Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 1) to the left of z = 1.22 2) to the right of z = -1.4 3) between z = -.03 and z = .01 4) to the left of z = -1 OR to the right of z = 2 5) P(z < 1.48) 6) P(z > -.589) 7) P( -2.05 < z < -.004) 8) P( z < .125 OR z > 1.52) Find the indicated probabilities. A standardized math test was given to 1750 American high school students. The scores were normally distributed with a mean score of 875, and a standard deviation of 137. One American high school student is chosen at random. What is the probability that their score is: 9) less than 800? 10) more than 900? 11) between 800 and 900? 12) Either below 850 OR above 900?

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 1) to the left of z = 1.22 0.341 0.136 0.0215 0.0015 This answer MUST be more than .841, and less than .977. 2nd VARS 2 (-1E99, 1.22, 0, 1) = .889

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 2) to the right of z = -1.4 0.341 0.136 0.0215 0.0015 This answer MUST be more than .841, and less than .977. 2nd VARS 2 (-1.4, 1E99, 0, 1) = .919

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 3) between z = -.03 and z = .01 0.341 0.136 0.0215 0.0015 This answer is going to be quite small, since the distance between the two z-scores is so small. 2nd VARS 2 (-0.03, 0.01, 0, 1) = .016

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 4) to the left of z = -1 OR to the right of z = 2 0.341 0.136 0.0215 0.0015 Looking at the graph, we know the answer is going to be close to .18, because the cumulative area below -1 is .1575 and the cumulative area above 2 is .023.

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 4) to the left of z = -1 OR to the right of z = 2 0.341 0.136 0.0215 0.0015 There are two ways to do this: 1) Find the area to the left of -1 and add it to the area to the right of 2. 2) Find the area BETWEEN -1 and 2 and subtract that from 1.

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 4) to the left of z = -1 OR to the right of z = 2 0.341 0.136 0.0215 0.0015 There are two ways to do this: 1) Find the area to the left of -1 and add it to the area to the right of 2. 2nd VARS 2 (-1E99, -1, 0, 1) + 2nd VARS 2 (2, 1E99, O, 1) = .181

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 4) to the left of z = -1 OR to the right of z = 2 0.341 0.136 0.0215 0.0015 There are two ways to do this: 2) Find the area BETWEEN -1 and 2 and subtract that from 1. 1 – 2nd VARS 2 (-1, 2, 0, 1) = .181

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 5) P(z < 1.48) 0.341 0.136 0.0215 0.0015 This answer MUST be more than .841, and less than .977. 2nd VARS 2 (-1E99, 1.48, 0, 1) = .931

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 6) P(z > -.589) 0.341 0.136 0.0215 0.0015 This answer MUST be more than .500, and less than .841. 2nd VARS 2 (-.589, 1E99, 0, 1) = .722

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 7) P( -2.05 < z < -.004) 0.341 0.136 0.0215 0.0015 This answer is going to be quite close to .477, since that’s the area between -2 and 0. 2nd VARS 2 (-2.05, -.004, 0, 1) = .478

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 8) P( z < .125 OR z > 1.52) 0.341 0.136 0.0215 0.0015 Looking at the curve, our answer MUST be between .500 and .682

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 8) P( z < .125 OR z > 1.52) 0.341 0.136 0.0215 0.0015 There are two ways to do this: 1) Add the area to the left of .125 to the area to the right of 1.52. 2) Find the area BETWEEN .125 and 1.52 and subtract that from 1.

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 8) P( z < .125 OR z > 1.52) 0.341 0.136 0.0215 0.0015 There are two ways to do this: 1) Add the area to the left of .125 to the area to the right of 1.52. 2nd VARS 2 (-1E99, .125, 0, 1) + 2nd VARS 2 (1.52, 1E99, O, 1) = .614

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated area(s) under the standard normal curve. 8) P( z < .125 OR z > 1.52) 0.341 0.136 0.0215 0.0015 There are two ways to do this: 2) Find the area BETWEEN .125 and 1.52 and subtract that from 1. 1 – 2nd VARS 2 (.125, 1.52, 0, 1) = .614

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated probabilities. A standardized math test was given to 1750 American high school students. The mean score was 875, with a standard deviation of 137. One American high school student is chosen at random. What is the probability that their score is: 9) less than 800? 0.341 0.136 0.0215 0.0015 875 738 601 464 1012 1149 1286 This answer MUST be more than .1575, and less than .500. 2nd VARS 2 (-1E99, 800, 875, 137) = .292

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated probabilities. A standardized math test was given to 1750 American high school students. The mean score was 875, with a standard deviation of 137. One American high school student is chosen at random. What is the probability that their score is: 10) more than 900? 0.341 0.136 0.0215 0.0015 875 738 601 464 1012 1149 1286 This answer MUST be more than .1575, and less than .500. 2nd VARS 2 (900, 1E99, 875, 137) = .428

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated probabilities. A standardized math test was given to 1750 American high school students. The mean score was 875, with a standard deviation of 137. One American high school student is chosen at random. What is the probability that their score is: 11) between 800 and 900? 0.341 0.136 0.0215 0.0015 875 738 601 464 1012 1149 1286 This answer is probably going to be around .3 or so (it just looks to be about as wide as the area with .341 under it). 2nd VARS 2 (800, 900, 875, 137) = .280

Sections 5-1 and 5-2 Quiz Review Warm-Up Find the indicated probabilities. A standardized math test was given to 1750 American high school students. The mean score was 875, with a standard deviation of 137. One American high school student is chosen at random. What is the probability that their score is: 12) Either below 850 OR above 900? 0.341 0.136 0.0215 0.0015 875 738 601 464 1012 1149 1286 This answer is going to be fairly large, since the distance between the two is pretty small. 1 – 2nd VARS 2 (850, 900, 875, 137) = .855