Energy = m x c x θ Energy = 5 x 300 x 10 Energy = 15,000 J speed = wavelength frequency Energy = 5 x 300 x 10 6.0 = 6.0 m 1.0 Energy = 15,000 J
Energy = m x c x θ Energy = 5 x 300 x 10 Energy = 15,000 J speed = wavelength frequency Energy = 5 x 300 x 10 6.0 = 6.0 m 1.0 Energy = 15,000 J
Energy = m x c x θ 2000 = 1 x c x 1 c = 2000 J/kgC E = m x c x θ E = 2 x 2000 x 10 E = 40,000 J
Energy = m x c x θ 2000 = 1 x c x 1 c = 2000 J/kgC E = m x c x θ E = 2 x 2000 x 10 E = 40,000 J
Energy = m x c x θ E = 2 x 440 x 100 E = 88,000 J Energy = POWER X TIME 5a. Energy = 2000 W X 10 s = 20,000 J 5b. Energy = 2000 W X 60s = 120,000 J
Energy = m x c x θ E = 2 x 440 x 100 E = 88,000 J Energy = POWER X TIME 5a. Energy = 2000 W X 10 s = 20,000 J 5b. Energy = 2000 W X 60s = 120,000 J
6a. Energy = POWER X TIME Energy = 50 W X 120 s = 6,000 J 6b. E = m x c x θ 6,000 = 1 x c x 1 c = 6000 J/kgC
6a. Energy = POWER X TIME Energy = 50 W X 120 s = 6,000 J 6b. E = m x c x θ 6,000 = 1 x c x 1 c = 6000 J/kgC
7. E /min = m x c x θ/min E /min = 0.5 x 4200 x 30 E /min = 63,000 J /min Power = Joules / sec or Watts ! Power = 63,000 J /min so divide by 60 to get J/sec Power = 1050 J /sec = about 1 kW
7. E /min = m x c x θ/min E /min = 0.5 x 4200 x 30 E /min = 63,000 J /min Power = Joules / sec or Watts ! Power = 63,000 J /min so divide by 60 to get J/sec Power = 1050 J /sec = about 1 kW
The jam will have a higher specific heat capacity and take a longer time to cool down than the pastry pudding part.
The jam will have a higher specific heat capacity and take a longer time to cool down than the pastry pudding part.
Heat lost by hot water cooling = heat gained by cold water warming mh x c x θh = mc x c x θc 60 x c x ( 80-50 ) = mc x c x ( 50 -10 ) 60 x c x ( 30 ) = mc x c x ( 40 ) 1800 = mc x 40 45 kg = mc
Heat lost by hot water cooling = heat gained by cold water warming mh x c x θh = mc x c x θc 60 x c x ( 80-50 ) = mc x c x ( 50 -10 ) 60 x c x ( 30 ) = mc x c x ( 40 ) 1800 = mc x 40 45 kg = mc