Raffle_snaffle Recall from homework set #2, air in a closed system undergoes two processes in series. First the air is compressed from state 1 to state.

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Presentation transcript:

raffle_snaffle Recall from homework set #2, air in a closed system undergoes two processes in series. First the air is compressed from state 1 to state 2 in a polytropic manner with n=1.3. Next the air is expanded at constant pressure from state 2 back to state 3, which is at the original volume. The following state point properties are known: P1=110 kPa, v1=0.8m3/kg, v2=0.4 m3/kg. Using state point information from homework set #2, determine the following. a. Draw the processes and label the state points on a single T-‐‐s diagram. b. Determine the entropy produced per mass from state 1 to state 2. Use a b Some specific values of n correspond to particular cases: n=0 is an isobaric process, n=∞ is an isochoric process. In addition, when the ideal gas law applies: n=1 is an isothermic process, n=γ is an isentropic process.

State 1 to state 2 is adiabatic with specific heat ratio 1.3 ? Because it’s adiabatic it is isentropic. On the T-S diagram. If it’s an isentropic/adiabatic compression, then the temperature will rise. Hence the numbering. State 2 to 3 is isobaric. Slope is contained in this equation. The slope is less than it would be if the process were to have been constant volume aka isochoric.