By Carl Lyman © September 2001

Slides:



Advertisements
Similar presentations
STOICHIOMETRY Study of the amount of substances consumed and produced in a chemical reaction.
Advertisements

CH 3: Stoichiometry Moles.
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
Stoichiometry.
Chapter 3.  Reactants are left of the arrow  Products are right of the arrow  The symbol  is placed above the arrow to indicate that the rxn is being.
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
AP Chemistry West Valley High School Mr. Mata.
Percentage Composition
Stoichiometry Calculations with Chemical Formulas and Equations Chapter 3 BLB 12 th.
Chapter 3 Percent Compositions and Empirical Formulas
Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction. Molecules, formula units, moles and volumes are not always.
Conservation of Mass (again) I think it must be important? I think it must be important? Lavoisier- observed that the total mass of a substance present.
Chapter 3. Atomic Mass  amu = Average Atomic Mass Unit  Based on 12 C as the standard.  12 C = exactly 12 amu  The average atomic mass (weight) of.
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
Stoichiometry Calculations with Chemical Formulas and Equations.
Molar relationships in chemical reactions
Choose Your Category The MoleAverage Atomic Mass and Molar Mass FormulasPercentage Composition Limiting Reactants Percentage Yield and Error Vocab 100.
1 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Stoichiometry. Chemical Equations Short hand way to represent chemical reactions H 2 + Cl 2 → HCl Symbols + = reacts with → = produces, yields Δ = adding.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
STAAR Ladder to Success Rung 8. How do chemists define a mole? Example #1: A sample consists of 6.85 x atoms of carbon. How many moles does the.
Stoichiometry! The heart of chemistry. The Mole The mole is the SI unit chemists use to represent an amount of substance. 1 mole of any substance = 6.02.
Stoichiometry Law of Conservation of Mass “We may lay it down as an incontestable axiom that, in all the operations of art and nature, nothing is created;
CHAPTER Chemical Reactions. Writing Chemical Equations A chemical reaction occurs when matter changes from one composition to another.
Mass Relationships in Chemical Reactions
Stoichiometry: Calculations with Chemical Formulas and Equations
Equations & Reactions.
Chemical Equations & Reactions(Rxn’s)
Mass Relationships in Chemical Reactions
Chapter 5 Lecture Outline
Mass Relationships in Chemical Reactions
University of Louisiana at Lafayette
5. 1 Introduction to Chemical Reactions A
Stoichiometry.
A.P. Ch. 3 Review Work Stoichiometry.
Stoichiometry Chapter 3
Mass Relationships in Chemical Reactions
Unit 4: Formula Stoichiometry
Atomic Mass Unit: amu (atomic mass unit) amu is defined as a mass exactly equal to on-twelfth the mass of Carbon-12 atom amu = 1/12 of carbon-12 Hydrogen.
Chemical Quantities & Stoichiometry
Mass Relationships in Chemical Reactions
Chapter 5 Chemical Reactions
Look over objectives and try those types of
St. Charles Community College
Section 9.3—Analysis of a Chemical Formula
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
MIDTERM REVIEW IN FOUR PARTS.
Mass Relationships in Chemical Reactions
balanced chemical reaction
TURN IN OLD WARMUP SHEET!
Stoichiometry Review.
2.4 تعيين الصيغة البسيطة تجريبياً Percent Composition Of Compounds
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Answers (2) C (13) C (3) B (14) D (4) C (15) D (5) B (16) D (6) A (17) A (7) C (18) D (8) A (19) B (9) D (20) D (10) A (21) A (11) B (22) B (12) C.
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mole and Stoichiometry
Stoichiometry.
Unit 8: Reactions And Stoichiometry
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Presentation transcript:

By Carl Lyman © September 2001 Jeopardy Template By Carl Lyman © September 2001

Midterm Jeopardy 2 100 200 300 400 500 MOF Reactions Stoichiometry Thermo 100 200 300 400 500

