Section 5.3 Use Angle Bisectors of Triangles

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5.3 Bisectors of a Triangle
Bisectors in Triangles
Medians, Altitudes, & Perpendicular Bisectors
5.2 Bisectors of a Triangle
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Presentation transcript:

Section 5.3 Use Angle Bisectors of Triangles Remember that an angle bisector is a ______ that divides an angle into two ____________ __________ angles. Remember also that the distance from a point to a line is the length of the ______________ ________ from the point to the line. In the diagram, ray congruent adjacent perpendicular segment

Section 5.3 Use Angle Bisectors of Triangles Theorem Theorem 5.5: Angle Bisector Theorem If a point is on the angle bisector, then it is equidistant from the sides of the angle.

Angle Bisector Theorem Section 5.3 Use Angle Bisectors of Triangles Theorem Theorem 5.6: Converse of the Angle Bisector Theorem If a point is equidistant from the sides of an angle, then it lies on the angle bisector.

EXAMPLE 1 Use the Angle Bisector Theorems Find the measure of GFJ. FJ bisects GFH, so mGFJ = mHFJ mGFJ = 42°

EXAMPLE 2 Solve a real-world problem SOCCER A soccer goalie’s position relative to the ball and goalposts forms congruent angles, as shown. Will the goalie have to move farther to block a shot toward the right goalpost R or the left goalpost L?

EXAMPLE 2 Solve a real-world problem SOLUTION No. The goalie is standing on the angle bisector and must move the same distance to block either shot.

Use algebra to solve a problem EXAMPLE 3 Use algebra to solve a problem ALGEBRA For what value of x does P lie on the bisector of A? SOLUTION If P is on the  bisector , then P is equidistant from the sides of A, so BP = CP. BP = CP Set segment lengths equal. x + 3 = 2x –1 Substitute expressions for segment lengths. 4 = x Solve for x. Point P is on the bisector of A when x = 4.

GUIDED PRACTICE for Examples 1, 2, and 3 In Exercises 1–3, find the value of x. 1. x = 15 Two angles are , so the two (blue) segments are  .

GUIDED PRACTICE for Examples 1, 2, and 3 In Exercises 1–3, find the value of x. 2. Two segments are , so the two s are . 4x – 6 = 3x + 5 x = 11

GUIDED PRACTICE for Examples 1, 2, and 3 In Exercises 1–3, find the value of x. 3. Two angles are , so the two segments are . 6x – 5 = 5x x = 5

GUIDED PRACTICE for Examples 1, 2, and 3 4. Do you have enough information to conclude that QS bisects PQR? Explain. No; SR and SP must be  to the sides of the .

Angle Bisectors of a Triangle Section 5.3 Use Angle Bisectors of Triangles Theorem Theorem 5.7: Concurrency of Angle Bisectors of a Triangle The angle bisectors of a triangle intersect at a point that is equidistant from the sides.

Section 5.3 Use Angle Bisectors of Triangles The point of concurrency of the three angle bisectors of a triangle is called the ___________. The incenter of a triangle always lies ___________ the triangle. Because the incenter is equidistant from the ______ of the triangle, a _______ can be drawn inside the triangle. This circle is said to be __________. incenter inside sides circle inscribed

Use the concurrency of angle bisectors EXAMPLE 4 Use the concurrency of angle bisectors In the diagram, N is the incenter of ABC. Find ND. By Theorem 5.7, Concurrency of Angle Bisectors, the incenter N is equidistant from the sides of ABC. NF = ND. Use the Pythagorean Theorem to find ND. c = 2 a + b Pythagorean Theorem NF + 16 2 20 = Substitute 400 = NF + 256 2 Multiply 144 = NF 2 Subtract 256 12 = NF Square root each side Because NF = ND, ND = 12.

GUIDED PRACTICE for Example 4 5. WHAT IF? In Example 4, suppose you are not given AF or AN, but you are given that BF = 12 and BN = 13. Find ND. NF + 12 2 13 = 169 = NF + 144 2 25 = NF 2 5 = NF NF = ND, so ND = 5