Chemical Formulas Subscripts represent relative numbers of elements present (Parentheses) separate complexes or substituted elements Fe(OH)3 – Fe bonded.

Slides:



Advertisements
Similar presentations
GOLDSCHMIDT’S RULES 1. The ions of one element can extensively replace those of another in ionic crystals if their radii differ by less than approximately.
Advertisements

Thermobarometry Lecture 12. We now have enough thermodynamics to put it to some real use: calculating the temperatures and pressures at which mineral.
Lecture 5 Crystal Chemistry Part 4: Compositional Variation of Minerals 1. Solid Solution 2. Mineral Formula Calculations.
Chapter 3.  Reactants are left of the arrow  Products are right of the arrow  The symbol  is placed above the arrow to indicate that the rxn is being.
Atoms are the smallest components of nature
How Many Molecules? Pyrite Cube weighs 778 g – how many molecules is that?? About 4,000,000,000,000,000,000,000,000 Are they ALL Iron and Sulfur?
How many molecules? Pyrite – FeS 2 Would there be any other elements in there???
Lecture 5 (9/20/2006) Crystal Chemistry Part 4: Compositional Variation of Minerals Solid Solution Mineral Formula Calculations Graphical Representation.
Finding Theoretical Yield and Percent Yield
Percent Composition of a :Compound Percent Composition of a : Sample Empirical Formulas Molecular Formulas.
Formula Mass and Composition of Compounds
Chemical Formulas and Molar Masses A few old ideas revisited and a few new.
Chemical Quantities The Mole
Combustion Analysis Topic #13
&. Percent Composition Indicates relative % of each element in a compound Total % of the components ~ 100%
EARTH MATERIALS III Rock-forming minerals: silicates Professor Peter Doyle
ROCK vs. MINERAL n ROCK n Mixture n Can be separated by physical means n MINERAL n Pure substance n Has specific formula n Cannot be separated by physical.
Classification of Minerals Native Elements Native Elements – minerals naturally composed of only one element (e.g., diamond, sulfur, gold) Sulfides and.
Stoichiometry Atomic Mass Atomic Mass Molar Mass of an Element Molar Mass of an Element Molecular Mass Molecular Mass Percent Composition Percent Composition.
1 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Another ‘picture’ of atom arrangement
Chapter 3 Stoichiometric
Stoichiometry Chemical Analyses and Formulas Stoichiometry Chemical analyses of oxygen bearing minerals are given as weight percents of oxides. We need.
Empirical Formula The simplest formula that represents the whole number ratio between the elements in a compound.
Ionic radius is related to the valence of the ion - ions that have lost electrons (cations) are smaller than their neutral state, ions that have gained.
Stoichiometry Some minerals contain varying amounts of 2+ elements which substitute for each other Solid solution – elements substitute in the mineral.
The Mole Chapter 7 Chemical Quantities Determine the percent composition of Fe(OH) 2 Fe – 1 x 55.8 = 55.8 O – 2 x 16 = 32 H – 2 x 1 = 2 Molar mass =
What Could It Be? Empirical Formulas The empirical formula is the simplest whole number ratio of the atoms of each element in a compound. Note: it is.
1 Chapter 10 “Chemical Quantities” Yes, you will need a calculator for this chapter!
 How many atoms are in 3.6 mol of calcium?  How many moles are in 1.45 x atoms of sodium?  What is the molar mass of K 2 SO 4 ?  How many grams.
% Composition, Empirical Formulas, & Molecular Formulas.
Stoichiometry Chapter 3 Chemical Formulas and Equations.
Atomic Unit Calculations. Calculating Atomic Mass Units (amu) Definition: A unit of mass used to express atomic and molecular weights.
Molecular Formula Calculations Combustion & Weight Percent C x H y + (x + y/4) O 2  x CO 2 + y/2 H 2 O C 2 H 5 OH + 3 O 2  2 CO H 2 O.
Chemical bonds and molecular models.  Compounds are composed of chemical bonds  Bonds are result of interactions between particles- electrons and protons.
Mass Relationships in Chemical Reactions
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Chapter 7 Objectives Explain the significance of a chemical formula.
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Chapter 3 Calculations with Chemical Formulas and Equations
III. Atoms, Elements and Minerals
Mass Relationships in Chemical Reactions
Chemistry II Objectives Unit II - Chapter 2-4
Law of Conservation of Mass
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Percentage Composition from Formulas
EMPIRICAL FORMULA AND MOLECULAR FORMULA
Classification of Minerals
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
A sample problem 3.43) Allicin is the compound responsible for the characteristic smell of garlic. An analysis of the compound gives the following percent.
Molecular formulas.
Percent Composition Empirical Formula Molecular Formula
Mass Relationships in Chemical Reactions
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Classification of Minerals
Ch 6 Chemical Composition
Mass Relationships in Chemical Reactions
Unit 3: Stoichiometry The Mole, Molar Mass, % Composition, Balancing Chemical Equations, Limiting Reagent, Percent Yield.
Stoichiometry- Mass Relationships in Chemical Reactions
Empirical & Molecular Formulas
What Could It Be? Finding Empirical and Molecular Formulas.
Geology 2217 Lab. 1. Recalculation of chemical analyses.
Ch. 7: Chemical Formulas and Compounds
Chemical Formulas & Mass
Stoichiometry.
Stoichiometry Some minerals contain varying amounts of 2+ elements which substitute for each other Solid solution – elements substitute in the mineral.
Chapter 3 Atoms: the Building Blocks of Matter
Problem: A melt or water solution that a mineral precipitates from contains ALL natural elements Question: Do any of these ‘other’ ions get into a particular.
Presentation transcript:

