Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X Y Y D Find the average slope from point A, to Point D, as a percent [pause] In this problem, ----- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X Y Y D Points A, B, C and D are located on a x-y coordinate system. The exact coordinates of these points --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X Y Y D are provided in a table of values, where the units of length --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 [ft] X Y D is feet. [pause] The elevation of Point A is provided --- Y A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X [ft] Y [ft] D as 362.01 feet. And the backsight and foresight measurements from a level survey --- Y A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] 0.2% 0.4% 0.6% 0.8% BS HI FS Elev A 1.95 362.01 dd B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X [ft] Y [ft] D are provided. This leveling data is also --- Y A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] BS HI FS Elev A 1.95 362.01 dd [ft] B 9.50 4.84 dd C 4.63 3.72 dd D 5.85 X [ft] Y [ft] D in units of feet. [pause] The average slope of a line segment equals --- Y A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 362.01 slope dd B 9.50 4.84 Δz dd S= C 4.63 3.72 ΔL dd D 5.85 X Y Y D the change in elevation between the two end points, divided by ---- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 Δz dd S= C 4.63 3.72 slope ΔL dd D 5.85 horizontal X Y Y length D the horizontal length between the two end points. Next we’ll add the subscript, A D --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y D to both of these terms, because we are looking to find the slope from Point A, --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 A B X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y D to point D. [pause] We can determine the horizontal length, delta L sub A D --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 B A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y D by using the given coordinate data, for points A and D. Where this length equals, --- A 0.00 0.00 B 128.33 67.54 C C 209.67 118.45 B A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y the square root of the difference in x coordinates squared, plus, the difference of the y coordinates squared. ΔLAD= (DX-AX)2+(DY-AY)2 A 0.00 0.00 B 128.33 67.54 C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y After plugging in these values, we find the change in the horizontal length between Points --- ΔLAD= (DX-AX)2+(DY-AY)2 A 0.00 0.00 B 128.33 67.54 C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y A and D equals, 397.33 feet. This length will be the denominator, in our quotient --- ΔLAD= (DX-AX)2+(DY-AY)2 A 0.00 0.00 B 128.33 67.54 ΔLAD=397.33 [ft] C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y to calculate the slope. [pause] The change in elevation between Points A and D, ---- ΔLAD= (DX-AX)2+(DY-AY)2 A 0.00 0.00 B 128.33 67.54 ΔLAD=397.33 [ft] C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev A 1.95 change in dd elevation B 9.50 4.84 ΔzAD dd S= C 4.63 3.72 slope ΔLAD dd D 5.85 horizontal length X Y Y can be calculated using the level survey data, --- ΔLAD= (DX-AX)2+(DY-AY)2 A 0.00 0.00 B 128.33 67.54 ΔLAD=397.33 [ft] C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 dd C 4.63 3.72 ΔzAD dd SAD= D 5.85 ΔLAD X Y ΔLAD=397.33 [ft] provided in the problem statement. Where the change in elevation ---- A 0.00 0.00 B 128.33 67.54 C 209.67 118.45 A X D 312.74 245.08

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 dd C 4.63 3.72 ΔzAD dd SAD= D 5.85 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] from Point A to Point D equals, the elevation at Point D A X

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 dd C 4.63 3.72 ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] minus the elevation at Point A, which is given as 362.01 feet.. We can find the elevation at Point D, by adding the elevation at Point C, --- A X

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 dd C 4.63 3.72 ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] to the backsight reading to Point C, minus, the foresight reading to Point D. The survey data provides the --- ElevD=ElevC+BSC-FSD

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 dd C 4.63 3.72 ElevC ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] backsight to Point C and foresight to Point D, but not the elevation of Point C. We’ll write a similar equation for --- ElevD=ElevC+BSC-FSD ?

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 ElevB dd C 4.63 3.72 ElevC ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] the elevation at Point C, and a third equation for the elevation --- ElevD=ElevC+BSC-FSD ElevC=ElevB+BSB-FSC ?

