Polygons Mixed Exercise

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Presentation transcript:

Polygons Mixed Exercise Pg 132 – 133 Exercise 6h No. 1 to No. 6

1. Find the size of each marked Angle Sum of exterior angles = 360° 110°+ 130°= 240° m = 360°- 240°= 120° 2 p = 180°- 120°= 60° 1

Sum of exterior angles = 360° One interior angle = 180°- 30°= 150° 2. Find the size of each exterior angle of a regular polygon with 12 sides. What is the size of each interior angle? Sum of exterior angles = 360° 360°÷ 12 = 30° 1 Interior + Exterior = 180° One interior angle = 180°- 30°= 150° 1

3. Find the size of the angle marked x° Sum of interior angles = (5-2) x 180° Sum of interior angles = 3 x 180°= 540° 1 90°+ 130° + 120° + 80° = 420° x = 540°- 420°= 120° 2 Pentagon  5 sides

One exterior angle = 180° - 168°= 12° 4. How many sides has a regular polygon if each interior angle is 168°? Interior + Exterior = 180° One exterior angle = 180° - 168°= 12° 1 12°x n = 360°?? n = 360° ÷ 12° = 30 SIDES! 2

n = 360° ÷ 45°= 8 SIDES (OCTAGON) 5. Is it possible for each exterior angle in a regular polygon to be a) 45° b)75° a) 45° x n = 360°??? n = 360° ÷ 45°= 8 SIDES (OCTAGON) 2 b) 75° x n = 360°??? n = 360° ÷ 75°= 4.8 (not possible!) 2

6. Find the size of the marked angle Sum of interior angles = (4-2) x 180° Sum of interior angles = 2 x 180°= 360° 1 120° + 80°+ 80° = 280° 360°- 280°= 80° 2 Quadrilateral  4 sides X = 180° – 80° = 100° 1 1 Mark for your presentation of working: Is it good? (1), Is it okay but could be better (0.5), Do you think you could have done much better? (0)

Polygons Plenary Quiz