Bell Work September 23 – 27, 2013.

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Presentation transcript:

Bell Work September 23 – 27, 2013

Bell Work: September 23, 2013 Use the solutions below to correct #6-24 (even) from p.266 of the Holt textbook 6) 8 11 8) 2 3 5 10) 5 1 24 12) 13 1 8 14) 5 7 16) 13 14 18) 1 1 3 20) 1 1 20 22) 3 5 6 24) 14

Bell Work: September 24, 2013 Find the greatest common factor that will evenly divide both 14 and 70. Find the least common multiple for 10 and 11. Rename the following expressions using the distributive property 6(3+5) and 24 + 60 Solve. 12.852 ÷ 3.06 Solve. 𝟑 𝟏 𝟐 ×𝟒

Bell Work: September 24, 2013 (14,70) GCF = 14 2) (10,11) LCM = 110 6(3+5) 24 + 60 6(3) + 6(5) 12(2+5) 18 + 30 Solve. 12.852 ÷ 3.06 = 4.2 6) Solve. 𝟑 𝟏 𝟐 ×𝟒 = 𝟕 𝟐 × 𝟒 𝟏 = 𝟐𝟖 𝟐 = 14 0.8 [ 17.2 + 10 (13.5) ] = 121.73 meters 0.8 ( 17.2 + 135 ) = 0.8 (152.2) =

Bell Work: September 25, 2013 Find the greatest common factor that will evenly divide both 18 and 36. Find the least common multiple for 12 and 7. Rename the following expressions using the distributive property 3(2+9) and 42 + 24 Solve. 𝟑 𝟏 𝟐 ÷𝟒

Bell Work: September 25, 2013 (18,36) GCF = 18 2) (12,7) LCM = 84 3(2+9) 42 + 24 3(2) + 3(9) 6(7+4) 6 + 27 5) 6) Solve. 𝟑 𝟏 𝟐 ÷𝟒 = 𝟕 𝟐 ÷ 𝟒 𝟏 = 𝟕 𝟐 × 𝟏 𝟒 = 𝟕 𝟖 6 ÷ 0.8 = 7.5 laps 7.5 laps × 0.8 miles per lap = 6 miles 0.5 ÷ 0.03 = 16. 𝟔 ≈ 16.7 min 16.7 min × 0.03 L used per min ≈ 0.5 Liters