42(TOTAL) - 10(5 BONDS) = 32(REMAIN)T

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Valence Shell Electron Pair Repulsion Theory

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Presentation transcript:

42(TOTAL) - 10(5 BONDS) = 32(REMAIN)T RENDER THE VESPR DOT STRUCTURE OF IF5 SHOWING THE GEOMETRY, AXE NOTATION AND FULL POLARITY ASSESSMENT (MOLECULAR AND BOND POLARITY…BOTH) STEP ONE: CALCULATE VALENCE ELECTRONS: I: 7 X 1 = 7 F:7 X 5 = 35 neutral = 0 total Ve- = 42 STEP TWO: ID CENTRAL (LEAST ELECTRONEGATIVE) AND DRAW WITH SINGLE BONDS…NO GEOMETRY YET! F F 42(TOTAL) - 10(5 BONDS) = 32(REMAIN)T F I F F

32(TOTAL) - 30(FOR OCTETS) = 2(REMAIN) RENDER THE VESPR DOT STRUCTURE OF IF5 SHOWING THE GEOMETRY, AXE NOTATION AND FULL POLARITY ASSESSMENT (MOLECULAR AND BOND POLARITY…BOTH) STEP THREE: COMPLETE THE VALENCE OF THE LIGANDS. Step 4: PLACE REMAINNING ELECTRONS ON CENTRAL F 32(TOTAL) - 30(FOR OCTETS) = 2(REMAIN) F F I F F 2 (TOTAL)

THIS MOLECULE IS AX5E1 FORM THE VSEPR CHART AND IS THIS MOLECULE HAS 6 DOMAINS, SQUARE BIPYRAMIDAL : WITH 5 BONDS AND ONE UNSHARED PAIR ON THE CENTRAL ATOM. F F F I F F THIS MOLECULE IS AX5E1 FORM THE VSEPR CHART AND IS SQUARE PYRAMIDAL

32(TOTAL) - 8(5 BONDS) = 24(REMAIN) RENDER THE VESPR DOT STRUCTURE OF SO42- SHOWING THE GEOMETRY, AXE NOTATION AND FULL POLARITY ASSESSMENT (MOLECULAR AND BOND POLARITY…BOTH) STEP ONE: CALCULATE VALENCE ELECTRONS: S: 7 ve- X 1 = 6 0: 6 ve- X 4 = 24 -2 charge = 2 total Ve- = 32 STEP TWO: ID CENTRAL (LEAST ELECTRONEGATIVE) AND DRAW WITH SINGLE BONDS…NO GEOMETRY YET! 32(TOTAL) - 8(5 BONDS) = 24(REMAIN) S O

24(TOTAL) - 24(4 BONDS) =0 REMAIN, SO NO PAIRS ON CENTRAL ATOM! RENDER THE VESPR DOT STRUCTURE OF SO42- SHOWING THE GEOMETRY, AXE NOTATION AND FULL POLARITY ASSESSMENT (MOLECULAR AND BOND POLARITY…BOTH) O O S O O 24(TOTAL) - 24(4 BONDS) =0 REMAIN, SO NO PAIRS ON CENTRAL ATOM!

THIS MOLECULE IS AX4E0 FORM THE VSEPR CHART AND IS RENDER THE VESPR DOT STRUCTURE OF SO42- SHOWING THE GEOMETRY, AXE NOTATION AND FULL POLARITY ASSESSMENT (MOLECULAR AND BOND POLARITY…BOTH) O O O S THIS MOLECULE IS AX4E0 FORM THE VSEPR CHART AND IS TETRAHEDRAL O