Professor Dave problem from yesterday

Slides:



Advertisements
Similar presentations
Phase Changes The boiling point is the temperature at which the (equilibrium) vapor pressure of a liquid is equal to the external pressure. The normal.
Advertisements

White Board Practice Problems © Mr. D. Scott; CHS.
Calculations in Chapter 10. Molar Enthalpy of Fusion Used when melting or freezing = ___energy ____ mol of substance Can be arranged to find any of the.
How many joules are needed to change 120.g of
Practice Energy Calculation Quiz. How much energy does it take to convert 722 grams of ice at  211  C to steam at 675  C? (Be sure to draw and label.
Calorimetry How to use math to describe the movement of heat energy Temperature Change Problems Temperature Change Problems Phase Change Problems Phase.
Temperature ( o C) Heat (J) Solid Liquid Gas Heat = mass x ΔT x C l Heat = mass x H Fusion Heat = mass x H Vaporization s ↔ l l ↔ g H Vaporization H Fusion.
Good Morning! 9/20/2015  Today we will be… Preparing for tomorrow’s test by going through the answers to the Practice Test  Before we get into the practice.
THERMOCHEMISTRY: HEAT and CHANGE. When a material is heated (or cooled), it can undergo one of these changes: Its temperature changes OR Its physical.
Heating & Cooling Curves A STEP BY STEP PRACTICE PROBLEM © Mr. D. Scott; CHS.
Molar Enthalpy of Vaporization
Thermochemistry Enthalpy: change in heat. Energy and Change of State You do not have to write this When energy is added to a solid substance, its temperature.
Calculating Heat During Change of Phase Heat Added (J)
Aim: How to measure energy absorbed during a phase change DO NOW: 1. A g piece of iron absorbs joules of heat energy, and its temperature.
Specific Heat Practice. Gold has a specific heat of J/(g°C). How many joules of heat energy are required to raise the temperature of 15 grams of.
Measurement of Heat Energy. The amount of heat given off or absorbed in a reaction can be calculated by a) q=mc∆T(Table T) q= heat (in joules or calories)
C ice = J/g°CC water = J/g°C C steam = J/g°C ∆H fus = kJ/mol, ∆H vap = kJ/mol What is the change in enthalpy when g.
Chapter 14: Liquids and Solids
Phase Change Problems.
Multi-step Problems.
Energy Transfer and Thermal Equilibrium
Heating / Cooling Curve Calculations
States of Matter.
Thermochemistry Practice
Phase Change Problems.
Chapter 17 Thermochemistry 17.3 Heat in Changes of State
Quantitative Thermochemistry
Look at the graph below and identify the following: Is this endothermic or exothermic? Activation energy? Enthalpy of the reactants? Enthalpy of the products?
Do now Turn in Chillin’ Out lab.
Section 7.3—Changes in State
Heat Exchange During Physical Changes
Warm-up #2 Who do you agree with and why?
Do Now & Announcements Work on Phase diagram practice
Multi-step Problems.
Bellwork Wednesday Determine if the following are endothermic or exothermic. H = kJ/mol H = kJ/mol H = kJ/mol H = kJ/mol.
Physics Montwood High School R. Casao
Phase Changes, Heat of Fusion, and Heat of Vaporization
Heating & Cooling Curves
Do Now & Announcements Work on Phase diagram practice
Chapter 17 Thermochemistry.
Calculating Energy Changes at Phase Changes
Heating Curve H = Cice x T x mass Hfusion= 6.02 kJ/mol x mass
HEATING CURVES.
A. Phase Changes Sublimation solid  gas
Warm Up #2 In an endothermic reaction, if 350 J of heat is absorbed, how much heat is lost by the surroundings? How do you know? If the final temperature.
Changes of State units: J/g Heat of Vaporization
Bellwork 3/6/18 What is energy? What units can energy be measured in?
Heating Curves and Phase Diagrams
Warm Up # 4 When the temperature for 45.0 grams of water decreases from 90.5oC to 7.0oC, how much energy is lost, in kilojoules? The specific heat of.
Chapter 10 Properties of Solids and Liquids
Section 5 Water Chapter 10 Ice and Water.
2.3 Thermal Energy Transfer In The Hydrosphere.
Heat in Changes of State
Calculating Energy Changes at Phase Changes
Heating curves and DH temperature added energy.
Calculating Energy Changes at Phase Changes
Latent Heat and Phase Changes
Heat in Changes of State and Calculating Heat of Reaction
Warm Up: Get out Reaction Diagram Paper
Calculating Energy Changes at Phase Changes
States of Matter & Energy
Unit 10: Thermodynamics.
11.5 – NOTES Heat of Combustion and Phase Changes
Quick Review What is energy? How is it measured?
Do Now: Just to review before we start…
Matter and Energy.
Heating Curves and Enthalpy
Calculating Energy Changes at Phase Changes
Quick Review What is energy? How is it measured?
Heating Curve H = Cice x T x mass Hfusion= 6.02 kJ/mol x mass
Presentation transcript:

