Mole Relations in Chemical Equations

Slides:



Advertisements
Similar presentations
Mathematics of Chemical Equations By using “mole to mole” conversions and balanced equations, we can calculate the exact amounts of substances that will.
Advertisements

 Balance the following equation.  Fe + O 2  Fe 2 O 3  4Fe + 3O 2  2Fe 2 O 3  This means that when we combine four atoms of iron with three molecules.
Limiting Reactants and Excess
Limiting Reactant.  Determine which reactant is left over in a reaction.  Identify the limiting reactant and calculate the mass of the product.  Calculate.
Molar Relationships. A balanced chemical equation can be interpreted in numbers of molecules, but generally chemists interpret equations as “mole-to-mole”
April 3, 2014 Stoichiometry. Stoichiometry is the study of quantities of materials consumed and produced in chemical reactions Stoikheion (Greek, “element”)
Stoichiometry Chapter 8. Stoichiometry Chemical equations Limiting reagent Problem types Percent yield Mass-mass Mole - mole other.
Stoichiometry II. Solve stoichiometric problems involving moles, mass, and volume, given a balanced chemical reaction. Include: heat of reaction Additional.
Stoichiometry Balancing Equations Molecular and Empirical Formulas Percent Composition Mole Conversions
Test Review Chemical Reactions and Stoichiometry.
Meet the Mole.
Stoichiometry. What Is It? Branch of chemistry that shows the relationships among reactants and products in a chemical reaction Equations must be balanced.
Stoichiometry – Chemical Quantities Notes. Stoichiometry Stoichiometry – Study of quantitative relationships that can be derived from chemical formulas.
Stoichiometry Chemical Quantities Chapter 9. What is stoichiometry? stoichiometry- method of determining the amounts of reactants needed to create a certain.
Chap. 9: Stoichiometry Identify the mole ratio of any two species in a chemical reaction. Calculate theoretical yields from chemical equations.
 Predict the products and write a balanced equation for the following: BaCl 2 + MgSO 4 
STOICHIOMETRY. The Problem  If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced?
Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)
Chapter 9 Stoichiometry Test REVIEW SHEET
Mol ratio: coefficients of a balanced equation 2 H 2 + O 2 → 2 H 2 O 2 mol H 2 for every 1 mol O 2 In chemical calculations, mol ratios convert moles of.
Aim: How to do Mass to Mass Calculations. Mass to Mass Calculations.
IC5.2.3 Mole calculations © Oxford University Press Mole calculations.
Stoichiometry  the calculations of quantities in chemical reactions  “stoichio” = elements  “metry” = to measure.
Stoichiometry.
Percent Yield.
Stoichiometry II.
7.2 – The Limiting Reactant
Stoichiometry Stoichiometry: is the study of the calculations of amounts of substances involved in chemical equations.
Stoichiometry Miss Knick HAHS Chem 1B.
MASS - MASS STOICHIOMETRY
Calculating Quantities in Reactions Mass-to-mass problems
Stoichiometry Lancaster High School.
Gram to moles to moles to Grams pg 8
Mathematics in Chemistry
Unit 4: Stoichiometry Stoichiometry.
Calculations with Equations
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
Chemical Reactions Unit
Unit 8 Stoichiometry Notes
WARM-UP 3/2/15 HAPPY MARCH! Balance the following equations
Balancing Chemical Equations
Mathematics of Chemical Equations
2.4 تعيين الصيغة البسيطة تجريبياً Percent Composition Of Compounds
Ch. 9 Notes -- Stoichiometry
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
2 H2 + O2 → 2 H2O 2 mol H2 for every 1 mol O2
Molar Conversions (p.80-85, )
9.3 NOTES Stoichiometry Non- Mass – Mass Problems
9.1 NOTES Stoichiometry.
STOICHIOMETRY Mole to Mole.
Stoichiometry Lancaster High School.
Announcements Bring handout from Tuesday to discussion tomorrow.
Stoichiometry Chemistry II Chapter 9.
and cooking with chemicals
Stoichiometry How does stoichiometry relate to a correctly balanced chemical equation?
Unit 5: Stoichiometry Stoichiometry.
Stoichiometry.
Opener 1/11 Balance the following:
Balancing Equations In Chemical Reactions.
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
Chemical Calculations
Stoichiometry.
Stoichiometry Lancaster High School.
Do Now & Announcements Hand in note packet so I can check your HW (I’ll give it back to you after the quiz) Do Now Quiz (Physical & Chemical Changes)
Bell Work: Intro to Stoicheometry
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
Stoichiometry.
Clicker #1 How many cars can we make? A) 3 B) 4 C) 6 D) 12 E) 16.
Chapter 5 Chemical Quantities and Reactions
Presentation transcript:

Mole Relations in Chemical Equations Students will learn how to predict the mass of products expected in a chemical reaction

Review: Finding the moles from the grams 7.0 grams Na2SO4 = __________ moles 30.0 grams KMnO4 = __________ moles 17.0 grams PCl3= __________ moles

Review: Finding the grams from the moles 1.5 mole NaCl = __________ grams .0165 mole K2SO4 = _________ grams 1.25 mole Cu(NO3)2 = ________ grams

Hydrogen and Oxygen React. How much water will be produced? The reaction between hydrogen and oxygen can be read a couple different ways. 2H2 + O2  2H2O Two molecules of hydrogen react with one molecule of oxygen Two moles of hydrogen react with one mole of oxygen

N2 + 3H2  2NH3

2H2 + O2  2H2O How many moles of oxygen do you need in the examples below? 12 mol of hydrogen ____________ 25 mol of hydrogen ____________

Balance the equation (NH4)2Cr2O7  Cr2O3 + N2 + H2O So this means that: 1.00 mole (NH4)2Cr2O7 produces ___ mole H2O 0.50 mole (NH4)2Cr2O7 produces ___ mole H2O

Video Click here for video

Calculations (NH4)2Cr2O7  Cr2O3 + N2 + 4H2O 25.2 g ↓ g g g 252 g/mol 152 g/mol 28 g/mol 18 g/mol (NH4)2Cr2O7  Cr2O3 + N2 + 4H2O 25.2 g ↓ g g g mole mol mol mol

H2O2  H2O + O2 34 g/mol 18 g/mol 32 g/mol H2O2  H2O + O2 68 grams mol mol mol

Fe + Cl2  FeCl3 55.8g/mol 71.0 g/mol 162.3 g/mol Fe + Cl2  FeCl3 3.0 ____ _____ ____ ____ _____