ENGINEERING CURVES By: Muhammad Zahid.

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Presentation transcript:

ENGINEERING CURVES By: Muhammad Zahid

ENGINEERING CURVES While designing Objects various types of curves are used. Curves which are commonly used in engineering drawing are: 1. conic section. 2. cycloidal curves. 3. involute. 4. evolutes. 5. spirals 6. helix

CONIC CURVES Section formed by the intersection of a right circular cone by a plane in different positions relative to the axis of the cone are called conics . e.g. Parabola, hyperbola and ellipse.

CONIC CURVES CONIC Conic is defined as the locus of a point moving in a plane such that the ratio of its distance from a fixed point and a fixed straight line is always constant. This ratio is called Eccentricity. Fixed point  is called Focus Fixed line is called Directrix

CONIC CURVES   The eccentricity is always < 1 for   Ellipse = 1   for Parabola > 1   for Hyperbola  

CONIC CURVES when e=1/2, the curve is an  Ellipse, when e=1, it is a parabola and when e=2, it is a hyperbola.  Figure below shows the ellipse, parabola and hyperbola.

CONIC CURVES ELLIPSE:- Construction of Ellipse:- An ellipse can be defined as where a & b are the length of major and minor axes of the ellipse.

CONIC CURVES ELLIPSE:-

CONIC CURVES ELLIPSE:- draw any vertical line AB as directrix. at any point C on this line draw a perpendicular line to the AB. Mark a focus F on the axis such that CF=80mm Divide CF into 7 equal parts (sum of numerator and denominator of eccentricity) and mark the forth point from C as vertex V. so AT point V draw a perpendicular VB equal to length VF.

CONIC CURVES ELLIPSE:- draw a line joining C and B. Though point F draw a line at 45° which meets the line CB at point D. Through D, drop a perpendicular DV’ on CC’. Bisect the line VV’ and mark O on the intersection point. Mark any point on the axis between VF and draw perpendicular line to meet CD at point 1’. With F as a centre and radius = 1–1’, cut two arcs on the perpendicular through 1 to locate P1 and P1’.

CONIC CURVES ELLIPSE:- P1 and P1’ are the points on the ellipse because the distance of P1 from AB is equal to C1. So P1-F=1-1’ and Similarly, with F as centre and radii = 2–2’, 3–3’, etc., cut arcs on the corresponding perpendiculars to locate P2 and P2’, P3 and P3’, etc. Also, cut similar arcs on the perpendicular through O to locate V1 and V1’.

PARABOLA Parabola(Applications) There are a large number of applications for parabolic shapes. Some of these are in searchlight mirrors, telescopic mirrors, a beam of uniform strength in design applications, the trajectory of the weightless flight, etc.

PARABOLA Constructing a Parabola draw any vertical line AB as directrix. at any point C on this line draw a perpendicular line to the AB. Mark a focus F on the axis such that CF=60mm Bisect CF into equal parts and mark the mid point from C as vertex V. so AT point V draw a perpendicular VB equal to length VF. draw a line joining C and B.

PARABOLA Mark a few points, say, 1, 2, 3, … on VC’ and erect perpendiculars through them meeting CB produced at 1’, 2’, 3’, … With F as a centre and radius = 1–1’, cut two arcs on the perpendicular through 1 to locate P1 and P1’. Similarly, with F as a centre and radii = 2–2’, 3–3’, etc., cut arcs on the corresponding perpendiculars to locate P2 and P2’, P3 and P3’, etc. Draw a smooth curve passing through V, P1, P2, P3 … P3’, P2’, P1’.

PARABOLA

HYPERBOLA Hyperbola (Applications) Hyperbolic shapes finds large number of industrial applications like the shape of cooling towers, mirrors used for long distance telescopes, etc

HYPERBOLA Constructing a Hyperbola (Eccentricity Method) Construction of hyperbola by eccentricity method is similar to ellipse and parabola. Let we construct a Hyperbola where the eccentricity, e = 3/2 and the distance of the focus from the directrix = 50 mm.