Temperature & Gas Laws Chapter 16.

Slides:



Advertisements
Similar presentations
Gas Laws. Gases No definite shape, no definite volume.
Advertisements

GAS LAWS. CHARLES'S LAW Jacques Charles Invented hydrogen balloon Collected data on the relationship between the temperature and volume of gases.
V. Combined and Ideal Gas Law
Chapter 14- Gas Laws.
Elementary Gas Laws and the Ideal Gas Law
Gases.
Gas Laws AP Physics B.
Gases Dr. Ron Rusay Summer 2004 © Copyright 2004 R.J. Rusay.
Ch. 10 & 11 - Gases II. The Gas Laws (p ) P V T.
13.7 NOTES The Ideal Gas Laws
Boyle’s Law y = A / x Pressure = A Volume PV = constant P1V1 = P2V2
Gas Laws Name Period Due Date.
Gas Law Group Activity (Print pages 2 and 3 back-to-back as worksheet) (Print the other sheets and place around the room) Group mathematicians with non-mathematicians.
Ch and 14.2 Gas Laws.
Gas Laws.
Part 1.
Gas Laws Chapter 5.
Chapter 6 Gases 6.6 The Combined Gas Law.
Ch. 10 & 11 - Gases II. The Gas Laws (p ) P V T.
Boyle’s Law and Charles’ Law
The Combined Gas Law When measured at STP, a quantity of gas has a volume of 500 dm3. What volume will it occupy at 0 oC and 93.3 kPa? (101.3 kPa) x (500.
Ch. 10 & 11 - Gases II. The Gas Laws (p ) P V T C. Johannesson.
Dispatch Draw a picture of a gas in a container
Particles subject to Pressure, Temperature, Moles and Volume
Mathematical Relationships between P, V, and T
Gases.
Gas Laws Foldable.
The Gas Laws (p ) read the text first
Gas Laws.
Gas Laws.
Gas Laws.
Drill - Without using your notes…
10.3 – NOTES Gas Laws.
Warm Up #2 For the following problems, label P, V and T as well as the law you are using. You have a container with 2.4 atm of pressure at 340 K. How.
The Gas Laws Define pressure and gas pressure.
The Combined Gas Law When measured at STP, a quantity of gas has a volume of 500 dm3. What volume will it occupy at 0 oC and 93.3 kPa? (101.3 kPa) x (500.
Boyle’s Law: Pressure-Volume Relationship
Chapter 13 - Gases II. The Gas Laws P V T.
Gas Laws.
Chemistry Chapter 11 - Gases
Gas Variable Relationships
LECTURE 6.7 –IDEAL LAW.
By; Santiago Romanos and Sarah Swiderski
Gases 5.The Gas Laws P V T.
By; Santiago Romanos and Sarah Swiderski
Gas Laws AP Physics B.
The Combined Gas Law and the Ideal Gas Law
No, it’s not related to R2D2
Gas Laws AP Physics B.
AP Chemistry D. Paskowski
TEKS 9A & 9C Gas Laws.
Lesson 5.3 – Gas Laws Chemistry 1 Honors Dr. J. Venables
Boyle’s Law At a constant temperature pressure and volume are inversely related As one goes up the other goes down P1 x V1= P2 x V2
Bell Work: Gasses List 10 things you know about gases. . . anything you can think of related to a gas.
PV = nRT Pressure x Volume = Moles x gas constant x Temp.
Ch. 10 & 11 - Gases II. The Gas Laws (p ) P V T.
Ch. 10 & 11 - Gases II. The Gas Laws (p ) P V T C. Johannesson.
Explaining behavior of specific fluids.
Gas Laws.
Unit 6: Gases and Atmospheric Chemistry
Gas Laws I.
The Combined Gas Law and Avogadro’s Principle
Gasses laws.
Relationships between pressure, volume, and temperature
Gas Laws… Continued.
Boyle’s Gas Law ** At constant temperature and
The Gas Laws.
Notes Ch Gas Laws Chemistry.
Gas Laws AP Physics B.
Combined Gas Law At times 1 and 2 so
Presentation transcript:

Temperature & Gas Laws Chapter 16

Temperature Measured in Celsius and Kelvin (Kelvin = Celsius + 273) Absolute Zero: the temperature at which the volume of an ideal gas is zero (T = 0 K) Directly related to the average KE of particles in a substance

Gas Laws Boyle’s Law: the volume of a gas is inversely related to its pressure Charles’ Law: the volume of a gas is directly related to its absolute temperature Gay-Lussac’s Law: the pressure of a gas is directly related to its absolute temperature

Ideal Gas Law Incorporates Boyles, Charles and Gay-Lussac’s Laws and includes the effect of moles of a substance: PV = nRT Where R = ideal gas constant = 8314 J/kmol K

Ideal Gas Law Units Pressure (P) = Pascals Volume (V) = m3 Temperature (T) = Kelvin Number of moles (n) = kmol

Combined Gas Law Gas Laws can be expressed in an equation that relates initial conditions to final conditions: P1V1 = P2V2 T2 T2

Standard Conditions Standard Temperature = 0oC (273 K) Standard Pressure = 1 atm = 1.013 x 105 Pa

Practice Problems . . . . .