Amount of heat transferred = mass x change in temperature x specific heat q = m(∆T)Cp.

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Presentation transcript:

amount of heat transferred = mass x change in temperature x specific heat q = m(∆T)Cp

Can you picture a piece of aluminum foil that is taken out of an oven. Example: Aluminum has a specific heat of 0.902 J/g x oC. How much heat is lost when a piece of aluminum with a mass of 23.984 g cools from a temperature of 415.0 oC to a temperature of 22.0 oC? Step 1: First read the question and try to understand what they are asking you. Can you picture a piece of aluminum foil that is taken out of an oven. Imagine the aluminum losing heat to its surroundings until the temperature goes from 415.0 oC to 22.0 oC.

Step 2: Write the original formula.

Step 3: List the known and unknown factors Step 3: List the known and unknown factors. Looking at the units in the word problem will help you determine which is which. q = ? m = 23.984 g ∆T = (415.0 oC - 22.0 oC) = 393.0 oC (remember, they asked for the change in temperature) Cp = 0.902 J/g x oC

Step 4. Substitute your values into the formula q = ? m = 23.984 g DT = (415.0 oC - 22.0 oC) = 393.0 oC Cp = 0.902 J/g x oC