Stoichiometry Lesson 1.

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Presentation transcript:

Stoichiometry Lesson 1

Balanced chemical equations can be used to relate the amounts of reactants and products in chemical reactions. 2Fe2O3 + 3C → 4Fe + 3CO2   The coefficients mean that 2 moles of Fe2O3 react with 3 moles of C to produce 4 moles of Fe and 3 moles of CO2. The coefficients are a chemical recipe that describes the exact amounts of reactants required to make exact amounts of products in moles.

1. How many grams Fe2O3 of are required to produce 105 g of Fe? Fe2O3 + 3C → Fe + 3CO2 4 ?g 105 g 105 g Fe x 1 mole x 2 mole Fe2O3 x 159.6 g = 150. g 55.8 g 4 mole Fe 1 mole

2. How many grams of C are require to consume 155 g of Fe2O3? Fe2O3 + C → 4 Fe + 3 CO2 2 3 155 g ? g 155 g Fe2O3 x 1 mole x 3 mole C x 12.0 g = 17.5 g 159.6 g 2 mole Fe2O3 1 mole

3. How many grams of Al2(CO3)3 are produced by the complete 3. How many grams of Al2(CO3)3 are produced by the complete reaction of 452 g of Al(NO3)3?   Al(NO3)3 + 3 Na2CO3 → Al2(CO3)3 + 6 NaNO3 2 1 452 g ? g 452 g Al(NO3)3 x 1 mole x 1 mole Al2(CO3)3 x 234.0 g = 248 g 213.0 g 2 mole Al(NO3)3 1 mole

4. How many moles of Na2CO3 are required to completely 4. How many moles of Na2CO3 are required to completely consume 152 g of Al(NO3)3?   Al(NO3)3 + Na2CO3 → Al2(CO3)3 + 6 NaNO3 2 3 152 g ? moles 152 g Al(NO3)3 x 1 mole x 3 mole Na2CO3 = 1.07 moles 213.0 g 2 mole Al(NO3)3