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 ElevB dd C 4.63 3.72 ElevC ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] at Point B. [pause] 362.01 feet + 1.95 feet - 4.84 feet = the elevation at Point B, --- ElevD=ElevC+BSC-FSD ElevC=ElevB+BSB-FSC ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 ElevC ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] which equals 359.12 feet. When plugging in the variables for the elevation ---- ElevD=ElevC+BSC-FSD ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 ElevC ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] at Point C, the elevation at Point C equals --- ElevD=ElevC+BSC-FSD ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 ElevD ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] 364.90 feet. [pause] 364.90 feet + 4.63 feet minus ----- ElevD=ElevC+BSC-FSD 364.90[ft] ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] 5.85 feet, equals, 363.68 feet. Next we can find the change in elevation by subtracting, --- ElevD=ElevC+BSC-FSD 364.90[ft] ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] the elevation at Point A from the elevation at Point D, which equals, --- ElevD=ElevC+BSC-FSD 364.90[ft] ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] 1.67 feet. [pause] To find the average slope from Point A to Point D, --- ΔzAD=1.67 [ft] ElevD=ElevC+BSC-FSD 364.90[ft] ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] we’ll divide 1.67 feet into 397.33 feet, and the average slope of line segment A D, equals, ---- ΔzAD=1.67 [ft] ElevD=ElevC+BSC-FSD 364.90[ft] ElevC=ElevB+BSB-FSC 359.12 [ft] ElevB=ElevA+BSA-FSB

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] 0.0042, which, as a percentage, equals, --- ΔzAD=1.67 [ft] ElevD=ElevC+BSC-F SAD=0.0042 364.90[ft] ElevC=ElevB+B 359.12 [ft] ElevB=E

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD ΔzAD=ElevD-ElevA ΔLAD=397.33 [ft] 0.42 percent. [pause] ΔzAD=1.67 [ft] ElevD=ElevC+BSC-F SAD=0.0042 364.90[ft] ElevC=ElevB+B SAD=0.42% 359.12 [ft] ElevB=E

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD 0.2% 0.4% 0.6% 0.8% ΔLAD=397.33 [ft] When reviewing the possible solutions, --- ΔzAD=1.67 [ft] SAD=0.0042 SAD=0.42%

Find: Average Slope AD [%] [ft] BS HI FS Elev change in A 1.95 362.01 dd elevation B 9.50 4.84 359.12 dd C 4.63 3.72 364.90 ΔzAD dd SAD= D 5.85 363.38 ΔLAD 0.2% 0.4% 0.6% 0.8% ΔLAD=397.33 [ft] the answer is B. ΔzAD=1.67 [ft] SAD=0.0042 AnswerB SAD=0.42%

d

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Find the elevation at Point F, in feet. [pause] In this problem, --- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Find the elevation at Point F, in feet. [pause] In this problem, --- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Find the elevation at Point F, in feet. [pause] In this problem, --- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Points A through F are positioned along an open traverse. Survey data is provided, ---- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd which includes backsight readings, ---- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd foresight readings, and, the elevation ---- F 5.37 E D F C B A

Find: ElevF [ft] 849.8 869.8 874.4 879.8 E F D C B A BS HI FS Elev A 5.15 862.09 dd B 4.44 2.64 dd C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd at Point A. [pause] All length values in the data table, ---- F 5.37 E ElevA D F C B A

Find: ElevF [ft] E F D C B A BS HI FS Elev A 5.15 862.09 all values dd 4.44 2.64 in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd are in units of feet. [pause] The problem asks to find the elevation of --- F 5.37 E D F C B A

Find: ElevF [ft] ? E F D C B A BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Point F. In this analysis, we’ll begin with Point A, --- F 5.37 ? E D F C B A

Find: ElevF [ft] ? E F D C B A BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd because we were given it’s elevation value. From here, we can relate the elevation between F 5.37 ? E D F C B A

Find: ElevF [ft] ? ? E F D C B A BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd 2 consecutive points, A and B, using the backsight and --- F 5.37 ? E D F C B A

Find: ElevF [ft] ? ? E F D C B A BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd foresight measurements. The column labeled H i, --- F 5.37 ? E D F C B A

Find: ElevF [ft] ? ? E F D C B A BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd represents the height of the instrument, or more precisely, the elevation of the ---- F 5.37 ? E D F C B A

Find: ElevF [ft] ? ? E F D C B A vertical datum BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd line of sight, based on a vertical datum, or benchmark. Before we can find the elevation --- F 5.37 ? E D F C B A vertical HI datum

Find: ElevF [ft] ? ? E F D C B A vertical datum BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd at Point F, we first have to find the elevation at Point B, ---- F 5.37 ? E D F C B A vertical HI datum

Find: ElevF [ft] ? ? E F D C B A vertical datum BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd and then we’ll work our way down to --- F 5.37 ? E D F C B A vertical HI datum

Find: ElevF [ft] ? ? E F D C B A vertical datum BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd to Point F, one point at a time. [pause] If we take a closer look at ---- F 5.37 ? E D F C B A vertical HI datum

