Unit 9 Exam Review.

Slides:



Advertisements
Similar presentations
Do NOW Please draw the Lewis Dot structure of NO3-1 and identify if it is a polar or nonpolar molecule.
Advertisements

Pressure Volume & Temperature. In liquids and solids, the primary particles (atoms or molecules) are always in contact with each other. In gases, particles.
Gaseous State Chapter 9.
Wrap up Proving “R” constant.  We can find out the volume of gas through Stoichiometry CH 4 + O 2  CO 2 + H 2 O22 Think of the coefficients as volume.
Avogadro’s Law.
Gases Chapter – The Gas Laws Kinetic Theory = assumes that gas particles:  do not repel or attract each other  are much smaller than the distances.
Gas Stoichiometry A balanced equation shows the ratio of moles being used and produced Because of Avogrado’s principle, it also shows the ratio of volumes.
Mullis1 Gay Lussac’s law of combining volumes of gases When gases combine, they combine in simple whole number ratios. These simple numbers are the coefficients.
Gas Notes I. Let’s look at some of the Nature of Gases: 1. Expansion – gases do NOT have a definite shape or volume. 2. Fluidity – gas particles glide.
Third Nine Weeks- 6 weeks review
Chapter 11 Gas Laws. Objectives Describe the properties of gases Describe the Kinetic Molecular Theory, Ideal Gases Explain air pressure and barometers.
Behavior of Gas Molecules
Chapter 12 (Practice Test)
Ideal Gas Law & Gas Stoichiometry
Warm-up R= L atm/mol k  If a gas is compressed…  What happens to the volume?  What happens to the pressure?  What happens to Temperature? 
NOTES: Unit 4 - AIR Sections A1 – A8: Behavior of Gases and Gas Laws.
Ideal Gas Law (Equation):
Gas Stoichiometry. Equal volumes of gases at the same temperature and pressure contain equal amounts of particles The coefficients in a balanced equation.
Gas Stoichiometry!. equal volumes of gases at the same temperature & pressure contain equal numbers of particles equal volumes of gases at the same temperature.
Note: You must memorize STP and the gas laws!!. The Kinetic Molecular Theory states that gas particles are ____________ and are separated from one another.
Ideal gases and molar volume
Ideal Gas Law Chapter Ideal Gas Law The ideal gas law combines: –pressure –temperature –volume –# of particles (amount)
What volume will 1 mole of a gas occupy at STP? STP = 273K, 1.013x10 5 Pa One mole of any ideal gas occupies a volume of 22.4L at STP.
Unit 9 Exam Review. Constants and Formulas Molar Volume : 22.4 L/mol Ideal Gas Constant:.0821 L*atm/mol *K Combined Gas Law: P 1 V 1 = P 2 V 2 n 1 T 1.
Unit 9 Exam Review. Constants and Formulas Molar Volume : 22.4 L/mol Ideal Gas Constant:.0821 L*atm/mol *K Combined Gas Law: P 1 V 1 = P 2 V 2 n 1 T 1.
Thursday Welcome, Practice Tests, Labs Round 2 tests Temperature & Pressure Conversions Combined Gas Law –M STP Molar Volume Ideal Gas Law.
Gas Laws Kinetic Theory assumptions Gas particles do not attract or repel Small particles in constant random motion Elastic collisions All gases have the.
Unit 5:Gas Laws Ms. C. HIll. I. Kinetic Molecular Theory A. Explains the properties of gases B. Predicts how gases will act C. It says gas particles:
Unit 9 Exam Review.
The Gas Laws.
Avogadro’s Law The Ideal Gas Law Combined Gas Laws STP
TOPIC: BOYLE’S LAW Do Now: According to the KMT, Why do gases exert pressure Answer: Gas particles are in constant motion, pushing on the walls of their.
V. Combined and Ideal Gas Law
Gas Laws Gases.
Chapter 12 Practice Test Assignment #2
Chapter 13 The Gas Laws.
Gases.
Honors Chemistry Chapter 12 Gas Laws.
10.7 – NOTES Ideal Gas Laws.
Quantitative chemistry
Ideal Gas Law PV=nRT.
II. Molar Conversions.
Molar Volume.
Ch. 11: Molecular Composition of Gases
The Ideal Gas Law.
Gas Volumes and the Ideal Gas Law
Volume and Moles (Avogadro’s Law)
Ideal Gas Law (Equation):
Ch. 11: Molecular Composition of Gases
Guy-Lussac’s Law P1 / T1 = P2 / T2 Avogadro’s Law V1 / n1 = V2 / n2
Avogadro’s Law.
Gas Stoichiometry.
Warm-up If I have 4.00 moles of a gas at a pressure of 5.60 atm and a volume of 12.0 liters, what is the temperature in kelvin?
Volume-Mass Relationships of Gases
The Gas Laws.
Avogadro’s Law.
Gas Law Stoichiometry.
Moles and Gas Volume (3.4) Avogadro’s Hypothesis: equal volumes of different gases at the same temperature and pressure contain the same number of particles.
Moles, Volume and Density
Section 3 Gas Volumes and the Ideal Gas Law
Unit 9 Exam Review.
11.9 Tro's Introductory Chemistry, Chapter 11.
Accelerated Chemistry Molecular Composition of Gases
Chapter 11 Preview Lesson Starter Objectives
Stoichiometry of Gases
Gas Volumes and Ideal Gas Law
C2H6 CH3 B. Empirical Formula
Chapter 11 Gas Volumes and the Ideal Gas Law Section 3.
Molar Volume Chapter 7-2.
Presentation transcript:

