4.3 Netwon’s Second and Third Laws

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4.3 Netwon’s Second and Third Laws

Yesterdays homework Define Equilibrium using text on page 127 Equilibrium:the state in which the net force on an object is zero. (therefore it is at rest or moving with a constant velocity) (no acceleration if the net force is zero!!) Complete questions 1-5 on page 127 1. zero … constant velocity 2. -3674N 3. 4502N at1.655 degrees 4. 4502N the same magnitude force but in opposite direction 5. no… there must be none, or two or more forces required for equilibrium

Equilibrium Chapter 4 Section 2 Newton’s First Law Equilibrium is the state in which the net force on an object is zero. Objects that are either at rest or moving with constant velocity are said to be in equilibrium. Newton’s first law describes objects in equilibrium. Tip: To determine whether a body is in equilibrium, find the net force. If the net force is zero, the body is in equilibrium. If there is a net force, a second force equal and opposite to this net force will put the body in equilibrium.

4.3 Objectives Chapter 4 Section 3 Newton’s Second and Third Laws Describe an object’s acceleration in terms of its mass and the net force acting on it. Predict the direction and magnitude of the acceleration caused by a known net force. Identify action-reaction pairs.

net force = mass  acceleration Section 3 Newton’s Second and Third Laws Chapter 4 Newton’s Second Law The acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the object’s mass. F = ma net force = mass  acceleration F represents the vector sum of all external forces acting on the object, or the net force.

Calculating Acceleration Laura slides a 2.2Kg book towards Roberto. If the net force acting on the book is 1.6N to the right, what is the book’s acceleration? ∑F=ma 1.6N=(2.2 kg)a a= 0.73m/s2 to the right

Example problems: Space shuttle astronauts experience accelertaions of about 35m/s2 during takeoff. What force would a 75Kg astronaut experience? 2600N An 8.5Kg bowling ball initially at rest is dropped from the top of an 11m building. The ball hits the ground 1.5s later. Find the net force on the falling ball. 83N

Newton’s Third Law Chapter 4 Section 3 Newton’s Second and Third Laws Chapter 4 Newton’s Third Law If two objects interact, the magnitude of the force exerted on object 1 by object 2 is equal to the magnitude of the force simultaneously exerted on object 2 by object 1, and these two forces are opposite in direction. In other words, for every action, there is an equal and opposite reaction. Because the forces coexist, either force can be called the action or the reaction.

Action and Reaction Forces Section 3 Newton’s Second and Third Laws Chapter 4 Action and Reaction Forces Action-reaction pairs do not imply that the net force on either object is zero. The action-reaction forces are equal and opposite, but either object may still have a net force on it. Consider driving a nail into wood with a hammer. The force that the nail exerts on the hammer is equal and opposite to the force that the hammer exerts on the nail. But there is a net force acting on the nail, which drives the nail into the wood.

Practice Q 1-5 page 130 Conceptual Challenge q’s 1-2