CHEM 163 SI Upcoming Sessions: Wednesday, September 19th SI CANCELED Thursday, September 20th 5:10-6:00pm Gilman 2104

Agenda How was the Exam???? IMPORTANT Announcements Lecture Review Chapter 4 Practice Problems Agenda

IMPORTANT Announcements SI Exam 2 Review will be held by me on October 1st from 6:10- 8:00pm in Sukup 0022 Email me through the SI website if you have any questions I will have resources and session information posted on the SI website

I will be traveling with the Agronomy department to Australia from September 19th-September 30th

E = hc/lambda 1 J = 6.241509 x 1018 eV Constants Lambda = wavelength of electromagnetic radiation 1 J = 6.241509 x 1018 eV c = speed of light 3.00 x 108 m/s h = Planck’s constant 6.626 x 10-34 J*s E = energy of electromagnetic radiation E = hc/lambda Constants

Electron Shells 2n2 Principle quantum number (n) Each shell has a fixed maximum amount of electrons For main group elements the # of electrons in the valence shell is equal to the roman numeral group number Valence shell: outermost occupied shell of an atom

Lecture Review Write the ground-state electron configuration and indicate the number of valence electrons for: Al I Rb Ar Mg

Lecture Review Name each element and tell how many valence electrons it has: 1s22s22p63s23p2 [Ne]3s1 [Ar]4s23d104p3

1. Forming bonds releases energy and breaking bonds requires energy. TRUE 2. Longer wavelengths have lower frequency and lower energy. TRUE or FALSE

Periodic Table Trends Ionization Energy Electronegativity Metallic Character Atomic Size Periodic Table Trends

What is the wavelength, in nm, of the photon emitted when an electron relaxes from the n = 6 state to the n = 4 state in a hydrogen atom? c = 3.00 x 108 m/s E = hc/λ h = 6.626 x 10–34 J·s 1 J = 6.241509 x 1018 eV

Here is the step-by-step answer to the problem on the previous slide. Let me know if you have any questions about this or the Chapter 4 Practice Problems!