Credits That’s all folks. Exit

MOF $100 What is the molar mass of (NH4)2CO3? A.) 144 g/mol B.) 138 g/mol C.) 96 g/mol D.) 78 g/mol

MOF $100 C 96 g/mol Subscript must be multiplied in for parentheses N 2 x 14 = 28 H 8 x 1 = 8 C 1 x 12 = 12 O 3 x 16 = 48

MOF $200 What is the percent composition of chromium in BaCrO4? D.) 25.2 %

MOF $200 C 20.5% Ba 1 x 137 = 137 Part/Whole x 100 Cr 1 x 52 = 52 O 4 x 16 = 64 52 x 100 = 253 g/mol 253

MOF $300 What is the mass in grams of 5.90 moles of C8H18? A.) 0.0512 g B.) 19.4 g C.) 389 g D.) 673 g

MOF $300 D 673 g 5.90 mol x 114 g = 1 mol C 8 x 12 = 96 H 18 x 1 = 18

How many moles of silver atoms are in 1.8 x 1020 atoms of silver? MOF $400 How many moles of silver atoms are in 1.8 x 1020 atoms of silver? A.) 3.0 x 10-4 B.) 3.3 x 10-3 C.) 3.0 x 102 D.) 1.1 x 1044

MOF $400 A 3.0 x 10-4 mol 1.8 x 1020 atoms x 1 mol = 6.02 x 1023 atoms Don’t forget to use parentheses when plugging scientific notation into your calculator

MOF $500 Which of the following is NOT an empirical formula? A.) Sb2S3 B.) C2H8O C.) C2N2H8 D.) BeCr2O7

MOF $500 C C2N2H8 Empirical formulas are in lowest whole number ratio of atoms. C2N2H8 can be reduced to CNH4

CaSO4 + AlCl3  Al2(SO4)3 + CaCl2 Reactions $100 CaSO4 + AlCl3  Al2(SO4)3 + CaCl2 What is the coefficient of Al2(SO4)3 when the equation is completely balanced using the smallest whole-number coefficients? A.) 1 B.) 2 C.) 3 D.) 4

Reactions $100 A 1 3CaSO4 + 2AlCl3  Al2(SO4)3 + 3CaCl2 Balanced equations have the same number of atoms of each element in both the reactants and products. Only coefficients can be altered.

is an example of which type of reaction? Reactions $200 The equation 2C3H7 + 9O2  6CO2 + 8H2O is an example of which type of reaction? A.) single-replacement reaction B.) double-replacement reaction C.) decomposition reaction D.) combustion reaction

Reactions $200 D combustion reaction A hydrocarbon reacts with oxygen to produce carbon dioxide and water

is an example of which type of reaction? Reactions $300 The equation Mg(s) + 2HCl(aq)  MgCl2(aq) + H2(g) is an example of which type of reaction? A.) combination reaction B.) single-replacement reaction C.) decomposition reaction D.) double-replacement reaction

Reactions $300 B single replacement reaction The free element Mg replaces hydrogen in the compound HCl.

Reactions $400 A double-replacement reaction takes place when aqueous Na2CO3 reacts with aqueous Sn(NO3)2. You would expect one of the products of this reaction to be ________. A.) NaNO3 B.) NaSn C.) Sn(CO3)2 D.) CNO3

Reactions $400 A NaNO3 Na2CO3 + Sn(NO3)2  SnCO3 + 2NaNO3 Na and Sn trade places

Reactions $500 Predict the products: Mg + CuCl2  A.) No reaction B.) MgCu + Cl2 C.) Cu + MgCl2 D.) MgCuCl2

Reactions $500 C Cu + MgCl2 This is a single replacement reaction. It will occur because the free element Mg is higher in activity than the element it is replacing in the compound. Mg and Cu will be the ones trading places because they are both metals and have positive oxidation numbers.

