Hello to Casey Holgado listening from Oklahoma State!

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Hello to Casey Holgado listening from Oklahoma State! inst.eecs.berkeley.edu/~cs61c UC Berkeley CS61C : Machine Structures Lecture 23 – Combinational Logic Blocks 2010-03-17 Hello to Casey Holgado listening from Oklahoma State! Lecturer SOE Dan Garcia www.cs.berkeley.edu/~ddgarcia National Broadband Plan  The FCC delivered their plan to Congress yesterday, “with an ambitious agenda to connect by 2020 all corners of the nation &transform the economy and society with the communications network of the future”. 100 Million households @ 100 Mbit/s!! The Obama administration put $7.2 billion toward this… Greet class broadband.gov

Review Use this table and techniques we learned to transform from 1 to another

Today Data Multiplexors Arithmetic and Logic Unit Adder/Subtractor

Data Multiplexor (here 2-to-1, n-bit-wide) “mux”

N instances of 1-bit-wide mux How many rows in TT?

How do we build a 1-bit-wide mux?

4-to-1 Multiplexor? How many rows in TT?

Is there any other way to do it? Hint: NCAA tourney! Ans: Hierarchically!

Midterm discussion, moving forward Administrivia Midterm discussion, moving forward If you want a regrade for your midterm, staple a paper with your explanation (clearly indicating on what question you want more points) to your exam and turn it in to your TA in lab this week We’ll regrade the exam and your score MIGHT go down…

Arithmetic and Logic Unit Most processors contain a special logic block called “Arithmetic and Logic Unit” (ALU) We’ll show you an easy one that does ADD, SUB, bitwise AND, bitwise OR

Our simple ALU

Adder/Subtracter Design -- how? Truth-table, then determine canonical form, then minimize and implement as we’ve seen before Look at breaking the problem down into smaller pieces that we can cascade or hierarchically layer

Adder/Subtracter – One-bit adder LSB…

Adder/Subtracter – One-bit adder (1/2)…

Adder/Subtracter – One-bit adder (2/2)…

N 1-bit adders  1 N-bit adder + What about overflow? Overflow = cn?

Consider a 2-bit signed # & overflow: What about overflow? Consider a 2-bit signed # & overflow: 10 = -2 + -2 or -1 11 = -1 + -2 only 00 = 0 NOTHING! 01 = 1 + 1 only Highest adder C1 = Carry-in = Cin, C2 = Carry-out = Cout No Cout or Cin  NO overflow! Cin, and Cout  NO overflow! Cin, but no Cout  A,B both > 0, overflow! Cout, but no Cin  A,B both < 0, overflow! ± # What op?

Consider a 2-bit signed # & overflow: What about overflow? Consider a 2-bit signed # & overflow: 10 = -2 + -2 or -1 11 = -1 + -2 only 00 = 0 NOTHING! 01 = 1 + 1 only Overflows when… Cin, but no Cout  A,B both > 0, overflow! Cout, but no Cin  A,B both < 0, overflow! ± #

Extremely Clever Subtractor

Truth table for mux with 4-bits of signals has 24 rows Peer Instruction Truth table for mux with 4-bits of signals has 24 rows We could cascade N 1-bit shifters to make 1 N-bit shifter for sll, srl 12 a) FF b) FT c) TF d) TT

Peer Instruction Answer Truth table for mux with 4-bits of signals controls 16 inputs, for a total of 20 inputs, so truth table is 220 rows…FALSE We could cascade N 1-bit shifters to make 1 N-bit shifter for sll, srl … TRUE Truth table for mux with 4-bits of signals is 24 rows long We could cascade N 1-bit shifters to make 1 N-bit shifter for sll, srl 12 a) FF b) FT c) TF d) TT False (explained above) True

Use muxes to select among input “And In conclusion…” Use muxes to select among input S input bits selects 2S inputs Each input can be n-bits wide, indep of S Can implement muxes hierarchically ALU can be implemented using a mux Coupled with basic block elements N-bit adder-subtractor done using N 1- bit adders with XOR gates on input XOR serves as conditional inverter