Lesson 36 – Quadratic Trigonometric Equations

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Presentation transcript:

Lesson 36 – Quadratic Trigonometric Equations PreCalculus 11/30/2018 PreCalculus

FAST FIVE Solve the quadratic equation x2 + 2x = 15 algebraically Solve the quadratic equation x2 + 2x = 15 graphically Solve each equation by factoring 1. (k+1)(k-5) = 0 2. (a+1)(a+2) = 0 3. (4k+5)(k+1) = 0 4. (2m+3)(4m+3) = 0 5. x2 – 11x + 19 = -5 6. n2 + 7n + 15 = 5 7. n2 – 10n + 22 = -2 8. n2 + 3n – 12 = 6 9. 6n2 – 18n – 18 = 6 10. 7r2 – 14r = –7 11/30/2018 PreCalculus

(A) Prerequisite Skill: Factoring with Trig Factor the following trig expressions: 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations We will outline a process by which we come up with the solution to a trigonometric equation ANALYTICALLY using ALGEBRA We will outline a process by which we come up with the solution to a trigonometric equation GRAPHICALLY using ALGEBRA  it is important you understand WHY we carry out these steps, rather than simply memorizing them and simply repeating them on a test of quiz 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve sin2x – 1 = 0 on the domain 0 < x < 4π. Your first solution will be analytical. We will VERIFY with a graphic solution 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve the equation 2cos2x – 1 = -cosx on the domain 0 < x < 4π. Your first solution will be analytical. We will VERIFY with a graphic solution 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve the equation 8sin2x + 13sinx = 4 – 4sin2x on the domain - π < x < 3π. Your first solution will be analytical. We will VERIFY with a graphic solution 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(θ) = 1 if 0° < θ < 360 ° 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(θ) = 1 if 0° < θ < 360 ° 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(θ – 45°) = 1 if 0° < θ < 360 ° 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(θ + π/3) = 1 if -2π < θ < 5π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve cos2(x) + 2cos(x) = 0 for 0 < x < 2π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve cos2(x) + 2cos(x) = 0 for 0 < x < 2π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve cos2(2x) + 2cos(2x) = 0 for 0 < x < 2π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(x) - 3cos(x) + 1 = 0 for 0 < x < 2π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(x) - 3cos(x) + 1 = 0 for 0 < x < 2π 11/30/2018 PreCalculus

(B) Solving Quadratic Trigonometric Equations Solve 2cos2(2x - 2π/3) - 3cos(2x - 2π/3) + 1 = 0 for xεR 11/30/2018 PreCalculus

(C) Further Examples Solve the following without a calculator 11/30/2018 PreCalculus

(C) Further Examples Solve the following algebraically, without a GRAPHICAL approach 11/30/2018 PreCalculus

(D) Homework Nelson Textbook, Chap 6.6 http://mrsantowski.tripod.com/2010MathSLY1/Assessments/NelsonS66p541.pdf 11/30/2018 PreCalculus