Find the next term in each sequence.

Slides:



Advertisements
Similar presentations
Warm Up Lesson Presentation Lesson Quiz
Advertisements

Geometric Sequences and Series
SOLUTION EXAMPLE 1 A linear system with no solution Show that the linear system has no solution. 3x + 2y = 10 Equation 1 3x + 2y = 2 Equation 2 Graph the.
Determine whether the sequence 6, 18, 54, is geometric. If it is geometric, find the common ratio. Choose the answer from the following :
EXAMPLE 1 Identify arithmetic sequences
EXAMPLE 3 Write an equation for a function
EXAMPLE 4 Classify and write rules for functions SOLUTION The graph represents exponential growth (y = ab x where b > 1). The y- intercept is 10, so a.
7.2 Analyze Arithmetic Sequences & Series
Notes Over 11.3 Geometric Sequences
7.3 Analyze Geometric Sequences & Series
EXAMPLE 2 Write a rule for the nth term Write a rule for the nth term of the sequence. Then find a 7. a. 4, 20, 100, 500,... b. 152, –76, 38, –19,... SOLUTION.
A sequence is geometric if the ratios of consecutive terms are the same. That means if each term is found by multiplying the preceding term by the same.
EXAMPLE 4 Solve a multi-step problem CYCLING
Write and graph a direct variation equation
EXAMPLE 2 Write a rule for the nth term a. 4, 9, 14, 19,... b. 60, 52, 44, 36,... SOLUTION The sequence is arithmetic with first term a 1 = 4 and common.
10.8 Warm Up Warm Up Lesson Presentation Lesson Presentation Compare Linear, Exponential, and Quadratic Models.
12.2 – Analyze Arithmetic Sequences and Series. Arithmetic Sequence: The difference of consecutive terms is constant Common Difference: d, the difference.
Wednesday, March 7 How can we use arithmetic sequences and series?
12.2: Analyze Arithmetic Sequences and Series HW: p (4, 10, 12, 14, 24, 26, 30, 34)
Geometric Sequences and Series
SOLUTION EXAMPLE 4 Graph an equation in two variables Graph the equation y = – 2x – 1. STEP 1 Construct a table of values. x–2–1 012 y31 –3–5.
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
+ Geometric Sequences & Series EQ: How do we analyze geometric sequences & series? M2S Unit 5a: Day 9.
Standard 22 Identify arithmetic sequences Tell whether the sequence is arithmetic. a. –4, 1, 6, 11, 16,... b. 3, 5, 9, 15, 23,... SOLUTION Find the differences.
Notes Over 11.2 Arithmetic Sequences An arithmetic sequence has a common difference between consecutive terms. The sum of the first n terms of an arithmetic.
8.3 Geometric Sequences and Series Objectives: -Students will recognize, write, and find the nth terms of geometric sequences. -Students will find the.
EXAMPLE 1 Find a positive slope Let (x 1, y 1 ) = (–4, 2) = (x 2, y 2 ) = (2, 6). m = y 2 – y 1 x 2 – x 1 6 – 2 2 – (–4) = = = Simplify. Substitute.
EXAMPLE 5 Find the sum of a geometric series Find the sum of the geometric series 16 i = 1 4(3) i – 1. a 1 = 4(3) 1– 1 = 4 r = 3 = 4 1– – 3 ( )
12.2, 12.3: Analyze Arithmetic and Geometric Sequences HW: p (4, 10, 12, 18, 24, 36, 50) p (12, 16, 24, 28, 36, 42, 60)
Thursday, March 8 How can we use geometric sequences and series?
9.3 Geometric Sequences and Series. 9.3 Geometric Sequences A sequence is geometric if the ratios of consecutive terms are the same. This common ratio.
11.3 Geometric Sequences & Series. What is a geometric sequence? What is the rule for a geometric sequence? How do you find the nth term given 2 terms?
12.3 – Analyze Geometric Sequences and Series. Geometric Sequence: Ratio of any term to the previous term is constant Common Ratio: Ratio each term is.
Geometric Sequence Sequences and Series. Geometric Sequence A sequence is geometric if the ratios of consecutive terms are the same. 2, 8, 32, 128, 512,...
Geometric Sequences. Warm Up What do all of the following sequences have in common? 1. 2, 4, 8, 16, …… 2. 1, -3, 9, -27, … , 6, 3, 1.5, …..
9.3 Geometric Sequences and Series. Common Ratio In the sequence 2, 10, 50, 250, 1250, ….. Find the common ratio.
EXAMPLE 1 Evaluate recursive rules Write the first six terms of the sequence. a. a 0 = 1, a n = a n – b. a 1 = 1, a n = 3a n – 1 SOLUTION a. a 0.
Warm-up: Page 238 #47 and #48 Homework: Page 245 #3-28 all
11.3 Geometric Sequences & Series
Homework Check.
Sequences and Series IB standard
11.3 Geometric Sequences & Series
The sum of the first n terms of an arithmetic series is:
Geometric Sequences and Series
AKS 67 Analyze Arithmetic & Geometric Sequences
Objectives Find terms of a geometric sequence, including geometric means. Find the sums of geometric series.
1.7 - Geometric sequences and series, and their
Unit 1 Test #3 Study Guide.
1. Evaluate ANSWER Evaluate –2 ANSWER 16.
Geometric Sequence The ratio of a term to it’s previous term is constant. This means you multiply by the same number to get each term. This number that.
12.3 Geometric Sequences & Series
9-3 Geometric Sequences & Series
Geometric sequences.
Homework Check.
Warm up.
Objectives Find the indicated terms of an arithmetic sequence.
Geometric sequences.
Write the percent as a decimal.
Homework Check.
Warm up 1. One term of a geometric sequence is a5 = 48. The common ratio is r = 2. Write a rule for the nth term. 2. Find the sum of the geometric.
Solving for x and y when you have two equations
8.3 Analyzing Geometric Sequences and Series
Warm-Up Write the first five terms of an = 4n + 2 a1 = 4(1) + 2
Geometric Sequence The ratio of a term to it’s previous term is constant. This means you multiply by the same number to get each term. This number that.
Geometric Sequences and Series
9.3 Geometric Sequences & Series
Unit 3: Linear and Exponential Functions
Geometric Sequences and series
Geometric Sequence Skill 38.
Presentation transcript:

