Law of Cosines and Sines

Slides:



Advertisements
Similar presentations
Area = ½ bc sinA = ½ ab sinC = ½ ac sinB
Advertisements

© Project Maths Development Team
Module 8 Lesson 5 Oblique Triangles Florben G. Mendoza.
Starter a 6 c A 49° 96° 1.Use the Law of Sines to calculate side c of the triangle. 2.Now find the Area of a Triangle.
Introduction to Trigonometry Lesson 9.9. What is Trigonometry? The shape of a right triangle is determined by the value of either of the other two angles.
45 ⁰ 45 – 45 – 90 Triangle:. 60 ⁰ 30 – 60 – 90 Triangle: i) The hypotenuse is twice the shorter leg.
Law of Cosines. We use the law of cosines and the law of sines because we need to be able to find missing sides and angles of triangles when they are.
The Sine Law (animated). Sine Law Let’s begin with the triangle  ABC:
Trigonometry. Basic Ratios Find the missing Law of Sines Law of Cosines Special right triangles
9.5 Apply the Law of Sines day 3 How do you use the law of sines to find the area of a triangle?
Finding Areas with Trigonometry. Objectives I can use trigonometry to find the area of a triangle.
Solution of Triangles COSINE RULE. Cosine Rule  2 sides and one included angle given. e.g. b = 10cm, c = 7 cm and  A = 55° or, a = 14cm, b = 10 cm and.
{ Law of Sines and Cosines Trigonometry applied to triangles without right angles. 1.
Page 288 – Area of Triangles Surveyors calculate measures of distances and angles so that they can represent boundary lines of parcels of land. The diagram.
Chapter 7 Jeopardy Game By:Kyle, Yash, and Brahvan.
Law of Sines. Triangles Review Can the following side lengths be the side lengths of a triangle?
Lesson 39 - Review of Right Triangle Trigonometry
13.4 L AW OF S INES 13.5 L AW OF COSINES Algebra II w/ trig.
Chapter 7 review Number 73 This method shows how to find the direction by adding the vector. You will use the laws of sines and cosines. To view this show,
Triangle Warm-up Can the following side lengths be the side lengths of a triangle?
$100 $200 $300 $400 $500 $200 $300 $400 $500 Geometric mean Pythagorean Thm. Special Right Triangles Law of Sines and Cosines Trigonometry Angles of.
Similarity in Right Triangles Geometry Unit 11, Day 7 Ms. Reed.
Review of Trig Ratios 1. Review Triangle Key Terms A right triangle is any triangle with a right angle The longest and diagonal side is the hypotenuse.
Area and the Law of Sines. A B C a b c h The area, K, of a triangle is K = ½ bh where h is perpendicular to b (called the altitude). Using Right Triangle.
Ambiguous Law of Sines Compute b sin A, then compare to a No solution One Solution Two Solutions One Solution Compute side a to side b No solution One.
Trigonometric Identities
1 Equations 7.3 The Law of Cosines 7.4 The Area of a Triangle Chapter 7.
1 What you will learn  How to solve triangles by using the Law of Cosines  How to find the area of triangles if the measures of the three sides are given.
Section Take a note: Up until now, our work with triangles has involved right triangles, And for that we use the Pythagorean Theorem. But there.
9-3 L AW OF S INES. L AW OF S INES A B Given an oblique triangle (no right angle) we can draw in the altitude from vertex B Label the altitude k and find.
You will use the sine and cosine ratio to find the sides and angles of a right triangles Pardekooper.
9-2 Sine and Cosine Ratios. There are two more ratios in trigonometry that are very useful when determining the length of a side or the measure of an.
EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve ABC with C = 107°, B = 25°, and b = 15. SOLUTION First find the angle: A = 180° – 107° – 25° =
CHAPTER 5 LESSON 4 The Law of Sines VOCABULARY  None.
What you’ll learn Use the Law of Sines to solve oblique triangles. Use the Law of Sines to solve, if possible, the triangle or triangles in the ambiguous.
南亚和印度.
April 21, 2017 The Law of Sines Topic List for Test
Trigonometry Chapter 9.1.
LAW of SINES.
Oblique Triangles.
The Cosine Rule.
Unit 6: Trigonometry Lesson: Law of coSines.
Warm-Up Solve the following triangle 14 61o *Homework Check*
Trigonometric Functions
…there are three trig ratios
6-3: Law of Cosines
…there are three trig ratios
Sine and Cosine Rule revision
Law of Cosines Notes Over
Warm Up Solve ΔSJT given s = 49, side j = 16, and angle S = 115°. S = _____ J = _____ T = _____ s = _____ j = _____ t = _____.
a 2 = b 2 + c b c cos A These two sides are repeated.
The General Triangle C B A.
Aim: How do we review concepts of trigonometry?
Day 96 – Trigonometry of right triangle 1
WELCOME BACK TO OMHS & WELCOME TO HONORS TRIGONOMETRY
Law of Sines and Cosines
Area of Triangles C a b A B c
13. Law of Sines.
Section 1.6 Law of Cosines.
The General Triangle C B A.
The Sine Rule C. McMinn.
Section 6.5 Law of Cosines Objectives:
Trigonometry for Angle
1..
Introduction to Trigonometric Functions
LT: I can use the Law of Sines and the Law of Cosines to find missing measurements on a triangle. Warm-Up Find the missing information.
Warm Up – 2/27 - Thursday Find the area of each triangle.
Review from yesterday…
…there are three trig ratios
Integrated Math 10 – Santowski
Presentation transcript:

Law of Cosines and Sines MA341 Brian Oberg 30 NOV 99

Introduction The objective here is to prove two points: Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A Law of Sines: a / sin A = b / sin B = c / sin C

Given Terms sin(A)^2+cos(A)^2 =1 sin A = a/c cos A = b/c Pythagorean relation: a^2+b^2=c^2

Law of Cosines Given any triangle ABC Label sides a,b,c

Law of Cosines Draw in altitude from any angle to its base; this forms two right triangles Label altitude h and the new point D

Law of Cosines sin A = h/b h = b sin A cos A = AD/b AD = b cos A

Law of Cosines AD = b cos A BD = c - AD BD = c - b cos A

Law of Cosines h = b sin A BD = c - b cos A a^2 = h^2 + (BD)^2 a^2 = (b sin A)^2 + (c-b cos A)^2

Law of Cosines a^2 = (b sin A)^2 + (c - b cos A)^2 (b sin A)^2 = b^2 sin(A)^2 (c - b cos A)^2 = c^2 - 2bc cos A + cos(A)^2

Law of Cosines a^2 = b^2 sin(A)^2 + c^2 - 2bc cos A + cos(A)^2 a^2= b^2(sin(A)^2 + cos(A)^2) + c^2 - 2bc cos A

Law of Cosines a^2= b^2(sin(A)^2 + cos(A)^2) + c^2 - 2bc cos A remember: sin(A)^2 + cos(A)^2=1 a^2 = b^2 + c^2 - 2bc cos A

Law of Sines sin A = h/b h = b sin A sin B = h/a h= a sin B

Law of Sines h = b sin A h= a sin B a sin B = b sin A a / sin A = b / sin B

Law of Sines Furthermore: a / sin A = b / sin B = c / sin C

Conclusion Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A Law of Sines: a / sin A = b / sin B = c / sin C