Find: ElevF [ft] ? ? E F D C B A vertical datum BS HI FS Elev A 5.15 862.09 all values dd B 4.44 2.64 ? in units dd of feet C 8.41 1.95 dd D 7.65 2.41 rod level dd E 1.06 2.05 dd Points A and B, we can better understand the leveling procedure. F 5.37 ? E D F C B A vertical HI datum

Find: ElevF [ft] B A BS HI FS Elev all values in units A 5.15 862.09 dd HIAB of feet B 4.44 2.64 ElevB dd From the problem statement we know the elevation at Point A equals, --- B A

Find: ElevF [ft] B A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 HIAB dd of feet B 4.44 2.64 ElevB dd 862.09 feet. If we place the measuring rod at Point Point A, --- B A ElevA datum

Find: ElevF [ft] B A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 HIAB dd of feet B 4.44 2.64 ElevB dd measuring rod and take a level reading from the instrument to the rod, --- B A ElevA datum

Find: ElevF [ft] B A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 HIAB dd of feet B 4.44 2.64 ElevB dd measuring rod the backsight distance for Point A is the vertical length --- B A ElevA datum

Find: ElevF [ft] B A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 HIAB dd of feet B 4.44 2.64 ElevB dd measuring rod from the ground, up to the sighted location on the rod. As mentioned before, the height of the instrument A B is --- BSA B A ElevA datum

Find: ElevF [ft] B HIAB A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 HIAB dd of feet B 4.44 2.64 ElevB dd measuring rod the vertical distance between the datum, and the elevation, of the line of sight. BSA B HIAB A ElevA datum

Find: ElevF [ft] HIAB = ElevA +BSA B HIAB A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 dd HIAB of feet B 4.44 2.64 ElevB dd measuring HIAB = ElevA +BSA rod Now we can compute the Height of Instrument, A B, as --- BSA B HIAB A ElevA datum

Find: ElevF [ft] HIAB = ElevA +BSA B HIAB A ElevA datum BS HI FS Elev all values in units A 5.15 862.09 dd HIAB of feet B 4.44 2.64 ElevB dd measuring HIAB = ElevA +BSA rod the Elevation at Point A, plus, the backsight reading at Point A, which equals, ---- BSA B HIAB A ElevA datum

Find: ElevF [ft] HIAB = ElevA +BSA HIAB = 867.24 [ft] B HIAB A ElevA FS Elev all values in units A 5.15 862.09 dd HIAB of feet B 4.44 2.64 ElevB dd measuring HIAB = ElevA +BSA rod HIAB = 867.24 [ft] 867.24 feet. [pause] Next, the rod man sets the rod vertically at Point B, --- BSA B HIAB A ElevA datum

Find: ElevF [ft] B HIAB A datum BS HI FS Elev all values in units A 5.15 862.09 867.24 dd of feet B 4.44 2.64 ElevB dd measuring rod and the instrument man takes another level shot at the rod. This reading on the rod represents ---- B HIAB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 867.24 dd of feet B 4.44 2.64 ElevB dd measuring rod the foresight elevation, which in this case is for Point B, and for this example equals 2.64 feet. And the elevation of Point B, equals, --- FSB B HIAB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 dd 867.24 of feet B 4.44 2.64 ElevB dd measuring rod the vertical distance from the datum, and Point B, which equals, --- FSB B HIAB ElevB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 dd 867.24 of feet B 4.44 2.64 ElevB dd measuring ElevB = HIAB - FSB rod the height of the instrument, minus the foresight reading. After plugging in --- FSB B HIAB ElevB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 dd 867.24 of feet B 4.44 2.64 ElevB dd measuring ElevB = HIAB - FSB rod the known values, the elevation at Point B equals, --- FSB B HIAB ElevB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 dd 867.24 of feet B 4.44 2.64 ElevB dd measuring ElevB = HIAB - FSB rod ElevB = 864.60 [ft] 864.60 feet. [pause] Looking over our equations, the elevation at B equals the ---- FSB B HIAB ElevB A datum

Find: ElevF [ft] FSB B HIAB A datum BS HI FS Elev all values in units 5.15 862.09 dd 867.24 of feet B 4.44 2.64 864.60 dd measuring ElevB = HIAB - FSB rod height of the instrument minus the foresight reading, but previously we already solved for --- FSB B HIAB ElevB A datum