Find the next term in each sequence. 1. 3, 6, 9, 12, … ANSWER 15 2. 0.25, 0.50, 1, 2, … ANSWER 4

3. A high school graduated 250 seniors in 2004. In 2005 the number of graduating seniors increased by 4%. How many seniors graduated in 2005? ANSWER 260 seniors

EXAMPLE 1 Identify geometric sequences Tell whether the sequence is geometric. a. 4, 10, 18, 28, 40, . . . b. 625, 125, 25, 5, 1, . . . SOLUTION To decide whether a sequence is geometric, find the ratios of consecutive terms. 5 2 a2 a1 = 10 4 a. a3 a2 = 18 10 9 5 a4 a3 = 28 18 14 9 a5 a4 = 40 28 10 7 ANSWER The ratios are different, so the sequence is not geometric.

EXAMPLE 1 Identify geometric sequences a2 a1 = 125 625 1 5 b. 1 5 a3 a2 = 25 125 a4 a3 = 5 25 1 a5 a4 = 1 5 ANSWER Each ratio is , so the sequence is geometric. 1 5

GUIDED PRACTICE for Example 1 Tell whether the sequence is geometric. Explain why or why not. 1. 81, 27, 9, 3, 1, . . . Each ratio is , so the sequence is geometric. 1 3 ANSWER 2. 1, 2, 6, 24, 120, . . . ANSWER The ratios are different. The sequence is not geometric.

GUIDED PRACTICE for Example 1 Tell whether the sequence is geometric. Explain why or why not. 3. – 4, 8, – 16, 32, – 64, . . . ANSWER Each ratio is . So the sequence is geometric. – 2

Write a rule for the nth term EXAMPLE 2 Write a rule for the nth term Write a rule for the nth term of the sequence. Then find a7. a. 4, 20, 100, 500, . . . b. 152, – 76, 38, – 19, . . . SOLUTION The sequence is geometric with first term a1 = 4 and common ratio a. r = 20 4 = 5. So, a rule for the nth term is: an = a1 r n – 1 Write general rule. = 4(5)n – 1 Substitute 4 for a1 and 5 for r. The 7th term is a7 = 4(5)7 – 1 = 62,500.

( ) ( ) EXAMPLE 2 Write a rule for the nth term The sequence is geometric with first term a1 = 152 and common ratio b. r = –76 152 = – 1 2 .So, a rule for the nth term is: an = a1 r n – 1 Write general rule. = 152 ( ) 1 2 – n – 1 Substitute 152 for a1 and for r. 1 2 – ( ) 7 – 1 The 7th term is a7 = 152 1 2 – 19 8 =

Write a rule given a term and common ratio EXAMPLE 3 Write a rule given a term and common ratio One term of a geometric sequence is a4 =12. The common ratio is r = 2. a. Write a rule for the nth term. b. Graph the sequence. SOLUTION a. Use the general rule to find the first term. an = a1r n – 1 Write general rule. a4 = a1r 4 – 1 Substitute 4 for n. 12 = a1(2)3 Substitute 12 for a4 and 2 for r. 1.5 = a1 Solve for a1.

