Probability & Tree Diagrams

A fair coin is flipped twice 1st 2nd H HH Possible Outcomes H T HT H TH T T TT

Attach probabilities 1st 2nd H HH P(H,H)=½x½=¼ ½ ½ H ½ T HT P(H,T)=½x½=¼ ½ H TH P(T,H)=½x½=¼ ½ T ½ T TT P(T,T)=½x½=¼

Calculate probabilities 1st 2nd * H HH P(H,H)=½x½=¼ ½ ½ H ½ * T HT P(H,T)=½x½=¼ * ½ H TH P(T,H)=½x½=¼ ½ T ½ T TT P(T,T)=½x½=¼ Probability of at least one Head?

10 beads in a bag – 3 Red, 2 Blue, 5 Green. One taken, returned to bag, then a second taken. 1st 2nd R RR B RB R G RG R BR B B BB G BG R GR G GB B G GG

Probabilities 1st 2nd R RR B RB R G RG R BR B B BB G BG R GR G GB B G P(RR) = 0.3x0.3 = 0.09 0.3 0.2 B RB P(RB) = 0.3x0.2 = 0.06 R 0.3 0.5 G RG P(RG) = 0.3x0.5 = 0.15 R BR P(BR) = 0.2x0.3 = 0.06 0.3 0.2 0.2 B B BB P(BB) = 0.2x0.2 = 0.04 0.5 G BG P(BG) = 0.2x0.5 = 0.10 R GR 0.3 P(GR) = 0.5x0.3 = 0.15 0.5 G 0.2 GB B P(GB) = 0.5x0.2 = 0.10 G GG 0.5 P(GG) = 0.5x0.5 = 0.25 All ADD UP to 1.0

Choose a Meal IC AP 0.45 0.55 S F P 0.2 0.45 0.55 IC AP 0.5 0.3 IC AP Dessert Ice Cream 0.45 Apple Pie 0.55 Main course Salad 0.2 Fish & Chips 0.5 Pizza 0.3 IC AP P(S,IC) = 0.2 x 0.45 = 0.09 0.45 0.55 S F P P(S,AP) = 0.2 x 0.55 = 0.110 0.2 0.45 0.55 IC AP P(F,IC) = 0.5 x 0.45 = 0.225 0.5 P(F,AP) = 0.5 x 0.55 = 0.275 0.3 IC AP P(P,IC) = 0.3 x 0.45 = 0.135 0.45 0.55 P(P,AP) = 0.3 x 0.55 = 0.165