right Triangles
Module 7.15 Quanyka’s Quilts
10.7 Solving Quadratic Equations by Completing the Square
ديبــــاجــــــة: صادق الكنيست الإسرائيلي في تاريخ على اقتراح قانون دائرة أراضي إسرائيل (تعديل رقم7) – 2009 الذي يشكّل، عمليًا، خطة إصلاح شاملة.
USING GRAPHS TO SOLVE EQUATIONS
Ex. 1 Solve by factoring. 2x2 + 9x + 7 = 0 6x2 – 3x = 0
Solving Inequalities by Adding or Subtracting
Solving One Step Equations
Using the Addition and Multiplication Principles Together
Angle Measure in Triangles
Solve an inequality using subtraction
½ of 6 = 3.
Quiz Date 1/22/19 Change For version B #5
Factoring Trinomials.
Example 2B: Solving Linear Systems by Elimination
Solving basic equations
Measurement.
Why We Need Car Parking Systems - Wohr Parking Systems
Types of Stack Parking Systems Offered by Wohr Parking Systems
Constructed Responses
Add Title.
Presentation transcript:

Module 7.15 Quanyka’s Quilts

𝐴 𝑥 =(𝑥+5)(𝑥+2) 𝐴 𝑥 = 𝑥 2 +7𝑥+10 Add 5 inches on this side Original Quilt 𝑥 2 Add 5 inches on this side “Fill in the quilt” Add 2 inches on this side 𝐴 𝑥 = 𝑥 2 +7𝑥+10

𝐴 𝑥 =(𝑥+2)(𝑥+4) 𝐴 𝑥 = 𝑥 2 +6𝑥+8 Add 2 inches on this side Original Quilt 𝑥 2 Add 2 inches on this side “Fill in the quilt” Add 4 inches on this side 𝐴 𝑥 = 𝑥 2 +6𝑥+8

𝐴 𝑥 =𝑥(𝑥+3) 𝐴 𝑥 = 𝑥 2 +3𝑥 Add nothing to this side Original Quilt 𝑥 2 Add nothing to this side Nothing to “fill in” Add 3 inches on this side 𝐴 𝑥 = 𝑥 2 +3𝑥

𝐴 𝑥 =(𝑥+6)(𝑥+6) 𝐴 𝑥 = 𝑥 2 +12𝑥+36 Add 6 inches to this side Original Quilt 𝑥 2 Add 6 inches to this side “Fill in the quilt” Add 6 inches on this side 𝐴 𝑥 = 𝑥 2 +12𝑥+36

𝐴 𝑥 =(𝑥+2)(𝑥+7) 𝐴 𝑥 = 𝑥 2 +9𝑥+14 Add 2 inches to this side Original Quilt 𝑥 2 Add 2 inches to this side “Fill in the quilt” Add 7 inches on this side 𝐴 𝑥 = 𝑥 2 +9𝑥+14

Notice that this quilt had extensions of 3 inches and 6 inches… 𝐴 𝑥 = 𝑥 2 +3𝑥+6𝑥+18 There are 3 inches on this side Original Quilt 𝑥 2 Notice that this quilt had extensions of 3 inches and 6 inches… 3 x 6 = 18 3 + 6 = 9 There are 6 inches on this side 𝐴 𝑥 = 𝑥 2 +9𝑥+18 𝐴 𝑥 =(𝑥+3)(𝑥+6)

𝐴 𝑥 = 𝑥 2 +12𝑥+2𝑥+24 𝐴 𝑥 = 𝑥 2 +14𝑥+24 𝐴 𝑥 =(𝑥+12)(𝑥+2) There are 12 inches on this side Original Quilt 𝑥 2 Notice again… 12 x 2 = 24 12 + 2 = 14 There are 2 inches on this side 𝐴 𝑥 = 𝑥 2 +14𝑥+24 𝐴 𝑥 =(𝑥+12)(𝑥+2)