of [A] in rate law equations (if you have a gaseous system).

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Presentation transcript:

of [A] in rate law equations (if you have a gaseous system). Rate laws can be converted into equations that give the concentrations of substances at any time during the course of a reaction. First-Order Reactions -- Rate laws for 1st order rxns have the form: You can use P instead of [A] in rate law equations (if you have a gaseous system). rate = k [A] -- To find rxn [ ]s over time, use… kt = ln [A]o [A]t ln [A]t = ln [A]o – kt or… Plotting ln [A]t v. t gives a straight line w/slope… –k.

(CH3)2O(g) CH4(g) + H2(g) + CO(g) If this is a first-order process, with k = 6.8 x 10–4 s–1 and w/the initial pressure of (CH3)2O being 256 torr, find the partial pressure of (CH3)2O after 36.5 min. For gases, P mol (and therefore [ ]), so… kt = ln [A]o [A]t kt = ln Po Pt becomes 6.8 x 10–4 s–1 (2190 s) = ln (256/Pt) = ln (256/Pt) 1.4892 Taking “e-to-the-both-sides” yields… 4.4335 = 256/Pt Pt = 57.7 torr

Half-life of a reaction, t1/2: the time required for a reactant’s [ ] to drop to ½ of its orig. value For 1st order rxns: k t1/2 = 0.693 = ln 2 For 1st order reactions: -- t1/2 is independent of initial concentration -- the [ ] of reactants is cut in half... every half-life Ernest Rutherford is given credit for discovering the concept of radioactive half-life. It was later shown that the same math applies to the kinetics of first-order chemical reactions.

AND t1/2 changes w/time. (!)) Second-Order Reactions (that are 2nd order in just one reactant) e.g., rate = k [A]2 (NOT rate = k [A] [B]) kt 1 [A]t = [A]o – k t1/2 = 1 [A]o and (t1/2 DOES depend on init. [ ] of reactant A… AND t1/2 changes w/time. (!)) Plotting v. t gives a straight line w/slope… k. 1 [A]t ** Above equations do NOT apply to 2nd order reactions that are 1st order in two reactants.

That’s upside-down thinking.” 1st order rxns 2nd-order-in-only-one-R rxns k t1/2 = 1 [A]o k t1/2 = 0.693 = ln 2 kt = ln [A]o [A]t kt 1 [A]t = [A]o – t ln [A] (or ln P) t 1 [A] (or ) P slope = k slope = –k “It’s natural to want to finish 1st.” “To want to finish 2nd? That’s upside-down thinking.”