Temperatures must be in Kelvin! ANIMATION Charles’ Law There is a direct relationship between the temperature and volume of a gas (if one increases so does the other) If pressure is held constant: V1 = V2 T1 T2 Temperatures must be in Kelvin! KMT – as the temperature decreases the particles move slower causing less collisions; the volume will decrease

Example 5.00 L of a gas is collected at 100 K and then allowed to expand to 20.0 L. What must the new temperature be in order to maintain the same pressure (as required by Charles' Law)? V1 = V2 T1 = T2 V1 = T1 = V2 = T2 = 5.00L 100K 20.0L 5.00L = 20.0L 100K T T = 400K ?

Example A gas has an initial volume of 15 L. If the temperature increases from 330 ºC to 450 ºC find the new volume. V1 = V2 T1 T2 V1 = T1 = V2 = T2 = 15L 330C + 273 = 603K ? 15L = V 603K 723K V = 18 L 450C + 273 = 723K

A quantity of gas has a volume of 254 mL at 27ºC A quantity of gas has a volume of 254 mL at 27ºC. When the temperature becomes 17ºC at constant pressure the gas has a volume of iRespond Question Multiple Choice F V = V T T 254mL = V 300K 290K A.) 263 mL B.) 246 mL C.) 299 mL D.) 160 mL E.)

F Multiple Choice iRespond Question If the temperature on a given mass of gas in a closed system is increased and the volume remains constant, the pressure of the gas will A.) decrease B.) increase C.) remain the same D.) E.)