Chapter 2 Instructions: Language of the Computer part 2 박능수

Conditional Operations The University of Adelaide, School of Computer Science 10 January 2019 Conditional Operations Branch to a labeled instruction if a condition is true Otherwise, continue sequentially beq rs, rt, L1 if (rs == rt) branch to instruction labeled L1; bne rs, rt, L1 if (rs != rt) branch to instruction labeled L1; j L1 unconditional jump to instruction labeled L1 Chapter 2 — Instructions: Language of the Computer

Compiling If Statements The University of Adelaide, School of Computer Science 10 January 2019 Compiling If Statements C code: if (i==j) f = g+h; else f = g-h; f, g, … in $s0, $s1, … Compiled MIPS code: bne $s3, $s4, Else add $s0, $s1, $s2 j Exit Else: sub $s0, $s1, $s2 Exit: … Assembler calculates addresses Chapter 2 — Instructions: Language of the Computer

Compiling Loop Statements The University of Adelaide, School of Computer Science 10 January 2019 Compiling Loop Statements C code: while (save[i] == k) i += 1; i in $s3, k in $s5, address of save in $s6 Compiled MIPS code: Loop: sll $t1, $s3, 2 add $t1, $t1, $s6 lw $t0, 0($t1) bne $t0, $s5, Exit addi $s3, $s3, 1 j Loop Exit: … Chapter 2 — Instructions: Language of the Computer

Basic Blocks A basic block is a sequence of instructions with No embedded branches (except at end) No branch targets (except at beginning) A compiler identifies basic blocks for optimization An advanced processor can accelerate execution of basic blocks

MIPS Control Flow Instructions MIPS conditional branch instructions: bne $s0, $s1, Lbl #go to Lbl if $s0$s1 beq $s0, $s1, Lbl #go to Lbl if $s0=$s1 Ex: if (i==j) h = i + j; bne $s0, $s1, Lbl1 add $s3, $s0, $s1 Lbl1: ... Instruction Format (I format): How is the branch destination address specified? 0x05 16 17 16 bit offset

Specifying Branch Destinations Use a register (like in lw and sw) added to the 16-bit offset which register? Instruction Address Register (the PC) its use is automatically implied by instruction PC gets updated (PC+4) during the fetch cycle so that it holds the address of the next instruction limits the branch distance to -215 to +215-1 (word) instructions from the (instruction after the) branch instruction, but most branches are local anyway PC Add 32 offset 16 00 sign-extend from the low order 16 bits of the branch instruction branch dst address ? 4

In Support of Branch Instructions We have beq, bne, but what about other kinds of branches (e.g., branch-if-less-than)? For this, we need yet another instruction, slt Set on less than instruction: slt $t0, $s0, $s1 # if $s0 < $s1 then # $t0 = 1 else # $t0 = 0 Instruction format (R format): Alternate versions of slt slti $t0, $s0, 25 # if $s0 < 25 then $t0=1 ... sltu $t0, $s0, $s1 # if $s0 < $s1 then $t0=1 ... sltiu $t0, $s0, 25 # if $s0 < 25 then $t0=1 ... 0 16 17 8 0x24 2

Aside: More Branch Instructions Can use slt, beq, bne, and the fixed value of 0 in register $zero to create other conditions less than blt $s1, $s2, Label less than or equal to ble $s1, $s2, Label greater than bgt $s1, $s2, Label great than or equal to bge $s1, $s2, Label Such branches are included in the instruction set as pseudo instructions - recognized (and expanded) by the assembler Its why the assembler needs a reserved register ($at) slt $at, $s1, $s2 #$at set to 1 if bne $at, $zero, Label #$s1 < $s2

Bounds Check Shortcut Treating signed numbers as if they were unsigned gives a low cost way of checking if 0 ≤ x < y (index out of bounds for arrays) sltu $t0, $s1, $t2 # $t0 = 0 if $s1 > $t2 (max) # or $s1 < 0 (min) beq $t0, $zero, IOOB # go to IOOB if # $t0 = 0 The key is that negative integers in two’s complement look like large numbers in unsigned notation. Thus, an unsigned comparison of x < y also checks if x is negative as well as if x is less than y.