Stoichiometry $100 6 CO2 + 6 H2O  C6H12O6 + 6 O2 What is the total number of moles of water needed to make 2.5 moles of C6H12O6? A.) 2.5 B.) 6.0 C.) 12 D.) 15

Stoichiometry $100 D 15 mol 2.5 = X 1 6 ← From original equation

2Pb(NO3)2(s)  2PbO(s) + 4NO2(g) + O2(g) Stoichiometry $200 2Pb(NO3)2(s)  2PbO(s) + 4NO2(g) + O2(g) How many grams of oxygen are produced when 11.5 grams of NO2 is formed? A.) 1.00 g B.) 2.00 g C.) 2.88 g D.) 32.0 g

Stoichiometry $200 B 2.00 g 11.5g x 1mol 0.25 = X 0.0625mol x 32g = 46g 4 1 1mol

Stoichiometry $300 2 C4H10 + 13 O2  8 CO2 + 10 H2O What is the total number of moles of O2 that must react completely with 5.00 moles of C4H10? A.) 10.0 B.) 20.0 C.) 26.5 D.) 32.5

Stoichiometry $300 D 32.5 mol 5.00 = X 2 13

Stoichiometry $400 4Fe(s) + 3O2(g) 2Fe2O3(s) How many grams of Fe2O3 are formed when 16.7 grams of Fe reacts completely with oxygen? A.) 12.0 g B.) 23.9 g C.) 47.8 g D.) 95.6 g

Stoichiometry $400 B 23.9 g 16.7g x 1mol 0.298 = X 0.149mol x 160g = 56g 4 2 1mol

Stoichiometry $500 Ca + F2  CaF2 What is the limiting reagent and what quantity of CaF2 results from the reaction of 3.00 g of calcium and 2.00 g of fluorine? A.) Ca, 4.78 B.) F2, 4.78 C.) Ca, 4.11 D.) F2, 4.11 E.) Ca, 3.22

Stoichiometry $500 D F2, 4.11 Determine how many grams of product can be made Ca 3g x 1mol 0.075 = X 0.075mol x 78g = 5.85g 40g 1 1 1mol F2 2g x 1mol 0.053 = X 0.053mol x 78g = 4.11g 38g 1 1 1mol F2 is the limiting reagent because it can make the least amount of product. The theoretical yield is the smaller amount of product made and is based on the amount made by the limiting reagent.

Which Kelvin temperature is equal to -73°C? Thermo $100 Which Kelvin temperature is equal to -73°C? A.) 100 K B.) 173 K C.) 200 K D.) 346 K

Thermo $100 C 200 K K = °C + 273 = -23 + 273

Thermo $200 The average kinetic energy of water molecules is greatest in which of these samples? A.) 10 g of water at 35°C B.) 10 g of water at 55°C C.) 100 g of water at 25°C D.) 100 g of water at 45°C

Thermo $200 B 10g of water at 55°C Temperature measures kinetic energy, the higher the temperature the higher the kinetic energy

Thermo $300 The specific heat of silver is 0.24 J/gºC. How much heat is needed to warm 4.37 g of silver from 25.0ºC to 27.5ºC? A.) 2.62 J B.) 0.14 J C.) 45.5 J D.) 0.022 J

Thermo $300 A 2.62 J q = mcΔT q = (4.37 g)(0.24 J/g°C)(27.5°C – 25.0°C)

Calculate the energy required to produce 7 moles of Cl2O7 Thermo $400 2Cl2 + 7 O2 + 543.4 kJ  2 Cl2O7 Calculate the energy required to produce 7 moles of Cl2O7 A.) 29.26 kJ B.) 271.7 kJ C.) 543.4 kJ D.) 1901.9 kJ

Thermo $400 D 1901.9 kJ 7 = X 2 543.4 ← From original equation

Thermo $500 Given the potential energy diagram of a chemical reaction: . . . (see image) Which arrow represents the potential energy of the reactants? A.) B.) C.) D.)

Category 4 $500 B A = activation energy C = P.E. of activated complex D = P.E. of products