Parabolic Input: R(t) t (s) (Parabolic input error coefficient)

Slides:

Advertisements

Similar presentations

The Performance of Feedback Control Systems

Advertisements

Lect.7 Steady State Error Basil Hamed

Automatic control by Meiling CHEN

Review last lectures.

سیستمهای کنترل خطی پاییز 1389 بسم ا... الرحمن الرحيم دکتر حسين بلندي- دکتر سید مجید اسما عیل زاده.

Feedback Control Systems (FCS) Dr. Imtiaz Hussain URL :

Steady-State Analysis Date: 28 th August 2008 Prepared by: Megat Syahirul Amin bin Megat Ali

Chapter 5 Transient and Steady State Response “I will study and get ready and someday my chance will come” Abraham Lincoln.

o Problem Reconsider Problem

Modern Control System EKT 308

Remainder Theorem. The n-th Talor polynomial The polynomial is called the n-th Taylor polynomial for f about c.

Lecture 17: Introduction to Control (part III)

Modern Control System EKT 308 Root Locus and PID controllers.

Vector Valued Functions

Modern Control System EKT 308 Steady-State and Stability.

Discrete Controller Design

1 Time Response. CHAPTER Poles and Zeros and System Response. Figure 3.1: (a) System showing input and output; (b) Pole-zero plot of the system;

2.1 Step Input Response: Eigenvalues: p 1 =-4.526, p 2,3 = ±2.7883i, p 4 = Final value theorem: Stability: If the step response reaches to.

Chapter 7 Steady State Error <<<4.1>>>

Automatic Control Theory School of Automation NWPU Teaching Group of Automatic Control Theory.

1 Steady-State Error M. Sami Fadali Professor of Electrical Engineering University of Nevada.

Dynamic Response Steady State Response: the part of response when t → ∞ Transient response: the part of response right after the input is being applied.

TUTORIAL EKT 308 Computer Network. Question 1 1. a) Differentiate between open loop and closed loop control systems. b) Explain positive features of feedback.

Intelligent Robot Lab Pusan National University Intelligent Robot Lab Chapter 7. Forced Response Errors Pusan National University Intelligent Robot Laboratory.

ABE425 Engineering Measurement Systems ABE425 Engineering Measurement Systems PID Control Dr. Tony E. Grift Dept. of Agricultural & Biological Engineering.

Exercise 1 Suppose we have a simple mass, spring, and damper problem. Find The modeling equation of this system (F input, x output). The transfer function.

CHAPTER III LAPLACE TRANSFORM

Control Systems EE 4314 Lecture 12 March 17, 2015

Chapter 7 The Root Locus Method The root-locus method is a powerful tool for designing and analyzing feedback control systems The Root Locus Concept The.

Transient & Steady State Response Analysis

DNT Control Principle Steady-State Analysis DNT Control Principle.

A First Analysis of Feedback

Control Systems (CS) Lecture-12-13

x points: -7, -4+3i HW 5 Problem:05-01

Feedback Control Systems (FCS)

Time Domain analysis STEADY-STATE ERROR.

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. {image}

LINEAR CONTROL SYSTEMS

Basic Design of PID Controller

Feedback Control Systems (FCS)

Observer Design.

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. {image}

Steady-State Errors System & Control Engineering Lab.

Eigenvalues: p1=-4.526, p2,3= ±2.7883i, p4=

Eigenvalues: p1=-4.526, p2,3= ±2.7883i, p4=

Time Response System & Control Engineering Lab.

HOMEWORK-04 Problem In a closed loop control system shown in the figure, the process transfer function is Gp(s)=(2s+3)/(s3+6s2-28s) and Gc=K. a)

HW-03 Problem Kuo-95 (p. 377) Find the steady-state errors for step, ramp and parabolic inputs. Determine the type of the system. ) s ( R Problem.

UNIVERSITI MALAYSIA PERLIS SCHOOL OF ELECTRICAL SYSTEM ENGINEERING

Control Systems (CS) Lecture-6 Steady State Error Dr. Imtiaz Hussain

Dynamic Response Unit step signal:

E(s): Laplace transform of the error e(t)

The characteristics of actual input signals are a sudden shock, a sudden change, a constant velocity, and constant acceleration. The dynamic behavior of.

Control Systems (CS) Lecture-6 Steady State Error

Control Systems (CS) Lecture-16 Steady State Error Dr. Imtiaz Hussain

Notes Over 6.6 Possible Zeros Factors of the constant

Performance of Second Order Systems

o Problem Reconsider Problem

Eigenvalues: p1=-4.526, p2,3= ±2.7883i, p4=

B.Tech – II – ECE – II SEMESTER ACE ENGINEERING COLLEGE

2a. Transfer function of closed loop system

HOMEWORK-03 Problem Kuo-95 (p. 377)

3. Steady State Error and Time Response Performance

Types of Errors And Error Analysis.

Chapter 5 – The Performance of Feedback Control Systems

Time Response, Stability, and

Exercise 1 For the unit step response shown in the following figure, find the transfer function of the system. Also find rise time and settling time. Solution.

Chapter 5 The Performance of Feedback Control Systems

By: Nafees Ahamad, AP, EECE, Dept. DIT University, Dehradun

Presentation transcript:

Parabolic Input: R(t) t (s) (Parabolic input error coefficient)

3. Steady State Error and Time Response Performance ) s ( R Final Value Theorem: Parabolic input Step input Ramp input

Example 3.1 a) ) s ( R System type: 0 Stability test Final value theorem: Step Ramp Parabolic ess: Step Ramp Parabolic [cn]ss: Step Ramp Parabolic System type: 0 Stability test

Integral control improves the steady state error performance Example 3.1 b) ) s ( R ess: Step Ramp Parabolic System type: 1 Integral control improves the steady state error performance ess: Step Ramp Parabolic System type : 0 Derivative control does not change the error performance

Example 3.1 d) ) s ( R System type: 2 DcDp  s0 System type: 0 ess: Step Ramp Parabolic System type: 2 DcDp  s0 System type: 0 Overshoot DcDp  s1 System type: 1 DcDp  s2 System type: 2 DcDp  s3 System type: 3