Other Control Flow Instructions MIPS also has an unconditional branch instruction or jump instruction: j label #go to label Instruction Format (J Format): 0x02 26-bit address PC 4 32 26 00 from the low order 26 bits of the jump instruction

Aside: Branching Far Away What if the branch destination is further away than can be captured in 16 bits? The assembler comes to the rescue – it inserts an unconditional jump to the branch target and inverts the condition beq $s0, $s1, L1 becomes bne $s0, $s1, L2 j L1 L2:

Instructions for Accessing Procedures MIPS procedure call instruction: jal ProcedureAddress #jump and link Saves (PC+4) in register $ra to have a link to the next instruction for the procedure return Jump to target address Machine format (J format): Then can do procedure return with a jr $ra #return Copies $ra to program counter Can also be used for computed jumps e.g., for case/switch statements Instruction format (R format): 0x03 26 bit address 0 31 0x08

Six Steps in Execution of a Procedure Main routine (caller) places parameters in a place where the procedure (callee) can access them $a0 - $a3: four argument registers Caller transfers control to the callee Callee acquires the storage resources needed Callee performs the desired task Callee places the result value in a place where the caller can access it $v0 - $v1: two value registers for result values Callee returns control to the caller $ra: one return address register to return to the point of origin

Leaf Procedure Example The University of Adelaide, School of Computer Science 10 January 2019 Leaf Procedure Example C code: int leaf_example (int g, h, i, j) { int f; f = (g + h) - (i + j); return f; } Arguments g, …, j in $a0, …, $a3 f in $s0 (hence, need to save $s0 on stack) Result in $v0 Chapter 2 — Instructions: Language of the Computer

Leaf Procedure Example The University of Adelaide, School of Computer Science 10 January 2019 Leaf Procedure Example MIPS code: leaf_example: addi $sp, $sp, -12 sw $t1, 8($sp) sw $t0, 4($sp) sw $s0, 0($sp) add $t0, $a0, $a1 add $t1, $a2, $a3 sub $s0, $t0, $t1 add $v0, $s0, $zero lw $s0, 0($sp) lw $t0, 4($sp) lw $t1, 8($sp) addi $sp, $sp, 12 jr $ra Save $t1 on stack Save $t0 on stack Save $s0 on stack Procedure body Result Restore $s0 Restore $t0 Restore $t1 Return Chapter 2 — Instructions: Language of the Computer

The University of Adelaide, School of Computer Science 10 January 2019 Non-Leaf Procedures Procedures that call other procedures For nested call, caller needs to save on the stack: Its return address Any arguments and temporaries needed after the call Restore from the stack after the call Chapter 2 — Instructions: Language of the Computer

Non-Leaf Procedure Example The University of Adelaide, School of Computer Science 10 January 2019 Non-Leaf Procedure Example C code: int fact (int n) { if (n < 1) return f; else return n * fact(n - 1); } Argument n in $a0 Result in $v0 Chapter 2 — Instructions: Language of the Computer

Non-Leaf Procedure Example The University of Adelaide, School of Computer Science 10 January 2019 Non-Leaf Procedure Example MIPS code: fact: addi $sp, $sp, -8 # adjust stack for 2 items sw $ra, 4($sp) # save return address sw $a0, 0($sp) # save argument slti $t0, $a0, 1 # test for n < 1 beq $t0, $zero, L1 addi $v0, $zero, 1 # if so, result is 1 addi $sp, $sp, 8 # pop 2 items from stack jr $ra # and return L1: addi $a0, $a0, -1 # else decrement n jal fact # recursive call lw $a0, 0($sp) # restore original n lw $ra, 4($sp) # and return address addi $sp, $sp, 8 # pop 2 items from stack mul $v0, $a0, $v0 # multiply to get result jr $ra # and return Chapter 2 — Instructions: Language of the Computer