Chemical Formulas Subscripts represent relative numbers of elements present (Parentheses) separate complexes or substituted elements Fe(OH)3 – Fe bonded to 3 separate OH groups (Mg, Fe)SiO4 – Olivine group – mineral composed of 0-100 % of Mg, 100-Mg% Fe Go over this example in detail – maybe get a few others together

Stoichiometry Some minerals contain varying amounts of 2+ elements which substitute for each other Solid solution – elements substitute in the mineral structure on a sliding scale, defined in terms of the end members – species which contain 100% of one of the elements Iintroduced binary diagrams before, use a ternary example – feldspar, get figure in here… Go over several examples in class – make sure students understand this – many mneral subclasses differ only in one or the other elemental substitution – garnet as an example may be good – isostructural, two sets of 3 with a ternary substitution Work into functional difference of solid solution – differentiate between minerals of solid solution and ones in which substitution is less interchangable – why the difference – is this a chemical or environmental reason?

Chemical heterogeneity Matrix containing ions a mineral forms in contains many different ions/elements – sometimes they get into the mineral Ease with which they do this: Solid solution: ions which substitute easily form a series of minerals with varying compositions (olivine series  how easily Mg (forsterite) and Fe (fayalite) swap…) Impurity defect: ions of lower quantity or that have a harder time swapping get into the structure

Compositional diagrams Fe3O4 magnetite FeO wustite Fe2O3 hematite A Fe O A1B2C3 C=50%, B=35%, C=15% A1B1C1 x A1B2C3 x B C

Fe Mg Si fayalite forsterite enstatite ferrosilite Fe Mg forsterite fayalite Pyroxene solid solution  MgSiO3 – FeSiO3 Olivine solid solution  Mg2SiO4 – Fe2SiO4

KMg3(AlSi3O10)(OH)2 - phlogopite K(Li,Al)2-3(AlSi3O10)(OH)2 – lepidolite KAl2(AlSi3O10)(OH)2 – muscovite Amphiboles: Ca2Mg5Si8O22(OH)2 – tremolite Ca2(Mg,Fe)5Si8O22(OH)2 –actinolite (K,Na)0-1(Ca,Na,Fe,Mg)2(Mg,Fe,Al)5(Si,Al)8O22(OH)2 - Hornblende Actinolite series minerals

Normalization Analyses of a mineral or rock can be reported in different ways: Element weight %- Analysis yields x grams element in 100 grams sample Oxide weight % because most analyses of minerals and rocks do not include oxygen, and because oxygen is usually the dominant anion - assume that charge imbalance from all known cations is balanced by some % of oxygen Number of atoms – need to establish in order to get to a mineral’s chemical formula Technique of relating all ions to one (often Oxygen) is called normalization

Normalization Be able to convert between element weight %, oxide weight %, and # of atoms What do you need to know in order convert these? Element’s weight  atomic mass (Si=28.09 g/mol; O=15.99 g/mol; SiO2=60.08 g/mol) Original analysis Convention for relative oxides (SiO2, Al2O3, Fe2O3 etc)  based on charge neutrality of complex with oxygen (using dominant redox species)

Normalization example Start with data from quantitative analysis: weight percent of oxide in the mineral Convert this to moles of oxide per 100 g of sample by dividing oxide weight percent by the oxide’s molecular weight ‘Fudge factor’ from Perkins Box 1.5, pg 22: is process called normalization – where we divide the number of moles of one thing by the total moles  all species/oxides then are presented relative to one another