Professor Dave problem from yesterday Do this problem as Today’s bellwork How much energy in joules is required to heat 35.3g of water from - 20C to 115C? ∆Hfus = 334 J/g ∆Hvap = 2260 J/g Cpice = 2.06 J/gC Cpwater = 4.184 J/gC Cpsteam = 2.02 J/gC Remember to split this problem into 5 pieces and add up the answers: Q for ice from -20->0 Melt ice Q for water from 0->100 Boil Water Q for steam from 100-115

Example H2O (s)  H2O (l) ∆Hfus = 333 J/g How much energy is needed to melt 10.5 g of ice? H2O (s)  H2O (l) ∆Hfus = 333 J/g

Example #2 How much energy is needed to condense 2.5 g of H2O? ∆Hvap = 2260 J/g

Heating Curves Shows how the temperature of a substance changes as heat is added.

Super Awesome Sample Problem How much heat is required to change 36 g of H2O from -8 deg C to 120 deg C? Step 1: Heat the ice (Cice = 2.06 J/gC) Q=mcΔT Q = 36 g x 2.06 J/g deg C x 8 deg C = 593.28 J = 0.59 kJ Step 2: Convert the solid to liquid ΔH fusion Q = 2.0 mol x 6.01 kJ/mol = 12 kJ Step 3: Heat the liquid (CH2O = 4.184 J/gC) Q=mcΔT Q = 36g x 4.184 J/g deg C x 100 deg C = 15063 J = 15 kJ

Now, add all the steps together Super Awesome Sample Problem How much heat is required to change 36 g of H2O from -8 deg C to 120 deg C? Step 4: Convert the liquid to gas ΔH vaporization Q = 2.0 mol x 44.01 kJ/mol = 88 kJ Step 5: Heat the gas (Cgas = 2.02 J/gC) Q=mcΔT Q = 36 g x 2.02 J/g deg C x 20 deg C = 1454.4 J = 1.5 kJ Now, add all the steps together 0.59 kJ + 12 kJ + 15 kJ + 88 kJ + 1.5 kJ = 118 kJ

The laws of thermodynamics First Law of Thermodynamics: Energy cannot be created or destroyed, but converted from one form to another. Second Law of Thermodynamics: The universe favors an increase of disorder (entropy) Third Law of Thermodynamics: The entropy of a pure substance at 0 K is 0. More simply, as you approach 0K, you approach 0 entropy (disorder)

Two trends in Nature High energy  low energy Order  Disorder

Ssolid < Sliquid < S gas Entropy Entropy (S) is a measure of the randomness or disorder of a system. If disorder increases, entropy increases. If order increases, entropy decreases. For any substance, the solid state is more ordered than the liquid state, which is more ordered than the gas state. Ssolid < Sliquid < S gas H2O (s)  H2O (l) ∆S > 0