9.6: Solving Polynomials when a > 1 Do NOW Factor the following: 3x2 + 13x – 10 6x2 + 25x + 25 3) Identify the factor of the tiles: 12/8/2018 1:10 PM 9.6: Solving Polynomials when a > 1

9.6: Solving Polynomials when a > 1 Worksheet Key 12/8/2018 1:10 PM 9.6: Solving Polynomials when a > 1

9.6: Solving Polynomials when a > 1 Worksheet Key 12/8/2018 1:10 PM 9.6: Solving Polynomials when a > 1

Use Square Roots to Solve Quadratic Functions Section 10.4 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Steps The opposite of a squared number is taking the SQUARE ROOT. The opposite of a square root is taking the SQUARING THE NUMBER. Given, x2 = d If d > 0, it will have TWO solutions, usually with a PLUS/MINUS (+) sign involved in the answer If d = 0, it will have ONE solution If d < 0, it will have NO solution 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

What gets rid of the squared? 6.6 - Solving Radical Equations Example 1 Solve x2 = 4 What gets rid of the squared? 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

Example 1 – Calculator Check 6.6 - Solving Radical Equations Solve x2 = 4 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 2 Solve 2x2 = 8 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Your Turn Solve 3x2 = 27 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 3 Solve x2 – 18 = –18 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

Example 3 – Calculator Check 6.6 - Solving Radical Equations Solve x2 – 18 = –18 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 4 Solve x2 + 12 = 5 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

Example 4 – Calculator Check 6.6 - Solving Radical Equations Solve x2 + 12 = 5 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 5 Solve 4x2 = 9 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 6 Solve 25x2 + 11 = 15 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Your Turn Solve 4x2 + 10 = 11 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 7 Solve 3x2 – 11 = 7 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 8 Solve 2x2 – 7 = 2 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Your Turn Solve x2 + 4 = 14 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 10 The speed s in miles per hour that a car is traveling when it goes into a skid can be estimated by using the formula s = where f is the coefficient of friction and d is the length of the skid marks in feet. 30 fd A car skids to a stop on a street with a speed limit of 30 mi/h. The skid marks measure 35 ft, and the coefficient of friction was 0.7. Was the car speeding? Explain. Substitute 30 for s and 0.7 for f. Simplify. 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Example 10 The speed s in miles per hour that a car is traveling when it goes into a skid can be estimated by using the formula s = where f is the coefficient of friction and d is the length of the skid marks in feet. A car skids to a stop on a street with a speed limit of 30 mi/h. The skid marks measure 35 ft, and the coefficient of friction was 0.7. Was the car speeding? Explain. 30 fd Substitute 30 for s and 0.7 for f. Simplify. Square both sides. 900 = 21d Simplify. 43 ≈ d Solve for d. If the car were traveling 30 mi/h, its skid marks would have measured about 43 ft. Because the actual skid marks measure less than 43 ft, the car was not speeding. 12/8/2018 1:10 PM 6.6 - Solving Radical Equations

6.6 - Solving Radical Equations Assignment Worksheet 12/8/2018 1:10 PM 6.6 - Solving Radical Equations