Solving for Variables Section 1.6.

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Presentation transcript:

Solving for Variables Section 1.6

What is the distance formula? d = rt But what if we were given the distance and time, but wanted to find the rate? We need to isolate “r” r = d/t

What if we wanted to figure out Celsius given Fahrenheit: The formula for a Fahrenheit temperature in terms of degrees Celsius is: What if we wanted to figure out Celsius given Fahrenheit: -32 -32 But remember you need multiply the whole left side by 5/9

Example: Solve for t s = 9s2 + t Undo this as you would any other equation…what must you do to get t by itself? s = 9s2 + t Subtract the 9s2 from both sides… –9s2 –9s2 t = s – 9s2 This is the solution.

The formula for the Perimeter of a Rectangle is P = 2L + 2W Example: Solve for W P = 2L + 2W – 2L –2L P – 2L = 2W 2 2 W L

Example: Solve for b A = 5a2b What must you do to get b by itself? We must “undo” the multiplication by 5a2 A = 5a2b Divide 5a2 from both sides… 5a2 5a2 b = A 5a2 This is the solution.

Solve for V: We can flip both sides of the equation! Now just multiply both sides by “m”

Solve for m: We can flip both sides of the equation! Now just multiply both sides by “m”

Solve for “y”. 5x – 3y = 6 -5x -5x -3y = -5x + 6 y = x - 2 -3 -3 -3

Solve for “y” 2y + 2 = 4x - 2 - 2 2y = 4x - 2 y = 2x - 1 2 2 2

3x – y = 12 -3x -3x -y = -3x + 12 y = 3x - 12 Solve for “y” -1 -1 -1 STUDENTS ALWAYS FORGET THE NEGATIVE!!! -1 -1 -1

Solve for “y”. 5x + 2y = 10 -5x -5x 2y = -5x + 10 y = x + 5 2 2 2

Solve for “y” 4(x – 3) + 3y = 12 4x – 12 + 3y = 12 -4x -4x + 12 + 12 3y = -4x + 24 3 3 3 4(x – 3) + 3y = 12

Solve for “y” 2y + 3(y – 4) + 5x = 2 2y + 3y – 12 + 5x = 2 -5x -5x 5y - 12= -5x + 2 + 12 + 12 5y = -5x + 14 5 5 5 Solve for “y” 2y + 3(y – 4) + 5x = 2