Lesson 7: Predicting Precipitate Formation

Slides:



Advertisements
Similar presentations
Unit 7 - Chpt 16 - Solubility equilibria and Quantitative analysis Solubility equilibria and Ksp Predict precipitation HW set1: Chpt 16 - pg #
Advertisements

Solubility Equilibria
Equilibrium 1994A Teddy Ku A MgF 2(s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+
Solubility Products Consider the equilibrium that exists in a saturated solution of BaSO 4 in water: BaSO 4 (s) Ba 2+ (aq) + SO 4 2− (aq)
Solubility Product Constant A special case of equilibrium involving dissolving. Solid  Positive Ion + Negative Ion Mg(NO 3 ) 2  Mg NO 3 - Keq.
Solubility Product Constant
Solubility Product Determining Precipitation Conditions.
Section 4: Solubility Equilibrium. Objectives Explain what is meant by solubility product constants, and calculate their values. Calculate solubilities.
Precipitation Analysis Considering the formation of solid from solution. Q vs. Ksp Ion Analysis.
Unit 7 - Chpt 16 - Solubility equilibria and Quantitative analysis Solubility equilibria and Ksp Predict precipitation Qualitative analysis HW set1: Chpt.
Ionic product and predicting precipitates. What is the solubility of Pb(OH) 2 in 0.15 mol L –1 KOH? K s (Pb(OH) 2 ) = 6 × 10 –16. 1 Write the equilibrium.
CH 223 LECTURE # 15 SAMPLE QUESTIONS. The lesson is for not only accuracy, but speed. You will always be under some time constraint. You can work in pairs.
Solubility Lesson 5 Trial Ion Product. We have learned that when two ionic solutions are mixed and if one product has low solubility, then there is a.
Solubility Lesson 4 Calculating Ksp.
Chapter 21 Notes, part III Ksp and Common Ion Effect.
Ksp: The Solubility Product Constant
Solubility Equilibrium Chapter 7. The Solubility Equilibrium Remember from SPH3U: Solubility is the amount of solute that dissolves in a given amount.
Unit 17. Dissolution: the process in which an ionic solid dissolves in a polar liquid. AgCl (s) ↔ Ag + (aq) + Cl - (aq) Precipitation: the process in.
Le Chatelier’s Principle
Chemistry 12 – Sorting out Solubility Problems This will help you with the following types of Solubility Problems: 1-ion concentrations in mixtures (no.
Unit 10 Test Review. 1. Dinitrogen trioxide gas decomposes to nitrogen monoxide gas and nitrogen dioxide gas in an endothermic process. Predict the effect.
Solubility Equilibrium Solubility Product Constant Ionic compounds (salts) differ in their solubilities Most “insoluble” salts will actually dissolve.
Solubility Equilibria
Equilibrium Problems Chapter Steps for Solving Equilibrium Problems 1.______________________ 2.______________________ 3.______________________.
Solubility Lesson 6 Changing solubility/Common Ion Effect.
Complex Ion Equilibria and Solubility A complex ion can increase the solubility of a salt. Ag + (aq) + 2 NH 3 (aq) Ag(NH 3 ) 2 + (aq) K f = [Ag(NH.
CHAPTER 17 - SOLUBILITY AND PRECIPITATION. Read intro on page 560 Dissolution CaCl 2(s) ↔ Ca +2 (aq) + 2 Cl - (aq) CaCl 2(s) ↔ Ca +2 (aq) + 2 Cl - (aq)Precipitation.
DO NOW: What is dissolution. What is precipitation
SOLUBILITY I. Saturated Solution BaSO 4(s)  Ba 2+ (aq) + SO 4 2- (aq) Equilibrium expresses the degree of solubility of solid in water. Ksp = solubility.
Solubility and Complexation Equilibria Chapter 18.
The equilibrium product constant A salt is considered soluble if it dissolves in water to give a solution with a concentration of at least 0.1 M at room.
Chapter 16 Solubility Equilibria. Saturated solutions of “insoluble” salts are another type of chemical equilibria. Ionic compounds that are termed “insoluble”
Ionic Equilibria III: The Solubility Product Principle
Ksp Values that indicate how soluble a solution is.
To Precipitate or not 6-6.
Chapter 7.6 Solubility Equilibria and the Solubility Product Constant
Solubility and Complexation Equilibria
Warm Up #5 __ AgCl(s) ⇌ __ Ag+1(aq) + __ Cl-1(aq) Balance the following and construct a K equation. What is the ratio between the solid and the two products?
Solubility Constants: Ksp
Equilibrium Jot down the answers to the following six questions
SCH4U:Solubility Equilibrium Lesson
KSP = Solubility product constant
Solubility Equilibria
Solubility equilibrium Entropy & Free Energy
Lesson 8: Solubility and Titrations
Ion Product Quotient: Predicting Precipitation
Lesson 6: The Solubility Product
Stoichiometry and molarity practice
Quiz 1. Find the concentration of Cu+ in equilibrium with CuBr(s) and M Br-. The Ksp for CuBr is 5x10-9. Show your work. A M B. 5 x 10-8.
The Solubility Product Constant (Ksp)
Solubility Product Constant (Ksp)
Solubility Lesson 5 Trial Ion Product.
Chapter 17: Chemical Equilibrium
Lesson # 5 The Solubility Product
Solubility Lesson 8 Titrations & Max Ion Concentration.
Solubility Lesson 8 Review Notes.
Unit 2, Lesson 10: Equilibrium Calculations – Part II
Lesson 2: Solubility Calculations
Solubility Product KSP.
Unit 3, Lesson 14: Dilutions
Solubility Lesson 7 Changing solubility.
Predicting Equilibrium
Solubility Equilibria
Solubility Product Constant
Chem 30: Solubility The Common Ion Effect.
Catalyst It is found that 1.1 x 10-2 g of SrF2 dissolves per 100 mL of solution. Calculate the solubility product of SrF2. End.
Solubility Product Constant
Solubility & Simultaneous Equilibria Part I: Ksp and Solubility
Solubility & Simultaneous Equilibria Part I: Ksp and Solubility
Solubility & Simultaneous Equilibria Part I: Ksp and Solubility
Presentation transcript:

Lesson 7: Predicting Precipitate Formation Unit 3: Solubility Lesson 7: Predicting Precipitate Formation

The Trial Ion Product Last unit, we used a trial Keq called the reaction quotient (Q). In this unit we will use a trial Ksp called the trial ion product (Q). Q = the product of ion concentrations that exists (what we have) Ksp = the product of ion concentrations that is needed to establish equilibrium (what we need to form a saturated solution)

Think-Pair-Share Predict what will happen when: Q < Ksp Q = Ksp TPS – 5 min

Calculations Involving Q Example 1 (Try it!): Will a precipitate form when 5.0 mL of 6.0x10-5 M Ag+ mixes with 10.0 mL of 4.2x10-6 M Cl-? (Hint: Note that when the two solutions are mixed they dilute each other!) “We do” – 15 min

Calculations Involving Q Example 2: If 25.0 mL of 4.50x10-3 M Pb(NO3)2 is mixed with 35.0 mL of 2.80x10-3 M MgI2, will a precipitate form? Example 3: What [Cl-] is required to just start precipitation of AgCl(s) from a 3.6x10-3 M solution of Ag+? “I do” – 20 min #2 – dilution calc, then find Q #3 – Q = Ksp, solve for [Cl-]

Homework Pg. 98 #56-68 even numbers 10 min