Unit 9 Exam Review

Which of the following does not represent the behavior of an ideal gas? C) A gas where the pressure is extremely high A) A gas where the particles are far apart B) A gas where the temperature is extremely low D) A gas where the particles bounce off of one another

Which of the following describes the behavior of gases (in accordance with KMT)? A larger gas particle has more KE than a smaller gas particle at the same temp Gas particles bounce off of one another Gases exert force on their containers Gases slow down motion when temperature increases

No Calculator on the following questions #ISeeYou____________ (insert name here)

Solve: How many moles of a gas occupy 400. mL at 760. torr and 50.0 K? R = .0821 L*atm/mol *K Convert torr to atm Convert ml to L .08 mol

1.6 atm (rigid container = constant volume; sealed = constant mole) Oxygen gas at 35oC in a sealed, rigid container has a pressure of 2.40 atm. If it is cooled to -65oC, what will the new pressure be? 1.6 atm (rigid container = constant volume; sealed = constant mole)

The syringe volume was increased from 2. 07 mL to 6. 13 mL The syringe volume was increased from 2.07 mL to 6.13 mL. If the original pressure was 1209 torr, what is the pressure when expanded? ~400 torr

If a sample of ammonia gas at STP has a volume of 12 If a sample of ammonia gas at STP has a volume of 12.1 L, what will its volume be when heated to 273.0oC at constant pressure? 24.2 L

How many moles of gas are present if a sample of butane gas is held in a sealed 161.3 liter container at a temperature of 42.0 K and is under 765 torr of pressure? ~40 mol

Solve: If a sample of gas at 1 Solve: If a sample of gas at 1.00 atm and 251 K gets compressed into a 50.0 mL container, causing the temperature to be 503 K and the pressure to be 1.50 atm, what was its original volume? 37.5 mL

If a gas in a rigid container has a pressure of 2 If a gas in a rigid container has a pressure of 2.05 atm when the temperature is 310. K, what temperature does it need to be heated to in order to reach 4.01 atm of pressure? ~620 K

The pressure will triple What will happen to the pressure of a gas at a constant temperature if its volume is decreased from 3.0 L to 1.0 L ? The pressure will triple

B (most mol with the highest temp) Which of these identical cylinders is under the greatest pressure? A B C D 1.00 mol 1.00 mol 0.5 mol 0.5 mol 250 K 300 K 250 K 300 K B (most mol with the highest temp)

A (most amount of moles/particles of gas) Which of these identical cylinders is under the greatest pressure? A B C D 2.0 mol 1.0 mol 0.5 mol 0.5 mol 250 K 300 K 500 K 600 K A (most amount of moles/particles of gas)

Convert mol NaHCO3 to mol CO2 2 NaHCO3(s)  1 Na2CO3(s) + 1 H2O(g) + 1 CO2 (g) If 6.00 moles of NaHCO3 react as shown above, how many liters of CO2 gas will be produced at STP? Convert mol NaHCO3 to mol CO2 Use molar volume because it’s at STP to convert to L CO2 67.2 L

Convert L O2 to L H2 using the mole ratio

Convert L N2O to L NH4NO3 with mole ratio 44.0 Convert L N2O to L NH4NO3 with mole ratio because it’s at STP divide by 22.4L to convert to mol NH4NO3 Multiply by formula mass (80.052) ~160 g

Write a balanced equation for the combustion of methane (CH4) Grams Write a balanced equation for the combustion of methane (CH4) Convert L CH4 to L H2O with mole ratio because it’s not at STP use PV=nRT to calculate mol of H2O Multiply by formula mass of water 9.74g H2O(g)