Write a rule given a term and common ratio EXAMPLE 3 Write a rule given a term and common ratio So, a rule for the nth term is: an = a1r n – 1 Write general rule. = 1.5(2) n – 1 Substitute 1.5 for a1 and 2 for r. Create a table of values for the sequence. The graph of the first 6 terms of the sequence is shown. Notice that the points lie on an exponential curve. This is true for any geometric sequence with r > 0. b.

Write a rule given two terms EXAMPLE 4 Write a rule given two terms Two terms of a geometric sequence are a3 = −48 and a6 = 3072. Find a rule for the nth term. SOLUTION Write a system of equations using an = a1r n – 1 and substituting 3 for n (Equation 1) and then 6 for n (Equation 2). STEP 1 a3 = a1r 3 – 1 – 48 = a1 r 2 Equation 1 a6 = a1r 6 – 1 3072 = a1r 5 Equation 2

Write a rule given two terms EXAMPLE 4 Write a rule given two terms STEP 2 Solve the system. – 48 r2 = a1 Solve Equation 1 for a1. 3072 = – 48 r2 (r5 ) Substitute for a1 in Equation 2. 3072 = – 48r3 Simplify. –4 = r Solve for r. – 48 = a1(– 4)2 Substitute for r in Equation 1. – 3 = a1 Solve for a1. STEP 3 an = a1r n – 1 Write general rule. an = – 3(– 4)n – 1 Substitute for a1 and r.

( ) GUIDED PRACTICE for Examples 2, 3 and 4 Write a rule for the nth term of the geometric sequence. Then find a8. 4. 3, 15, 75, 375, . . . ANSWER an = 3( 5 )n – 1; 234,375 5. a6 = – 96, r = 2 ANSWER an = – 3 (2)n – 1; – 384 6. a2 = – 12, a4 = – 3 ( ) ANSWER an = ; – 0.1875 1 2 n-1

( ) ( ) EXAMPLE 5 Find the sum of a geometric series Find the sum of the geometric series 16 i = 1 4(3)i – 1. a1 = 4(3)1– 1 = 4 Identify first term. r = 3 Identify common ratio. S16 = a1 1– r16 1 – r ( ) Write rule for S16. = 4 1– 316 1 – 3 ( ) Substitute 4 for a1 and 3 for r. = 86,093,440 Simplify. ANSWER The sum of the series is 86,093,440.

EXAMPLE 6 Use a geometric sequence and series in real life Movie Revenue In 1990, the total box office revenue at U.S. movie theaters was about $5.02 billion. From 1990 through 2003, the total box office revenue increased by about 5.9% per year. Write a rule for the total box office revenue an (in billions of dollars) in terms of the year. Let n = 1 represent 1990. a. What was the total box office revenue at U.S. movie theaters for the entire period 1990–2003? b.

( ) ( ) EXAMPLE 6 Use a geometric sequence and series in real life SOLUTION Because the total box office revenue increased by the same percent each year, the total revenues from year to year form a geometric sequence. Use a1 = 5.02 and r = 1 + 0.059 = 1.059 to write a rule for the sequence. a. an = 5.02(1.059)n – 1 Write a rule for an. There are 14 years in the period 1990–2003, so find S14. b. = 5.02 1– (1.059)14 1 – 1.059 ( ) 1 – r14 1 – r ( ) S14 = a1 105 ANSWER The total movie box office revenue for the period 1990–2003 was about $105 billion.

7. Find the sum of the geometric series 6( – 2)i–1. GUIDED PRACTICE for Examples 5 and 6 8 i – 1 7. Find the sum of the geometric series 6( – 2)i–1. – 510 ANSWER

GUIDED PRACTICE for Examples 5 and 6 8. MOVIE REVENUE Use the rule in part (a) of Example 6 to estimate the total box office revenue at U.S. movie theaters in 2000. ANSWER about $8.91 billion

Daily Homework Quiz 1. Tell whether the sequence 5, 10, 20, 40, . . . is geometric. If so, write a rule for the nth term of the sequence and find a6. ANSWER Yes; an = 5(2)n – 1; a6 = 160 2. One term of a geometric sequence is a5 = 48. The common ratio is r = 2. Write a rule for the nth term. ANSWER an = 3(2)n – 1

Daily Homework Quiz 3. Two terms of a geometric sequence are a2 = –2000 and a5 = 16,000,000. Find a rule for the nth term. ANSWER an = 100 (–20)n – 1 4. Find the sum of the geometric series 5(3)i – 1. ∑ i = 1 5 605 ANSWER