expanding multiplying a term over a bracket. Recap.

Factorise Finding terms that multiply to make an expression Factorise Finding terms that multiply to make an expression. It is the reverse of expanding. 4a + 3a2 So we are looking for two terms that will multiply together to make this expression. To find those terms we are going to look for what is common to both of them, to look what we can divide both of them by. In this case, we can divide both by a, so we are going to ask, what can we multiply a by, to make each of these terms? The answer is a(4 + 3a). We can check it is correct by expanding.

Factorise 15 + 5a 12ab3 + 4a2b

Factorise 4a3 + 10a2b 9a3 + 2b Why is the bottom one not possible?

Factorise 3a2 + 8a3b + 4ab 4xy3+ 6xy

6) 6y + 5x2 6a + a2 7) 3ab + 6ab2 12 + 3a 8) 5b2 + 15b 4a2 + 8ab Factorise 6a + a2 12 + 3a 4a2 + 8ab 9b + 9b3 4xy2 + 2x2y 6) 6y + 5x2 7) 3ab + 6ab2 8) 5b2 + 15b 9) 2a2 + 4a + 6a3 10) ab4 + 4ab2 + 3a3b3

answers 6a + a2 = a(6 + a) 12 + 3a = 3(4 + a) 4a2 + 8ab = a(6 + a) 9b + 9b3 = 9b(1 + b) 4xy2 + 2x2y 6) 6y + 5x2 = N/A 7) 3ab + 6ab2 8) 5b2 + 15b 9) 2a2 + 4a + 6a3 10) ab4 + 4ab2 + 3a3b3 = 3ab(1 + 2b) = 5b(b + 3) = 2xy(y + 2x) = 2a(a + 2 + 3a2) = ab(b3 + 4b + 3a2b2)