Aside: Spilling Registers What if the callee needs to use more registers than allocated to argument and return values? callee uses a stack – a last-in-first-out queue high addr One of the general registers, $sp ($29), is used to address the stack (which “grows” from high address to low address) add data onto the stack – push $sp = $sp – 4 data on stack at new $sp remove data from the stack – pop data from stack at $sp $sp = $sp + 4 top of stack $sp low addr

Aside: Allocating Space on the Stack The segment of the stack containing a procedure’s saved registers and local variables is its procedure frame (aka activation record) The frame pointer ($fp) points to the first word of the frame of a procedure – providing a stable “base” register for the procedure $fp is initialized using $sp on a call and $sp is restored using $fp on a return high addr $fp Saved argument regs (if any) Saved return addr Saved local regs (if any) Local arrays & structures (if any) $sp low addr

Aside: Allocating Space on the Heap Static data segment for constants and other static variables (e.g., arrays) Dynamic data segment (aka heap) for structures that grow and shrink (e.g., linked lists) Allocate space on the heap with malloc() and free it with free() in C Memory $sp 0x 7f f f f f f c Stack Dynamic data (heap) $gp 0x 1000 8000 Static data 0x 1000 0000 Text (Your code) PC 0x 0040 0000 Reserved 0x 0000 0000

MIPS Instruction Classes Distribution Frequency of MIPS instruction classes for SPEC2006 Instruction Class Frequency Integer Ft. Pt. Arithmetic 16% 48% Data transfer 35% 36% Logical 12% 4% Cond. Branch 34% 8% Jump 2% 0%

Atomic Exchange Support Need hardware support for synchronization mechanisms to avoid data races where the results of the program can change depending on how events happen to occur data races : Two memory accesses from different threads to the same location, and at least one is a write Atomic exchange (atomic swap) – interchanges a value in a register for a value in memory atomically, i.e., as one operation (instruction) Implementing an atomic exchange would require both a memory read and a memory write in a single, uninterruptable instruction. An alternative is to have a pair of specially configured instructions ll $t1, 0($s1) #load linked sc $t0, 0($s1) #store conditional

Atomic Exchange with ll and sc If the contents of the memory location specified by the ll are changed before the sc to the same address occurs, the sc fails (returns a zero) If the value in memory between the ll and the sc instructions changes, then sc returns a 0 in $t0 causing the code sequence to try again. try: add $t0, $zero, $s4 #$t0=$s4 (exchange value) ll $t1, 0($s1) #load memory value to $t1 sc $t0, 0($s1) #try to store exchange #value to memory, if fail #$t0 will be 0 beq $t0, $zero, try #try again on failure add $s4, $zero, $t1 #load value in $s4

Translation and Startup The University of Adelaide, School of Computer Science 10 January 2019 Translation and Startup Many compilers produce object modules directly Static linking machine code Chapter 2 — Instructions: Language of the Computer

Compiler Benefits Comparing performance for bubble (exchange) sort To sort 100,000 words with the array initialized to random values on a Pentium 4 with a 3.06 clock rate, a 533 MHz system bus, with 2 GB of DDR SDRAM, using Linux version 2.4.20 The unoptimized code has the best CPI, the O1 version has the lowest instruction count, but the O3 version is the fastest. gcc opt Relative Performance Clock cycles (M) Instr count (M) CPI None 1.00 158,615 114,938 1.38 O1 (medium) 2.37 66,990 37,470 1.79 O2 (full) 2.38 66,521 39,993 1.66 O3 (proc integ) 2.41 65,747 44,993 1.46

Addressing Mode Summary The University of Adelaide, School of Computer Science 10 January 2019 Addressing Mode Summary Chapter 2 — Instructions: Language of the Computer

MIPS Organization So Far Processor Memory Register File 1…1100 src1 addr src1 data 5 32 src2 addr 32 registers ($zero - $ra) 5 dst addr read/write addr 5 src2 data write data 32 230 words 32 32 32 bits branch offset read data 32 Add PC 32 32 32 32 Add 32 4 write data 0…1100 Fetch PC = PC+4 Decode Exec 32 0…1000 32 4 5 6 7 0…0100 32 ALU 1 2 3 0…0000 32 word address (binary) 32 bits 32 byte address (big Endian)