Find: ElevF [ft] HIAB = ElevA +BSA FSB B HIAB A datum BS HI FS Elev all values in units A 5.15 862.09 dd 867.24 of feet B 4.44 2.64 864.60 dd measuring ElevB = HIAB - FSB rod HIAB = ElevA +BSA the height of the instrument as the elevation at Point A plus the backsite reading to Point A. FSB B HIAB ElevB A datum

Find: ElevF [ft] HIAB = ElevA +BSA FSB B HIAB A datum BS HI FS Elev all values in units A 5.15 862.09 dd 867.24 of feet B 4.44 2.64 864.60 dd measuring ElevB = HIAB - FSB rod HIAB = ElevA +BSA Substituting in the Height of the Instrument, we can equate the elevation of Point B to ---- FSB B HIAB ElevB A datum

Find: ElevF [ft] HIAB = ElevA +BSA B A datum BS HI FS Elev all values in units A 5.15 862.09 dd 867.24 of feet B 4.44 2.64 864.60 dd measuring ElevB = HIAB - FSB rod HIAB = ElevA +BSA ElevB = ElevA +BSA- FSB the elevation at Point A, plus the backsight to Point A, minus the foresight to Point B. [pause] We can use this equation --- B ElevB A datum

Find: ElevF [ft] E F D C B A BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC dd C 8.41 1.95 ElevC ElevC = ElevB +BSB- FSC to find the elevation at Point C, by knowing the elevation at Point B, --- E D F C B A

Find: ElevF [ft] E F D C B A BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC dd C 8.41 1.95 ElevC ElevC = ElevB +BSB- FSC and the backsight to Point B, and foresight, to Point C. The elevation at Point C equals, --- E D F C B A

Find: ElevF [ft] E F D C B A BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 dd HIBC C 8.41 1.95 867.09 ElevC = ElevB +BSB- FSC 867.09 feet. We’ll continue to use this equation to solve for the elevation at Points ---- ElevC = 867.09 [ft] E D F C B A

Find: ElevF [ft] E F D C B A BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 ElevD HIDE dd E 1.06 2.05 ElevE dd HIEF D, E and F. The elevation at Point D equals, the elevation at Point C, --- F 5.37 ElevF E D F C B A

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 ElevD HIDE dd E 1.06 2.05 ElevE HIEF dd plus backsight of C, minus the foresight at D, which equals, --- F 5.37 ElevF E D F ElevD = ElevC +BSC- FSD

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 HIDE dd E 1.06 2.05 ElevE HIEF dd 873.09 feet. [pause] The elevation for Point E --- F 5.37 ElevF E D F ElevD = ElevC +BSC- FSD

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 HIDE dd E 1.06 2.05 ElevE dd HIEF is calculated the same way and equals --- F 5.37 ElevF E D F ElevD = ElevC +BSC- FSD ElevE = ElevD +BSD- FSE

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 HIDE dd E 1.06 2.05 878.69 dd HIEF 878.69 feet. [pause] And finally, --- F 5.37 ElevF E D F ElevD = ElevC +BSC- FSD ElevE = ElevD +BSD- FSE

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 dd HIDE E 1.06 2.05 878.69 HIEF dd the elevation at Point F equals, --- F 5.37 ElevF E ElevD = ElevC +BSC- FSD D F ElevE = ElevD +BSD- FSE ElevF = ElevE +BSE- FSF

Find: ElevF [ft] E F D BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 dd HIDE E 1.06 2.05 878.69 HIEF dd 874.38 feet. [pause] F 5.37 874.38 E ElevD = ElevC +BSC- FSD D F ElevE = ElevD +BSD- FSE ElevF = ElevE +BSE- FSF

Find: ElevF [ft] 849.8 869.8 874.4 879.8 BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC 849.8 869.8 874.4 879.8 C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 HIDE dd E 1.06 2.05 878.69 HIEF dd When viewing the possible solutions, --- F 5.37 874.38 ElevD = ElevC +BSC- FSD ElevF = 874.38 [ft] ElevE = ElevD +BSD- FSE ElevF = ElevE +BSE- FSF

Find: ElevF [ft] 849.8 869.8 874.4 879.8 BS HI FS Elev all values in units A 5.15 862.09 867.24 of feet B 4.44 2.64 864.60 HIBC 849.8 869.8 874.4 879.8 C 8.41 1.95 867.09 HICD D 7.65 2.41 873.09 HIDE dd E 1.06 2.05 878.69 dd HIEF the answer is C. F 5.37 874.38 ElevD = ElevC +BSC- FSD ElevF = 874.38 [ft] ElevE = ElevD +BSD- FSE ElevF = ElevE +BSE- FSF AnswerC

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