Chemistry 12.2
Today: We are going to go through section 12.2 together and I will walk you through it. If you pay attention and be quiet and fill out your notes while I am teaching, I will give you the chance to re-take the practice quiz on paper tomorrow in class. If you do not, I will take your quiz score as is.
Writing and Using Mole Ratios 12.2 Writing and Using Mole Ratios Writing and Using Mole Ratios How are mole ratios used in chemical calculations?
Writing and Using Mole Ratios 12.2 Writing and Using Mole Ratios In chemical calculations, mole ratios are used to convert between moles of reactant and moles of product, between moles of reactants, or between moles of products.
Writing and Using Mole Ratios 12.2 Writing and Using Mole Ratios Mole-Mole Calculations A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation interpreted in terms of moles.
Writing and Using Mole Ratios 12.2 Writing and Using Mole Ratios To determine the number of moles in a sample of a compound, first measure the mass of the sample. Then use the molar mass to calculate the number of moles in that mass. To determine the number of moles in a sample of a compound, first measure the mass of the sample. Then use the molar mass to calculate the number of moles in that mass.
12.2 Manufacturing plants produce ammonia by combining nitrogen with hydrogen. Ammonia is used in cleaning products, fertilizers, and in the manufacture of other chemicals.
for Sample Problem 12.2 Problem Solving 12.12 Solve Problem 12 with the help of an interactive guided tutorial.
Writing and Using Mole Ratios 12.2 Writing and Using Mole Ratios Mass-Mass Calculations
12.3 In this Hubble Space Telescope image, clouds of condensed ammonia are visible covering the surface of Saturn.
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for Sample Problem 12.3 ` Problem Solving 12.13 Solve Problem 13 with the help of an interactive guided tutorial.
Other Stoichiometric Calculations 12.2 Other Stoichiometric Calculations Other Stoichiometric Calculations What is the general procedure for solving a stoichiometric problem?
Other Stoichiometric Calculations 12.2 Other Stoichiometric Calculations In a typical stoichiometric problem, the given quantity is first converted to moles. Then the mole ratio from the balanced equation is used to calculate the number of moles of the wanted substance. Finally, the moles are converted to any other unit of measurement related to the unit mole, as the problem requires.
Other Stoichiometric Calculations Simulation 13 Strengthen your analytical skills by solving stoichiometric problems.
12.4 The electrolysis of water causes it to decompose into hydrogen and oxygen.
Example:
4Al + 3O2 2Al2O3 How many grams of aluminum burned if 200.0 grams of aluminum oxide formed?
for Sample Problem 12.4 Problem Solving 12.15 Solve Problem 15 with the help of an interactive guided tutorial.
12.5
for Sample Problem 12.5 Problem Solving 12.18 Solve Problem 18 with the help of an interactive guided tutorial.
Next: You have 6 practice problems to do and turn in. I will come around and give participation points to those who are doing their own work.
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for Sample Problem 12.5 Problem-Solving 12.19 Solve Problem 19 with the help of an interactive guided tutorial.
12.2 Section Quiz. 12.2.
12.2 Section Quiz. C3H8 + 5O2 3CO2 + 4H2O 1. How many moles of water are produced when 2.5 mol of O2 react according to the following equation? C3H8 + 5O2 3CO2 + 4H2O 2.0 2.5 3.0 4.0
12.2 Section Quiz 2. Nitrogen gas reacts with hydrogen gas to produce ammonia gas. N2(g) + 3H2(g) 2NH3(g) What volume of H2 is required to react with 3.00 L of N2, and what volume of NH3 is produced at 200°C? volume of H2 = 9.00 L, volume of NH3 = 6.00 L volume of H2 = 3.00 L, volume of NH3 = 3.00 L volume of H2 = 3.00 L, volume of NH3 = 6.00 L volume of H2 = 1.00 L, volume of NH3 = 1.50 L
12.2 Section Quiz 3. Automotive airbags inflate when sodium azide, NaN3, rapidly decomposes to its component elements via this reaction: 2NaN3 2Na + 3N2. How many grams of sodium azide are required to form 5.00 g of nitrogen gas? 11.61 g 17.41 g 7.74 g 1.36 g
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