Find the Next Term in an Integer Sequence

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Find the Next Term in an Integer Sequence 1 2 3 4 __ 2 4 8 16 __ 1 2 2 3 3 3 4 4 __ 1 3 5 7 9 __ 3 7 11 __ 10 15 19 22 24 __ 1 1 2 3 5 8 13 __ 1 4 9 16 __ 1 3 6 10 15 21 28 __ For the last sequence, use OEIS to reveal that the nth term is the largest number that can be created by stacking (in exponential form) a set of numbers that add to n. For example, the fifth term is 3^2, the sixth term is 3^3, the seventh term is 2^3^2, the eighth term is 2^3^3 = 134,217,728. For n >= 7, the nth term is f(n) = 2^f(n – 2). 0 1 2 … 8 0 1 2 __ 1 2 3 4 9 27 512 __ [OEIS] Online Encyclopedia of Integer Sequences: http://oeis.org/   Oct. 2018 Predicting the Future

Find Missing Term in an Arbitrary Sequence Z O T T F F __ J F M __ M J J 31 __ 31 30 31 30 31 31 30 A E F H I __ 3 3 5 4 4 3 5 __ 3 4 6 9 __ 18 24 1 3/2 __ 7/8 9/16 1 11 21 1211 111221 312211 __ Questions regarding the 1, 11, 21,1211,… series: Will the sequence always contain only the digits 1, 2, and 3? Is the length of the terms nondecreasing? In the last example, the first digit indicates round (1) or square (2) lens; the second digit, straight (1) or curved (2) bridge; the third digit, handles to the left (1) or to the right (2). So, the answer is 222. 221 111 212 122 ___   Oct. 2018 Predicting the Future

A Solution Method for Numerical Series Polynomial interpolation: You can pass a line through any two points, a hyperbola through any three points, a third-degree curve through any four points, and so on 4 8 12 20 16 1 2 3 4 __ 1 4 9 16 __ f(n) = an3 + bn2 + cn + d n = 1: a + b + c + d = 1 n = 2: 8a + 4b + 2c + d = 4 n = 3: 27a + 9b + 3c + d = 9 n = 4: 64a + 16b + 4c + d = 16 b = 1; a = c = d = 0; f(n) = n2 1 2 3 4 5 6 2 4 8 16 __   Oct. 2018 Predicting the Future

Polynomial Extrapolation Example This exponential series, when solved via polynomial extrapolation, yields a different answer! 2 4 8 16 __ f(n) = an3 + bn2 + cn + d n = 2: 8a + 4b + 2c + d = 4 n = 3: 27a + 9b + 3c + d = 8 n = 4: 64a + 16b + 4c + d = 16 a = 1/3; b = –1; c = 8/3; d = 0; f(n) = (1/3)n3 – n2 + (8/3)n f(5) = (1/3)125–25+(8/3)5 = 30 f(6) = (1/3)216–36+(8/3)6 = 52 f(30) = 8,180 230 = 1,073,741,824   Oct. 2018 Predicting the Future